Programming Forums > Application Development > C++

BlueRaja · Oct 10th, 2004, 4:09 PM

I have a conditional similar to the following:

#define OTHER_NUMBER 300
...
float MyFunction(int);
...
if (MyFunction(somenumber)==OTHER_NUMBER)

MyFunction is returning a value of 300.000 (confirmed by my wonderful debugger ^_^); however, the conditional is being evaluated as false. I've also tried the following:

(Toggle Plain Text)

#define OTHER_NUMBER 300.000

(Toggle Plain Text)

if ((int)MyFunction(somenumber)==OTHER_NUMBER)

(Toggle Plain Text)

if (MyFunction(somenumber)==(float)OTHER_NUMBER)

(Toggle Plain Text)

if (static_cast<int>(MyFunction(somenumber))==OTHER_NUMBER)//I'm not even quite sure what static_cast does...

But to no avail...
Any ideas? Thanks in advance.

Ooble · Oct 11th, 2004, 10:07 AM

You can either declare the function as int, or typecast it to an integer by placing (int) in front of the function call:

(Toggle Plain Text)

if ((int)MyFunction(somenumber) == OTHER_NUMBER)

Oct 10th, 2004, 4:09 PM	#1
BlueRaja Newbie Join Date: Oct 2004 Posts: 2 Rep Power: 0	I have a conditional similar to the following: (Toggle Plain Text) #define OTHER_NUMBER 300 ... float MyFunction(int); ... if (MyFunction(somenumber)==OTHER_NUMBER) #define OTHER_NUMBER 300 ... float MyFunction(int); ... if (MyFunction(somenumber)==OTHER_NUMBER) MyFunction is returning a value of 300.000 (confirmed by my wonderful debugger ^_^); however, the conditional is being evaluated as false. I've also tried the following: (Toggle Plain Text) #define OTHER_NUMBER 300.000 #define OTHER_NUMBER 300.000 (Toggle Plain Text) if ((int)MyFunction(somenumber)==OTHER_NUMBER) if ((int)MyFunction(somenumber)==OTHER_NUMBER) (Toggle Plain Text) if (MyFunction(somenumber)==(float)OTHER_NUMBER) if (MyFunction(somenumber)==(float)OTHER_NUMBER) (Toggle Plain Text) if (static_cast<int>(MyFunction(somenumber))==OTHER_NUMBER)//I'm not even quite sure what static_cast does... if (static_cast<int>(MyFunction(somenumber))==OTHER_NUMBER)//I'm not even quite sure what static_cast does... But to no avail... Any ideas? Thanks in advance. __________________ <span style='color:red'>AKhalifman@hotmail.com</span>

Oct 11th, 2004, 10:07 AM	#2
Ooble I eat cake for breakfast. Join Date: Jul 2004 Location: In my box. Posts: 4,434 Rep Power: 9	You can either declare the function as int, or typecast it to an integer by placing (int) in front of the function call: (Toggle Plain Text) if ((int)MyFunction(somenumber) == OTHER_NUMBER) if ((int)MyFunction(somenumber) == OTHER_NUMBER) __________________ Me :: You :: Them

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Programming Forums > Application Development > C++

Wow, Stupid Noob Question