Programming Forums > Application Development > C

bivhitscar · Nov 2nd, 2005, 8:34 PM

Is it possible to print the escape sequence representation of a nonprinting character using printf()? ie. print "\n" instead of actually printing the newline itself.

I am trying to get a loop to read a string and print each character with it's equivalent ascii code. But this all turns to shit mainly with the newline character. Aside from making a kinda long if statement to filter the possibilites, any suggestions?

nindoja · Nov 2nd, 2005, 8:37 PM

[code]printf("\\n");[code]
Basically, escape the backslash, so the escape sequence isn't seen.

bivhitscar · Nov 2nd, 2005, 8:48 PM

Quote:

Originally Posted by nindoja

(Toggle Plain Text)

printf("\\n");

Basically, escape the backslash, so the escape sequence isn't seen.

That only works when I know what character is coming.

This is the code I'm using:

(Toggle Plain Text)

for (i = 1; i <= length; i++)
  {
    printf("%c = %3d, ", string[i - 1], string[i - 1]);

    if (i % 8 == 0)
      printf("\n");
  }

That basicaly says, read the current element of the array, print the character and print it's ascii code. The if statement is just for formatting purposes.

Ideally, I just want a simple if else that says if ch == isspace() print the escape sequence instead of the actual character, else print the character. Am I making any sense?

bivhitscar · Nov 2nd, 2005, 8:56 PM

Actually, after reviewing what characters would actually pop up in real input, it's only two - a fair bit easier than I first thought. Although, I'd still like to hear if it's possible.

InfoGeek · Nov 3rd, 2005, 3:08 AM

You can do something like

(Toggle Plain Text)

if(ch=='\n')
  printf("<new-line> - %3d",ch);
else if(ch==' ')
  printf("<space> - %3d",ch);

bivhitscar · Nov 3rd, 2005, 10:08 PM

Quote:

Originally Posted by InfoGeek

You can do something like

(Toggle Plain Text)

if(ch=='\n')
  printf("<new-line> - %3d",ch);
else if(ch==' ')
  printf("<space> - %3d",ch);

Yeh, I just ended up using a switch. Thanks though.

Nov 2nd, 2005, 8:34 PM	#1
bivhitscar Hobbyist Programmer Join Date: Oct 2005 Location: Melbourne, Australia Posts: 126 Rep Power: 3	Printing escape sequences using printf()? Is it possible to print the escape sequence representation of a nonprinting character using printf()? ie. print "\n" instead of actually printing the newline itself. I am trying to get a loop to read a string and print each character with it's equivalent ascii code. But this all turns to shit mainly with the newline character. Aside from making a kinda long if statement to filter the possibilites, any suggestions? __________________ it's ironic considerate rarity patron of love higher knowledge engulfs me...

Nov 2nd, 2005, 8:56 PM	#4
bivhitscar Hobbyist Programmer Join Date: Oct 2005 Location: Melbourne, Australia Posts: 126 Rep Power: 3	Actually, after reviewing what characters would actually pop up in real input, it's only two - a fair bit easier than I first thought. Although, I'd still like to hear if it's possible. __________________ it's ironic considerate rarity patron of love higher knowledge engulfs me...

Nov 3rd, 2005, 3:08 AM	#5
InfoGeek Professional Programmer Join Date: Jun 2005 Location: India, The great. Posts: 435 Rep Power: 4	You can do something like (Toggle Plain Text) if(ch=='\n') printf("<new-line> - %3d",ch); else if(ch==' ') printf("<space> - %3d",ch); if(ch=='\n') printf("<new-line> - %3d",ch); else if(ch==' ') printf("<space> - %3d",ch); __________________ PFO - My daily dose of technology.

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Nov 2nd, 2005, 8:37 PM	#2
nindoja Programmer Join Date: Jun 2005 Posts: 92 Rep Power: 4	[code]printf("\\n");[code] Basically, escape the backslash, so the escape sequence isn't seen.

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Programming Forums > Application Development > C

Printing escape sequences using printf()?