Programming Forums > Script Programming > Python

lingon · May 1st, 2005, 2:14 PM

Hi! If I, for exampel, enter the number 123456 is there any way that I can make python read it as 1,2,3,4,5,6?And thus for eampel give the numbers the names a,b,c,d,e,f and then "print a+b+c+d+e+f" and get the answer 21?

Ooble · May 1st, 2005, 2:18 PM

What you're asking for is actually very simple. However, I would suggest using an array, and splitting the initial string into single-digit numbers. Have fun.

Sane · May 1st, 2005, 2:30 PM

(Toggle Plain Text)

a = 1
b = 2
c = 3
d = 4
e = 5
f = 6

print a,",",b,",",c,",",d,",",e,",",f
print "The sum of all those numbers is: %s"%(a+b+c+d+e+f)

(Toggle Plain Text)

a = "1"
b = "2"
c = "3"
d = "4"
e = "5"
f = "6"

x = [a,b,c,d,e,f]
print ",".join(x)
x = int(a)+int(b)+int(c)+int(d)+int(e)+int(f)
print "The sum of all those numbers is:", x

(Toggle Plain Text)

print "1, 2, 3, 4, 5, 6"
print "The sum of all those numbers is: 21"

There are actually a million more ways to do this.

Ooble · May 1st, 2005, 2:51 PM

(Toggle Plain Text)

import string

str = raw_input("Enter some numbers: ")
numbers = string.split(str, " ", 1)
for number in numbers:
    print str(number) + " ",

I think that should do it.

lingon · May 2nd, 2005, 1:50 PM

Hmm...What I'm actually trying to do is to make a program that uses a special algorithm to calculate the last number of your person number.
Ex.
881221 0759 This is my number
212121 2121 This is the algorithm. You here take 8*2,8*1,1*2 and so on untill you get the number(in this case):
16821410710 Now you do:
1+6+8+2+1+4+1+0+7+1+0 = 31 Now you take the higest nearest ten and minus it with the number you got:
40-31 = 9 Wich is correct
Can anyone make a program for this?
It sure beats me, but then I guess I suck at this :p

Moldz · May 2nd, 2005, 3:31 PM

You are not going to get better if you don't try. I wrote the program, it's not too hard. Try it and post any problems you are having. I will start you off:

(Toggle Plain Text)

pernum = '8812210759'
for digit in pernum:
   print digit

You might also want to check out the int() and str() functions.

lingon · May 3rd, 2005, 8:47 AM

Okej, so now it splits it into 9 different numbers but it doesn't understand that they are actually numbers.
Ex. if you print "print digit*2" it prints 88 instead of 16 and 22 instead of 4.
So how do I make it understand that it is numbers not letters? I tryed some different int() things but they didn't work

Moldz · May 3rd, 2005, 9:02 AM

Here's what I did in the python console:

(Toggle Plain Text)

>>> digit = "5"
>>> type(digit)
<type 'str'>
>>> number = int(digit)
>>> type(number)
<type 'int'>

That should help.

lingon · May 8th, 2005, 11:41 AM

Okej, thanks. I'll see if I can make it work

May 1st, 2005, 2:14 PM	#1
lingon Newbie Join Date: Apr 2005 Posts: 17 Rep Power: 0	Help please! Hi! If I, for exampel, enter the number 123456 is there any way that I can make python read it as 1,2,3,4,5,6?And thus for eampel give the numbers the names a,b,c,d,e,f and then "print a+b+c+d+e+f" and get the answer 21?

