Programming Forums > Application Development > Java

Eric the Red · Apr 9th, 2006, 7:30 PM

Can someone please tell me what's wrong with this code? The array has been declared already. I just don't know how to convert this ascii value to char. if i needed to convert the ascii value to a string I would do:

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 int i = 65;
String aChar = new Character((char)i).toString();

// output "a"

However, i need to convert to a char value.

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                        int countascii = 65;                        
                        char aChar = ' ';
                        aChar = new Character ((char) countAscii);
                        letters [0] [0] = aChar;

Kaja Fumei · Apr 9th, 2006, 8:12 PM

Unlike c#, the "char" type in Java is not the same as its "Character" class. The Character class is a wrapper around the char type. All you need to do is explicitly convert int to char:

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aChar = (char) countAscii;

Eric the Red · Apr 9th, 2006, 8:36 PM

thanks!

Apr 9th, 2006, 7:30 PM	#1
Eric the Red Hobbyist Programmer Join Date: Feb 2006 Posts: 214 Rep Power: 0	ascii value to char Can someone please tell me what's wrong with this code? The array has been declared already. I just don't know how to convert this ascii value to char. if i needed to convert the ascii value to a string I would do: (Toggle Plain Text) int i = 65; String aChar = new Character((char)i).toString(); // output "a" int i = 65; String aChar = new Character((char)i).toString(); // output "a" However, i need to convert to a char value. (Toggle Plain Text) int countascii = 65; char aChar = ' '; aChar = new Character ((char) countAscii); letters [0] [0] = aChar; int countascii = 65; char aChar = ' '; aChar = new Character ((char) countAscii); letters [0] [0] = aChar; __________________ Death smiles at us all. All a man can do is smile back.

Apr 9th, 2006, 8:12 PM	#2
Kaja Fumei Hobbyist Programmer Join Date: Oct 2005 Posts: 134 Rep Power: 4	Unlike c#, the "char" type in Java is not the same as its "Character" class. The Character class is a wrapper around the char type. All you need to do is explicitly convert int to char: (Toggle Plain Text) aChar = (char) countAscii; aChar = (char) countAscii;

Apr 9th, 2006, 8:36 PM	#3
Eric the Red Hobbyist Programmer Join Date: Feb 2006 Posts: 214 Rep Power: 0	thanks! __________________ Death smiles at us all. All a man can do is smile back.

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