Berto

A chap came into work this morning with a puzzle for us to solve, here it is

G G J D G F F
G G G P B F F
G G B D G F F
-----------------
Z N Y H P B G

standard maths where you add down the coloum etc etc

but each lettar is a number between 0 and 9.

I dont no the answer myself (gonna work it out lunch time) just though you lot might want to have a go at it. I am currently writing a program to solve the problem as well.

__________________
"Put your hand on a hot stove for a minute, and it seems like an hour. Sit with a pretty girl for an hour, and it seems like a minute. THAT'S relativity."

- Albert Einstein

HeX

can you please provide more details, because how can it be 3G = Z, and at the same time 3G = N. This is possible only when Z and N are equal.

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TheFalseDragon

Y-1
G-2
B-3
D-4
F-4
J-5
Z-6
H-6
N-7
P-8

Berto

Dragon its wrong and to HeX dont you remember basic maths?


9+4 = 13 carry the 1 over to the other side? remember that stuff?


Dragon you can only use 1 number once eg all g's are 4 so 4 cannot be used for any other letter.

__________________
"Put your hand on a hot stove for a minute, and it seems like an hour. Sit with a pretty girl for an hour, and it seems like a minute. THAT'S relativity."

- Albert Einstein

EdSalamander

D=1
G=2
B=3
F=4
Y=5
Z=6
N=7
P=8
J=9
H=0

That was a fun way to start the day! Thanks Berto!

(FYI it's probably easier to just do the logic and write it out on paper than to write a program for it, it's not very hard really )

__________________
I can pick my friends. And I can pick my nose. So, why can't I pick my friend's nose?

TheFalseDragon

ye i was doing it in my head, i thought that i might have had to use each one once but i tried to just get an answer down

Navid

one thing i noticed is that "J" can be anything really. So "Z", "N" and "Y" can be anything too. (or maybe im wrong)

For the rest, I just finished my math exam today so maybe next year

But i like these kind of problems, good logical programming practice. errr...sort of

Berto

Unfortunatly i think you are wrong as i have only found 1 answer to the question, and so therefore only 1 number for each letter.

__________________
"Put your hand on a hot stove for a minute, and it seems like an hour. Sit with a pretty girl for an hour, and it seems like a minute. THAT'S relativity."

- Albert Einstein

EdSalamander

Well, the fact that you found only one solution doesn't mean there aren't more. That doesn't mean I don't agree with you though. There's only one solution. It rests mostly on the fact that P must equal 8. That established, 8 plus 2D must equal one of the other remaining digits excluding the carry it creates. All that remain at that point are 0, 1, 5, 7, and 9. Even trial-and-error is fast enough to show that D then must equal 1 and H equal 0. The next line up does the same thing only with J = 9 and Y = 5, since those are the only tho remaining digits that can be made to work around the other numbers (which sum up to 6 [3 + 2 + 1carry]).

..ok, so maybe this isn't perfectly clear after all, but there's no need to go overboard explaining it, so ill stop with a simple: Yes, Berto, there's only one solution. :p

__________________
I can pick my friends. And I can pick my nose. So, why can't I pick my friend's nose?

Berto

well G has to be less than or equal to 3 - as 3G < 9
and it cant equal 0 as then Z would equal Zero.

3 numbers multiplied between 0 and 9 whoms answer is greater then 10 there are only 4 and 7 you can use (12 and 21) there is no 3 answer so g has to equal 2 or 3 and it just goes on from there,

i tried bopth 4 and 7 and only one fo them works

__________________
"Put your hand on a hot stove for a minute, and it seems like an hour. Sit with a pretty girl for an hour, and it seems like a minute. THAT'S relativity."

- Albert Einstein