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dnathe4th · Oct 17th, 2004, 12:37 PM

What would the easiest way to go about scripting, or writing a program, that output all the (positive) solutions to a 5dimensional problem?
for instance:
(1/2)A + (1/4)B + (1/8)C + (1/16)D + (1/32)E = 1/2

Ooble · Oct 17th, 2004, 2:13 PM

I take it you mean (1/2)x + (1/4)x + (1/8)x + (1/16)x + (1/32)x = 1/2. The solution is to parse it into some sort of array or something that holds all the info, and then rearrange the equation I know this doesn't really help, but there's more

. Apparently Perl is brilliant for this sort of thing - look it up.

dnathe4th · Oct 17th, 2004, 2:36 PM

I used different letters rather than "X" because each variable needs to be different based on the coefficient. I'll get back to this post once i work it out

Ooble · Oct 17th, 2004, 4:36 PM

Ah... you mean ax^5 + bx^4 + cx^3 + dx^2 + ex = 0? I see... sounds complicated...

Ade · Oct 17th, 2004, 4:44 PM

may i ask why you need this?

dnathe4th · Oct 17th, 2004, 8:24 PM

Ooble, i mean as in :
(1/2)A + (1/4)B + (1/8)C + (1/16)D + (1/32)E = 1/2
as stated in my first post

Ade: It was a homework assignment for my brother (he's 12, i think they were just supposed to guess the answer), and being the programming dood i am, i wanted to figure out if it could be done by a program, since most things can, but i didn't know where to start, so i came here

Ooble · Oct 18th, 2004, 11:02 AM

Heh... sorry. That's my mind twisting things until they bear no resemblance to the original for ya.... be glad I'm not malicious

Pizentios · Oct 18th, 2004, 4:39 PM

What Class? Pre-Calc? Or Calc?

Mjordan2nd · Oct 18th, 2004, 4:56 PM

I'm guessing you mean all integers for values A, B, C, D, E. I just limited this to a 10 due to time constraints. I'm not sure this is what you want, but run this and tell me:

(Toggle Plain Text)

#include <stdio.h>
                                                        
int main(void)
{
    int a, b, c, d, e;
    FILE *fp;
    fp=fopen("answers.dat", "w+");
    for(a = 0; a<10; a++)
    {
        for(b=0; b<10; b++)
        {
            for(c=0; c<10; c++)
            {
                for(d=0;d<10;d++)
                {
                    for(e=0;e<10;e++)
                    {
                        if(((.5*a) + (.25 * b) + (.125 * c) + (.0625 * d) + (.03125 * e)) == .5)
                        {
                            fprintf(fp, "a=%d\nb=%d\nc=%d\nd=%d\ne=%d\n\n", a, b, c, d, e);
                        }
                    }
                }
            }
        }
    }
                                                        
    return 0;
}

Ade · Oct 19th, 2004, 4:05 PM

This all brings back painful memoriesof A-level math

Oct 17th, 2004, 12:37 PM	#1
dnathe4th Programmer Join Date: Oct 2004 Posts: 32 Rep Power: 0	What would the easiest way to go about scripting, or writing a program, that output all the (positive) solutions to a 5dimensional problem? for instance: (1/2)A + (1/4)B + (1/8)C + (1/16)D + (1/32)E = 1/2 __________________ <CENTER><span style='font-size:17pt;line-height:100%'>My Homepage</span></CENTER>

Oct 17th, 2004, 2:13 PM	#2
Ooble I eat cake for breakfast. Join Date: Jul 2004 Location: In my box. Posts: 4,434 Rep Power: 8	I take it you mean (1/2)x + (1/4)x + (1/8)x + (1/16)x + (1/32)x = 1/2. The solution is to parse it into some sort of array or something that holds all the info, and then rearrange the equation I know this doesn't really help, but there's more . Apparently Perl is brilliant for this sort of thing - look it up. __________________ Me :: You :: Them

Oct 17th, 2004, 2:36 PM	#3
dnathe4th Programmer Join Date: Oct 2004 Posts: 32 Rep Power: 0	I used different letters rather than "X" because each variable needs to be different based on the coefficient. I'll get back to this post once i work it out __________________ <CENTER><span style='font-size:17pt;line-height:100%'>My Homepage</span></CENTER>

