#include <iostream>

int main()
{
    std::string name;
    int age;
    std::string ansr;
    std::string new_name;
    std::string ans;
        
    std::cout << "what's your name?\n";
    std::cin >> name;
    if (name != "Broax")
    new_name = name;
    if (name == "Broax")
    {
             std::cout << "Hello, Broax! You are 20 years old right?\n";
             ansa:
             std::cin >> ansr;
             if (ansr == "Yes")
             {
                      std::cout << "Yeah! I'm good!\n";
                      goto end;
                      }
             else if (ansr == "No")
             {
                       std::cout << "Liar! I'm never wrong!\n";
                       goto end;
                       }
             else
             {
                       std::cout << "Just say Yes or No, man!\n";
                       goto ansa;
                       }
             }
    else
    std::cout << "Hmmm... Nice to meet you, " << name <<"! =) How old are you?\n";
    std::cin >> age;
    std::cout << "Ok, " << name << " you're " << age <<"... I'll keep that in mind, now!\n\nDo you want to test me?\n";
    ansb:
    std::cin >> ans;
    if (ans == "Yes")
    std::cout << "Lol! =p You're name is " << new_name << " and you're " << age << " see... I didn't forget!\n";
    else if (ans == "No")
    std::cout << "Nice to see that you trust me! =D\n";
    else
    {
        std::cout << "Say what?\n";
        std::cout << "C'mon... give me a straight answer! Yes or No?\n";
        goto ansb;
        }
    end:
    std::cout << "Well then... Now that we're over with this it's time to say goodbye, ok?\nI'll miss you and stuff!\n\n";
    std::cout << "And thus we end our little tale of love and adventure! Please press return to get back to your life, being now certain that your names is " << new_name << " and that you are " << age << "!\n";
    std::cin.get()
    return 0;
}

#include <iostream>
using namespace std;    //it is easier to use this instead of std::bla. 

int main()
{
    string name;
    int age;
    string ansr;
    string new_name;
    string ans;
    bool stay = false;
        
    cout << "what's your name?\n";
    cin >> name;
    if (name != "Broax")
          new_name = name;
    if (name == "Broax")
    {
             cout << "Hello, Broax! You are 20 years old right?\n";
             do
             {    
                stay = false;
                cin >> ansr;
                if (ansr == "Yes")
                {
                      cout << "Yeah! I'm good!\n";
                }
                else if (ansr == "No")
                {
                       cout << "Liar! I'm never wrong!\n";
                }
                else
                {
                       cout << "Just say Yes or No, man!\n";
                       stay = true;
                }
         }while(stay); 
    }
    else
   {
       cout << "Hmmm... Nice to meet you, " << name <<"! =) How old are you?\n";
       cin >> age;
       cout << "Ok, " << name << " you're " << age <<"... I'll keep that in mind, now!\n\nDo you want to test me?\n";
       do
      {
          stay = false;
          cin >> ans;
          if (ans == "Yes")
               cout << "Lol! =p You're name is " << new_name << " and you're " << age << " see... I didn't forget!\n";
          else if (ans == "No")
               cout << "Nice to see that you trust me! =D\n";
          else
          {
             cout << "Say what?\n";
             cout << "C'mon... give me a straight answer! Yes or No?\n";
            stay = true;
          }
      }while(stay)
  cout << "Well then... Now that we're over with this it's time to say goodbye, ok?\nI'll miss you and stuff!\n\n";
  cout << "And thus we end our little tale of love and adventure! Please press return to get back to your life, being now certain that your names is " << new_name << " and that you are " << age << "!\n";
    cin.get()
    return 0;
}

#include <iostream>
#include <string>
#include <stdlib> // to use std::cin.get();

// miss type variable name (i.e ansa or ansb should be ansr)
// forgot to include string heder file. 

int main()
{
    std::string name;
    int age;
    std::string ansr;
    std::string new_name;
    std::string ans;
        
    std::cout << "what's your name?\n";
    std::cin >> name;
    
    if (name != "Broax")
       new_name = name;
    
    if (name == "Broax")
    {
             std::cout << "Hello, Broax! You are 20 years old right?\n";
             ansr:
             std::cin >> ansr;
             if (ansr == "Yes")
             {
                      std::cout << "Yeah! I'm good!\n";
                      break;
             }
             else if (ansr == "No")
             {
                       std::cout << "Liar! I'm never wrong!\n";
                       break;
             }
             else
             {
                       std::cout << "Just say Yes or No, man!\n";
                       return ansr;
                       }
             }
    else
    std::cout << "Hmmm... Nice to meet you, " << name <<"! =) How old are you?\n";
    std::cin >> age;
std::cout << "Ok, " << name << " you're " << age <<"... I'll keep that in mind, now!\n\nDo you want to test me?\n";

    std::cin >> ans;
    
    if (ans == "Yes")
std::cout << "Lol! =p You're name is " << new_name << " and you're " << age << " see... I didn't forget!\n";
       else if (ans == "No")
          std::cout << "Nice to see that you trust me! =D\n";
    else
    {
        std::cout << "Say what?\n";
        std::cout << "C'mon... give me a straight answer! Yes or No?\n";
        return ans;
    }
    
  
 std::cout << "Well then... Now that we're over with this it's time to say goodbye, ok?\nI'll miss you and stuff!\n\n";
std::cout << "And thus we end our little tale of love and adventure! Please press return to get back to your life, being now certain that your names is " << new_name << " and that you are " << age << "!\n";
 std::cin.get();
    
    return 0;
}

#include <iostream>
#include <string>

using namespace std;

int uhOh (string badNews)
{
	cerr << badNews << endl;
	return EOF;
}
int main()
{
    string name;
	string answer;
	string newName;
    int age = 20;
	bool badAnswer = true;
        
    cout << "What's your name?\n";

	// This function (>>) will delimit its input on whitespace.  Check the
	// manual for these input functions to determine what you need.
	// Cin is an input stream and has numerous other methods associated
	// with it, such as .get (), .getline (), and so forth.  The extraction
	// operator (>>) is probably the most problematic function it has.  Its
	// primary attraction is simplicity.  The string class also has a getline
	// method that is distinct from the stream getline.