May 1st, 2005, 2:18 PM	#2
Ooble I eat cake for breakfast. Join Date: Jul 2004 Location: In my box. Posts: 4,434 Rep Power: 9	What you're asking for is actually very simple. However, I would suggest using an array, and splitting the initial string into single-digit numbers. Have fun. __________________ Me :: You :: Them

May 1st, 2005, 2:30 PM	#3
Sane Programming Guru Join Date: Apr 2005 Location: Waterloo, Ontario Posts: 1,885 Rep Power: 5	(Toggle Plain Text) a = 1 b = 2 c = 3 d = 4 e = 5 f = 6 print a,",",b,",",c,",",d,",",e,",",f print "The sum of all those numbers is: %s"%(a+b+c+d+e+f) a = 1 b = 2 c = 3 d = 4 e = 5 f = 6 print a,",",b,",",c,",",d,",",e,",",f print "The sum of all those numbers is: %s"%(a+b+c+d+e+f) (Toggle Plain Text) a = "1" b = "2" c = "3" d = "4" e = "5" f = "6" x = [a,b,c,d,e,f] print ",".join(x) x = int(a)+int(b)+int(c)+int(d)+int(e)+int(f) print "The sum of all those numbers is:", x a = "1" b = "2" c = "3" d = "4" e = "5" f = "6" x = [a,b,c,d,e,f] print ",".join(x) x = int(a)+int(b)+int(c)+int(d)+int(e)+int(f) print "The sum of all those numbers is:", x (Toggle Plain Text) print "1, 2, 3, 4, 5, 6" print "The sum of all those numbers is: 21" print "1, 2, 3, 4, 5, 6" print "The sum of all those numbers is: 21" There are actually a million more ways to do this. Last edited by Sane; May 1st, 2005 at 2:33 PM.

May 1st, 2005, 2:51 PM	#4
Ooble I eat cake for breakfast. Join Date: Jul 2004 Location: In my box. Posts: 4,434 Rep Power: 9	(Toggle Plain Text) import string str = raw_input("Enter some numbers: ") numbers = string.split(str, " ", 1) for number in numbers: print str(number) + " ", import string str = raw_input("Enter some numbers: ") numbers = string.split(str, " ", 1) for number in numbers: print str(number) + " ", I think that should do it. __________________ Me :: You :: Them

May 2nd, 2005, 1:50 PM	#5
lingon Newbie Join Date: Apr 2005 Posts: 17 Rep Power: 0	Hmm...What I'm actually trying to do is to make a program that uses a special algorithm to calculate the last number of your person number. Ex. 881221 0759 This is my number 212121 2121 This is the algorithm. You here take 82,81,12 and so on untill you get the number(in this case): 16821410710 Now you do: 1+6+8+2+1+4+1+0+7+1+0 = 31 Now you take the higest nearest ten and minus it with the number you got: 40-31 = 9 Wich is correct Can anyone make a program for this? It sure beats me, but then I guess I suck at this :p Last edited by lingon; May 2nd, 2005 at 2:22 PM.*

May 2nd, 2005, 3:31 PM	#6
Moldz Programmer Join Date: Feb 2005 Posts: 54 Rep Power: 4	You are not going to get better if you don't try. I wrote the program, it's not too hard. Try it and post any problems you are having. I will start you off: (Toggle Plain Text) pernum = '8812210759' for digit in pernum: print digit pernum = '8812210759' for digit in pernum: print digit You might also want to check out the int() and str() functions.

May 3rd, 2005, 8:47 AM	#7
lingon Newbie Join Date: Apr 2005 Posts: 17 Rep Power: 0	Okej, so now it splits it into 9 different numbers but it doesn't understand that they are actually numbers. Ex. if you print "print digit*2" it prints 88 instead of 16 and 22 instead of 4. So how do I make it understand that it is numbers not letters? I tryed some different int() things but they didn't work

May 3rd, 2005, 9:02 AM	#8
Moldz Programmer Join Date: Feb 2005 Posts: 54 Rep Power: 4	Here's what I did in the python console: (Toggle Plain Text) >>> digit = "5" >>> type(digit) <type 'str'> >>> number = int(digit) >>> type(number) <type 'int'> >>> digit = "5" >>> type(digit) <type 'str'> >>> number = int(digit) >>> type(number) <type 'int'> That should help.

May 8th, 2005, 11:41 AM	#9
lingon Newbie Join Date: Apr 2005 Posts: 17 Rep Power: 0	Okej, thanks. I'll see if I can make it work

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Programming Forums > Script Programming > Python

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