the_real_g

Hey everyone

I'm not good with java so i was wondering if anyone could help me build this basic java program in textpad. I need to have a program that takes a string (upper case only) as a parameter and returns a histogram of the letters in the string. The ith element of the histogram should contain the number of ith character in the string alphabet. For example, if the user types in a "AAABBEECEDEDEDDDE", then the string alphabet is "(A,B,C,D,E)". The output should like something like this:

Please input a string:
> AAABBEECEDEDEDDDE
The histogram is:
A xxx
B xx
E xxxxxx
C x
D xxxxx

Anyone who can code this, thanks alot!!!!!!

Mjordan2nd

Show us what you have attempted so far. The lowest price you will be able to pay anyone on this forum to do your code thus far would be $999.98 I believe. Personally, I cost $1000.

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the_real_g

This is what i have so far. It only reads the input i think. I does not give my required output. Can you help?

class Histogram
{
public static void main(String[] args)
*throws java.io.IOException
*{
*char c;
*StringBuffer name = new StringBuffer();
*
*System.out.println("Please input a string and press enter")
*do
*{
*c = (char)System.in.read();
*name.append©;
*}

Thanks

sykkn

have a little formatting ... no charge ... it's on me ....



I'm not sure what the © thing is all about ...

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/* Don't make me use it! */

Berto

c = (char)System.in.read();

that line will throw an error on more then 1 character :/

Here is a little idea in pseudo codeish on how to get it done

Create array size 26 type int - each elemnt starts at 0;
readin line from user = line
for (int i = 0;i < line.length(); i++){
get character at position i;
case 'a'
array[1]++;

then

method to create #
for (int i = 0; i < 26; i++)
print new line
print amount of # for the number in the array

(i no its poo pseudo code but dont want to give you the answer/.

__________________
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- Albert Einstein

sykkn

this does not give an error if you enter more than one character. System.in.read() by default only reads 1 char from the STDIN. In order for you to use this though, you need to complete your do-WHILE loop.

This will get you passed reading the user input ... you should be able to take it from there.

__________________
[ [ SykkN alloc ] initWithThePowerTo: destroyYouAll ];
/* Don't make me use it! */

qub333

do yourslef a favor an read the input into a string,

import java.io.*;

public class ReadString {

public static void main (String[] args) {

// prompt the user to enter their name
System.out.print("Enter your name: ");

// open up standard input
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

String userName = null;

// read the username from the command-line; need to use try/catch with the
// readLine() method
try {
userName = br.readLine();
} catch (IOException ioe) {
System.out.println("IO error trying to read your name!");
System.exit(1);
}

System.out.println("Thanks for the name, " + userName);

}

} // end of ReadString class


or the more inplementable version

import java.io.*;

public class ReadString {

public String read (String prompt) {

// prompt the user to enter their name
System.out.print(prompt);

// open up standard input
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

String input = null;

// read the username from the command-line; need to use try/catch with the
// readLine() method
try {
input = br.readLine();
} catch (IOException ioe) {
System.out.println("IO error trying to read your name!");
System.exit(1);
}

return input;
}

} // end of ReadString class


i don't get exactly why you would want to read each letter individualy, thats more C than something like this, Java has quite an extensive API and thier documentation is exclent, more than once ive started a project only to find that half of it was already done. granted, its still good practice to learn how to do it the hard way, but something like this, it just makes life much simpler.