Oct 17th, 2004, 4:36 PM	#4
Ooble I eat cake for breakfast. Join Date: Jul 2004 Location: In my box. Posts: 4,434 Rep Power: 8	Ah... you mean ax^5 + bx^4 + cx^3 + dx^2 + ex = 0? I see... sounds complicated... __________________ Me :: You :: Them

Oct 17th, 2004, 4:44 PM	#5
Ade Hobbyist Programmer Join Date: Oct 2004 Location: England, UK Posts: 139 Rep Power: 0	may i ask why you need this? __________________ Don't wound what you can't kill

Oct 17th, 2004, 8:24 PM	#6
dnathe4th Programmer Join Date: Oct 2004 Posts: 32 Rep Power: 0	Ooble, i mean as in : (1/2)A + (1/4)B + (1/8)C + (1/16)D + (1/32)E = 1/2 as stated in my first post Ade: It was a homework assignment for my brother (he's 12, i think they were just supposed to guess the answer), and being the programming dood i am, i wanted to figure out if it could be done by a program, since most things can, but i didn't know where to start, so i came here __________________ <CENTER><span style='font-size:17pt;line-height:100%'>My Homepage</span></CENTER>

Oct 18th, 2004, 11:02 AM	#7
Ooble I eat cake for breakfast. Join Date: Jul 2004 Location: In my box. Posts: 4,434 Rep Power: 8	Heh... sorry. That's my mind twisting things until they bear no resemblance to the original for ya.... be glad I'm not malicious __________________ Me :: You :: Them

Oct 18th, 2004, 4:39 PM	#8
Pizentios Programming Guru Join Date: May 2004 Location: Brandon, Manitoba, Canada Posts: 2,023 Rep Power: 7	What Class? Pre-Calc? Or Calc? __________________ Profanity is the one language that all programmers understand. Check out my Blog <---updated Nov 30 2007!

Oct 18th, 2004, 4:56 PM	#9
Mjordan2nd The Supreme Ruler Join Date: May 2004 Location: Houston Posts: 1,476 Rep Power: 6	I'm guessing you mean all integers for values A, B, C, D, E. I just limited this to a 10 due to time constraints. I'm not sure this is what you want, but run this and tell me: (Toggle Plain Text) #include <stdio.h> int main(void) { int a, b, c, d, e; FILE fp; fp=fopen("answers.dat", "w+"); for(a = 0; a<10; a++) { for(b=0; b<10; b++) { for(c=0; c<10; c++) { for(d=0;d<10;d++) { for(e=0;e<10;e++) { if(((.5a) + (.25 * b) + (.125 * c) + (.0625 * d) + (.03125 * e)) == .5) { fprintf(fp, "a=%d\nb=%d\nc=%d\nd=%d\ne=%d\n\n", a, b, c, d, e); } } } } } } return 0; } #include <stdio.h> int main(void) { int a, b, c, d, e; FILE fp; fp=fopen("answers.dat", "w+"); for(a = 0; a<10; a++) { for(b=0; b<10; b++) { for(c=0; c<10; c++) { for(d=0;d<10;d++) { for(e=0;e<10;e++) { if(((.5a) + (.25 * b) + (.125 * c) + (.0625 * d) + (.03125 * e)) == .5) { fprintf(fp, "a=%d\nb=%d\nc=%d\nd=%d\ne=%d\n\n", a, b, c, d, e); } } } } } } return 0; } __________________ "Every gun that is made, every warship launched, every rocket signifies, in the final sense, a theft from those who hunger and are not fed, from those who are cold and are not clothed. The world in arms is not spending money alone. It is spending the sweat of its laborers, the genius of its scientists, the hopes of its children." - Dwight D. Eisenhower

Oct 19th, 2004, 4:05 PM	#10
Ade Hobbyist Programmer Join Date: Oct 2004 Location: England, UK Posts: 139 Rep Power: 0	This all brings back painful memoriesof A-level math __________________ Don't wound what you can't kill

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