    // Replace this ==>  cin >> name;
	getline (cin, name);
	if (!cin.good ()) return uhOh ("Failure on input");

    // This is superfluous, as it's the same condition as the else clause
	// for the following test.  As a matter of fact, "new_name" is not
	// needed, as the name will be in "name".
	/*
	if (name != "Broax")
		new_name = name;
	*/
    if (name == "Broax")
    {
		// Everthing here if name is "Broax"
		cout << "Hello, Broax! You are 20 years old right?\n";
		while (badAnswer)
		{
			getline (cin, answer);
			// Don't forget to test the input stream -- exercise
			// Realize that there are case issues here.  "yes" will fail.
			if (answer == "Yes")
			{
				cout << "Yeah! I'm good!\n";
				badAnswer = false;
				// The else-if and else portions will automatically be skipped
				// goto end;          
			}
			else if (answer == "No")
			{
				cout << "Liar! I'm never wrong!\n";
				badAnswer = false;
				// goto end;
			}
			else
			{
				cout << "Just say Yes or No, man!\n";
			}
        }  // Will fall out of this while loop once a good answer is given
	}  // This is the end of the name == Broax part.  If we came here we
	   // will skip the entire else section and automatically wind up at the end
    else // This is if the name is NOT Broax.  It needs braces to block all the
		 // instructions.  Otherwise, only the first statement is considered to
		 // be part of the block.
	{    // <== put that brace there
		cout << "Hmmm... Nice to meet you, " << name <<"! =) How old are you?\n";

		// The following is asking for a number.  If the user (maliciously
		// or carelessly) enters something that can't be construed as a valid
		// number (like "Broax"), the input stream is going to go into a fail state 
		// and stay there until cleared.  The program is essentially going to run off 
		// into the weeds and barf on its shoes.
		cin >> age;
		// So test it
		if (!cin.good ()) return uhOh ("Shoulda used another input method");
		badAnswer = true;
		cout << "Ok, " << name << " you're " << age 
			 << "... I'll keep that in mind, now!\n\nDo you want to test me?\n";
		while (badAnswer)
		{
			// Even if the extraction operator worked properly, the ENTER keycode
			// will be left in the stream and will be read on the next input, which
			// is rarely what one wants.  Consequently, we dump it, and clear any
			// possible error.
			cin.sync ();
			cin.clear ();
			getline (cin, answer);
			// It is perfectly valid to leave out braces when the code block is
			// a single line.  It is, however, bad practice, until one accrues
			// more experience.  It's a mistake waiting to be made.
			if (answer == "Yes")
			{
				cout << "Lol! =p You're name is " << name 
					 << " and you're " << age << " see... I didn't forget!\n";
				badAnswer = false;
			}
			else if (answer == "No")
			{
				cout << "Nice to see that you trust me! =D\n";
				badAnswer = false;
			}
			else
			{
				cout << "Say what?\n";
				cout << "C'mon... give me a straight answer! Yes or No?\n";
				// goto ansb;
			}
		} // Will exit this while when a good answer is finally given
	} // This is the end of the "not Broax" section
	// Regardless of the name, we wind up here, no "goto" necessary.
    cout << "Well then... Now that we're over with this it's time to say goodbye, ok?\nI'll miss you and stuff!\n\n";
    cout << "And thus we end our little tale of love and adventure! Please press return to get back to your life, being now certain that your names is " 
		 << name << " and that you are " 
		 << age << "!\n";
    cin.get();
    return 0;
}

int sum(int x, int y)
{
    int z = x + y;
    return z; //returns the sum of x and y to the caller
}

void main()
{
   int w; 
   w = sum(3, 2);  //sum will return 5
   cout<<w;            //output is 5
}

Can I write "void main()"?
The definition 
	void main() { /* ... */ }

is not and never has been C++, nor has it even been C. See the ISO C++ 
standard 3.6.1[2] or the ISO C standard 5.1.2.2.1. A conforming 
implementation accepts 
	int main() { /* ... */ }

and 
	int main(int argc, char* argv[]) { /* ... */ }

A conforming implementation may provide more versions of main(), but they 
must all have return type int. The int returned by main() is a way for a 
program to return a value to "the system" that invokes it. On systems that 
doesn't provide such a facility the return value is ignored, but that doesn't 
make "void main()" legal C++ or legal C. Even if your compiler accepts "void 
main()" avoid it, or risk being considered ignorant by C and C++ programmers. 
In C++, main() need not contain an explicit return statement. In that case, 
the value returned is 0, meaning successful execution. For example: 

	#include<iostream>

	int main()
	{
		std::cout << "This program returns the integer value 0\n";
	}

Note also that neither ISO C++ nor C99 allows you to leave the type out of a 
declaration. That is, in contrast to C89 and ARM C++ ,"int" is not assumed 
where a type is missing in a declaration. Consequently: 
	#include<iostream>

	main() { /* ... */ }

is an error because the return type of main() is missing.