Programming Forums > Application Development > C++

lilmul123 · May 8th, 2006, 9:47 AM

Here's what I have to do. Can anyone give me an idea on what I should do to do this?

Write a program that counts the number of letters, digits (0-9), and common puncuation symbols entered by the user. Stop inputting when the user presses ENTER. Use a switch statement to categorize the characters into puncuation, digits, and letters. When the program ends, report the number of characters in each category. (If you like, simply assume that, if a character is not a digit or puncuation, it is a letter. Also, just use the most common puncuation symbols (. , ? ! :

.

Infinite Recursion · May 8th, 2006, 9:56 AM

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#include <iostream>
#include <cctype>
 
using namespace std;
 
int main (void)
{
// use isdigit, isalpha, etc.
return 0;
}

Edited to remove the deprecated header. oops...

Ooble · May 8th, 2006, 10:05 AM

* thwaps IR *

Bad, bad!

Use the cctype header instead of ctype.h - the former is a C++ library, and the latter is a C library. The only difference is that in the C++ version, everything is in the std namespace. As IR points out, this library contains a number of functions designed to do exactly what you want to do: isalpha checks whether the character passed to it is a letter, for example.

For punctuation, you'll have to check 'em manually:

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switch (character)
{
    case '.':
    case '?':
    [...]
        // do stuff
        break;
}

rxbandit · May 8th, 2006, 10:18 AM

Yeah we're (lilmul123) wondering how to do this.

lilmul123 · May 8th, 2006, 10:20 AM

well, here's what I have thus far. can you tell me if i'm on the right track or not? i dont exactly know how to use the isdigit or isalpha statements.

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#include "conio.h"
#include "stdio.h"
#include "iostream.h"
#include "ctype.h"

void main()
{
char addup,dothis;
int lettercnt;
clrscr();
cout << "Please enter a bunch of characters, puncuation, or numbers: \n";
cin >> addup;
addup = getch();
{
switch(addup)
{
case 'a'||'e'||'i'||'o'||'u':
	lettercnt++;
	break;
}
{
cout << "You typed this many characters: " << lettercnt;
}
getch();
}
}

Ooble · May 8th, 2006, 10:19 AM

Try reading the responses.

Ooble · May 8th, 2006, 10:23 AM

Looks alright. A switch-case block doesn't work like that though.

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switch (addup)
{
    case 'a':
    case 'e':
    case 'i':
    case 'o':
    case 'u':
        // do stuff
        break;
    
    case '0':
    case '1':
    [...]
    case '9':
        // do other stuff
        break;
    
    default:
        // nothing useful happened - do other stuff
}

DaWei · May 8th, 2006, 10:24 AM

Quote:

For punctuation, you'll have to check 'em manually:

Nah, there are all sorts of things, like 'ispunct', 'isgraph', on and on. See the <locale> header.

Ooble · May 8th, 2006, 10:35 AM

Quote:

Originally Posted by DaWei

Nah, there are all sorts of things, like 'ispunct', 'isgraph', on and on. See the <locale> header.

If he was looking for all punctuation, then that'd work, but he specifies five specific characters he's looking for.

Infinite Recursion · May 8th, 2006, 10:26 AM

An alternative to the switch statement for symbols would be to base if off ASCII ranges or have a string of symbols and utilize the "find_first_of" function.

(Toggle Plain Text)

 
bool isSymbol (char x)
{
	 string SYMBOLS = "X ~`!@#$%^&*()_+-={}[]:\";'<>?,./|";
	 bool result = false;
	 int location = 0;
	 
	 location = SYMBOLS.find_first_of(x);
	 
	 if (location > 0)
		result = true;
	 
	 return result;
}

May 8th, 2006, 9:47 AM	#1
lilmul123 Newbie Join Date: Mar 2006 Posts: 25 Rep Power: 0	How to go about starting this program? Here's what I have to do. Can anyone give me an idea on what I should do to do this? Write a program that counts the number of letters, digits (0-9), and common puncuation symbols entered by the user. Stop inputting when the user presses ENTER. Use a switch statement to categorize the characters into puncuation, digits, and letters. When the program ends, report the number of characters in each category. (If you like, simply assume that, if a character is not a digit or puncuation, it is a letter. Also, just use the most common puncuation symbols (. , ? ! : .

