Programming Forums > Application Development > Visual Basic

Worried newbie · Oct 4th, 2005, 4:09 AM

I have just recently started college and with it started using vb6 for the first time, recently i was given a task to do but because i have little or no experience with this im really worried because i have become so worried about the problem that my brain wont allow me to think about it without panicing....

What shape will be displayed by the following vb program for any value of n>1?
for i = 1 to n
for j = 1 to i
print "+";
next j
print
next i

Im sure this is very easy but i sit here pen in hand cunfused and realy worried

Im not looking for the answer but an understandable explanaition and an example of my problem so i can do it myself

Thankyou for any help

stevengs · Oct 4th, 2005, 5:31 AM

why don't you try to compile it and run it?

Worried newbie · Oct 4th, 2005, 5:36 AM

Quote:

Originally Posted by stevengs

why don't you try to compile it and run it?

Im not aloud to do that, i have to do it on paper.

InfoGeek · Oct 4th, 2005, 5:35 AM

Output for n=5

(Toggle Plain Text)

+
++
+++
++++
+++++

OpenLoop · Oct 4th, 2005, 10:48 AM

then run it on the paper. Pick a value for n, say n = 3 and go thru the loop one iteration at a time and record the output everytime you encounter a "print" statement.

Worried newbie · Oct 4th, 2005, 1:01 PM

I have had a go and come out with three different out comes.

First is
1
12
123
1234
12345

second is
1
23
345
4567
56789

Third is
1
23
345
4567
56789

They were n=5..... now in really confused but i think one is correct?

OpenLoop · Oct 4th, 2005, 1:08 PM

If you where printing j the first one will be correct for n=5. But look at the code closely, what are you printing?

(Toggle Plain Text)

for i = 1 to n
  for j = 1 to i
      print "+";
  next j
  print
next i

You're printing "+" for every iteration of the nested loop(the one with j) and a new line for every iteration of the i loop.
Follow the same logic you did in your first try but take what i said in consideration.

Worried newbie · Oct 4th, 2005, 1:19 PM

Ok so im trying to think, if n = 10 it would look like this
+
++
+++
++++
+++++
++++++
+++++++
++++++++
+++++++++
++++++++++

I know this must seem so easy to some people but it can be very confusing to a first time user so thanx a lot for all the help

OpenLoop · Oct 4th, 2005, 1:20 PM

Yes, you got it. Now try to understand it very well, this is a good exercise on loops.

Worried newbie · Oct 4th, 2005, 1:23 PM

Let me just confirm this if n = 12 and print is "*": then it should look like this
*
**
***
****
*****
******
*******
********
*********
**********
***********
************

Oct 4th, 2005, 4:09 AM	#1
Worried newbie Newbie Join Date: Oct 2005 Posts: 6 Rep Power: 0	Please help I have just recently started college and with it started using vb6 for the first time, recently i was given a task to do but because i have little or no experience with this im really worried because i have become so worried about the problem that my brain wont allow me to think about it without panicing.... What shape will be displayed by the following vb program for any value of n>1? for i = 1 to n for j = 1 to i print "+"; next j print next i Im sure this is very easy but i sit here pen in hand cunfused and realy worried Im not looking for the answer but an understandable explanaition and an example of my problem so i can do it myself Thankyou for any help

Oct 4th, 2005, 5:31 AM	#2
stevengs Professional Programmer Join Date: May 2005 Location: Bad Nauheim, Germany Posts: 436 Rep Power: 4	why don't you try to compile it and run it? __________________ -Steven "Is this a piece of your brain?" - Basil Fawlty

Oct 4th, 2005, 5:35 AM	#4
InfoGeek Professional Programmer Join Date: Jun 2005 Location: India, The great. Posts: 435 Rep Power: 4	Output for n=5 (Toggle Plain Text) + ++ +++ ++++ +++++ + ++ +++ ++++ +++++ __________________ PFO - My daily dose of technology.

Oct 4th, 2005, 1:08 PM	#7
OpenLoop Expert Programmer Join Date: May 2005 Location: East Lansing, MI Posts: 663 Rep Power: 4	If you where printing j the first one will be correct for n=5. But look at the code closely, what are you printing? (Toggle Plain Text) for i = 1 to n for j = 1 to i print "+"; next j print next i for i = 1 to n for j = 1 to i print "+"; next j print next i You're printing "+" for every iteration of the nested loop(the one with j) and a new line for every iteration of the i loop. Follow the same logic you did in your first try but take what i said in consideration.

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Oct 4th, 2005, 10:48 AM	#5
OpenLoop Expert Programmer Join Date: May 2005 Location: East Lansing, MI Posts: 663 Rep Power: 4	then run it on the paper. Pick a value for n, say n = 3 and go thru the loop one iteration at a time and record the output everytime you encounter a "print" statement.

Oct 4th, 2005, 1:01 PM	#6
Worried newbie Newbie Join Date: Oct 2005 Posts: 6 Rep Power: 0	I have had a go and come out with three different out comes. First is 1 12 123 1234 12345 second is 1 23 345 4567 56789 Third is 1 23 345 4567 56789 They were n=5..... now in really confused but i think one is correct?

Oct 4th, 2005, 1:19 PM	#8
Worried newbie Newbie Join Date: Oct 2005 Posts: 6 Rep Power: 0	Ok so im trying to think, if n = 10 it would look like this + ++ +++ ++++ +++++ ++++++ +++++++ ++++++++ +++++++++ ++++++++++ I know this must seem so easy to some people but it can be very confusing to a first time user so thanx a lot for all the help

Oct 4th, 2005, 1:20 PM	#9
OpenLoop Expert Programmer Join Date: May 2005 Location: East Lansing, MI Posts: 663 Rep Power: 4	Yes, you got it. Now try to understand it very well, this is a good exercise on loops.

Oct 4th, 2005, 1:23 PM	#10
Worried newbie Newbie Join Date: Oct 2005 Posts: 6 Rep Power: 0	Let me just confirm this if n = 12 and print is "": then it should look like this * ** * ** *** **** ***** ****** ******* **********

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Programming Forums > Application Development > Visual Basic

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