Programming Forums > Application Development > C++

LOI Kratong · Sep 25th, 2005, 8:20 AM

hey guys, i have a console program into which i want to put a menu. I have a partly working menu, but it skips the getline part... heres the code:

(Toggle Plain Text)

if (op == 1)
       {
              bruteforce_input(); //<----- skips this part
      //other code...
       }

and then the function:

(Toggle Plain Text)

void bruteforce_input ()
{
     cout << "\n\n\n\n\t\t To begin Brute Forcing a ceasar shift,\n\t\t enter the cipher text:\n\n\t\t>";
     getline(cin,ciphertext);
     cout << "\t\t --------------------------------------\n\n\n";
     cls();
     cout << "\n\n\t\tStarting the brute force...\n\n\n";    
}

the getline() as i mentioned before skips when i try to run the program. Anyone know why?

DaWei · Sep 25th, 2005, 8:36 AM

Have you done previous input? You probably have a newline in the buffer that is satisfying the call. Put cin.sync () prior to the call. After the call, TEST CIN FOR FAILURE. That would be, "if (!cin.good ()) // Bad news ". Failing to to this is the hallmark of a newb or a schlock.

LOI Kratong · Sep 26th, 2005, 1:34 PM

Yeah i have previous input... thanks.

Right suppose you could call me a schlock...

Sep 25th, 2005, 8:20 AM	#1
LOI Kratong Professional Programmer Join Date: May 2005 Location: Woo - Boot Sector! Posts: 294 Rep Power: 4	getline() skipping. help? hey guys, i have a console program into which i want to put a menu. I have a partly working menu, but it skips the getline part... heres the code: (Toggle Plain Text) if (op == 1) { bruteforce_input(); //<----- skips this part //other code... } if (op == 1) { bruteforce_input(); //<----- skips this part //other code... } and then the function: (Toggle Plain Text) void bruteforce_input () { cout << "\n\n\n\n\t\t To begin Brute Forcing a ceasar shift,\n\t\t enter the cipher text:\n\n\t\t>"; getline(cin,ciphertext); cout << "\t\t --------------------------------------\n\n\n"; cls(); cout << "\n\n\t\tStarting the brute force...\n\n\n"; } void bruteforce_input () { cout << "\n\n\n\n\t\t To begin Brute Forcing a ceasar shift,\n\t\t enter the cipher text:\n\n\t\t>"; getline(cin,ciphertext); cout << "\t\t --------------------------------------\n\n\n"; cls(); cout << "\n\n\t\tStarting the brute force...\n\n\n"; } the getline() as i mentioned before skips when i try to run the program. Anyone know why? __________________ www.heldtogether.co.uk

Sep 25th, 2005, 8:36 AM	#2
DaWei Resident Grouch Join Date: Jun 2005 Posts: 6,453 Rep Power: 10	Have you done previous input? You probably have a newline in the buffer that is satisfying the call. Put cin.sync () prior to the call. After the call, TEST CIN FOR FAILURE. That would be, "if (!cin.good ()) // Bad news ". Failing to to this is the hallmark of a newb or a schlock. __________________ Abstraction doesn't make it impossible to write bad code; it makes it possible to write superior code. Contributor's Corner: Grumpy on C++ Exceptions DaWei on Pointers

Sep 26th, 2005, 1:34 PM	#3
LOI Kratong Professional Programmer Join Date: May 2005 Location: Woo - Boot Sector! Posts: 294 Rep Power: 4	Yeah i have previous input... thanks. Right suppose you could call me a schlock... __________________ www.heldtogether.co.uk

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Programming Forums > Application Development > C++

getline() skipping. help?