May 8th, 2006, 9:56 AM	#2
Infinite Recursion Programming Guru Join Date: Jul 2004 Location: United States Posts: 3,473 Rep Power: 8	(Toggle Plain Text) #include <iostream> #include <cctype> using namespace std; int main (void) { // use isdigit, isalpha, etc. return 0; } #include <iostream> #include <cctype> using namespace std; int main (void) { // use isdigit, isalpha, etc. return 0; } Edited to remove the deprecated header. oops... __________________ http://jasonpowers.net "There are a thousand hacking at the branches of evil to one who is striking at the root." Last edited by Infinite Recursion; May 8th, 2006 at 10:14 AM.

May 8th, 2006, 10:05 AM	#3
Ooble I eat cake for breakfast. Join Date: Jul 2004 Location: In my box. Posts: 4,434 Rep Power: 9	* thwaps IR * Bad, bad! Use the cctype header instead of ctype.h - the former is a C++ library, and the latter is a C library. The only difference is that in the C++ version, everything is in the std namespace. As IR points out, this library contains a number of functions designed to do exactly what you want to do: isalpha checks whether the character passed to it is a letter, for example. For punctuation, you'll have to check 'em manually: (Toggle Plain Text) switch (character) { case '.': case '?': [...] // do stuff break; } switch (character) { case '.': case '?': [...] // do stuff break; } __________________ Me :: You :: Them

May 8th, 2006, 10:20 AM	#5
lilmul123 Newbie Join Date: Mar 2006 Posts: 25 Rep Power: 0	well, here's what I have thus far. can you tell me if i'm on the right track or not? i dont exactly know how to use the isdigit or isalpha statements. (Toggle Plain Text) #include "conio.h" #include "stdio.h" #include "iostream.h" #include "ctype.h" void main() { char addup,dothis; int lettercnt; clrscr(); cout << "Please enter a bunch of characters, puncuation, or numbers: \n"; cin >> addup; addup = getch(); { switch(addup) { case 'a'\|\|'e'\|\|'i'\|\|'o'\|\|'u': lettercnt++; break; } { cout << "You typed this many characters: " << lettercnt; } getch(); } } #include "conio.h" #include "stdio.h" #include "iostream.h" #include "ctype.h" void main() { char addup,dothis; int lettercnt; clrscr(); cout << "Please enter a bunch of characters, puncuation, or numbers: \n"; cin >> addup; addup = getch(); { switch(addup) { case 'a'\|\|'e'\|\|'i'\|\|'o'\|\|'u': lettercnt++; break; } { cout << "You typed this many characters: " << lettercnt; } getch(); } }

May 8th, 2006, 10:19 AM	#6
Ooble I eat cake for breakfast. Join Date: Jul 2004 Location: In my box. Posts: 4,434 Rep Power: 9	Try reading the responses. __________________ Me :: You :: Them

May 8th, 2006, 10:18 AM	#4
rxbandit Newbie Join Date: May 2006 Posts: 1 Rep Power: 0	Yeah we're (lilmul123) wondering how to do this.

May 8th, 2006, 10:23 AM	#7
Ooble I eat cake for breakfast. Join Date: Jul 2004 Location: In my box. Posts: 4,434 Rep Power: 9	Looks alright. A switch-case block doesn't work like that though. (Toggle Plain Text) switch (addup) { case 'a': case 'e': case 'i': case 'o': case 'u': // do stuff break; case '0': case '1': [...] case '9': // do other stuff break; default: // nothing useful happened - do other stuff } switch (addup) { case 'a': case 'e': case 'i': case 'o': case 'u': // do stuff break; case '0': case '1': [...] case '9': // do other stuff break; default: // nothing useful happened - do other stuff } __________________ Me :: You :: Them

May 8th, 2006, 10:26 AM	#10
Infinite Recursion Programming Guru Join Date: Jul 2004 Location: United States Posts: 3,473 Rep Power: 8	An alternative to the switch statement for symbols would be to base if off ASCII ranges or have a string of symbols and utilize the "find_first_of" function. (Toggle Plain Text) bool isSymbol (char x) { string SYMBOLS = "X ~`!@#$%^&()_+-={}[]:\";'<>?,./\|"; bool result = false; int location = 0; location = SYMBOLS.find_first_of(x); if (location > 0) result = true; return result; } bool isSymbol (char x) { string SYMBOLS = "X ~`!@#$%^&()_+-={}[]:\";'<>?,./\|"; bool result = false; int location = 0; location = SYMBOLS.find_first_of(x); if (location > 0) result = true; return result; } __________________ http://jasonpowers.net "There are a thousand hacking at the branches of evil to one who is striking at the root."

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Programming Forums > Application Development > C++

How to go about starting this program?