Programming Forums > Application Development > C++

colt · Mar 23rd, 2005, 3:56 PM

Hello, I am writing this program whose function is to insert coins into a machine and I don't know how to perform this actions:

(Toggle Plain Text)

#include <stdio.h>  
main () 
{   
   int coins, i, result;   
   for (i=1; i<=1000; i++)    
   {        
        printf ("Print 5 to insert a coin of 5 cents, 10 for the 10 cents coin, 25 for the 25cents, 50 for the 50cents, 100 for the 1 peso and -1 to close the process of insert coins: \n ");         
        if  (coins==-1)         
        break;        
        scanf  ("%d", &coins);      
   }    
   result=coins;    
   printf ("The total money put in the machine is:%d", result); }

1) I am using the "if (coins==-1)" followed for the break statement to interrupt my coin loop, but if I do that, my program will store -1 in the coin variable and print the total money as -1, instead of previously supplying to me the result of the addition of the values of the inserted coins.

2)Even if I use a loop with like this "for=1; i<=5; i++" and didn't use "if coins==-1", as in this case I would not need to interrupt the loop before it's end, I still don't get the correct value of the "total money" because at each loop interaction the coin that I insert in the machine overwrite the previous value.

So what I need to know is how to use correctly the "if (coins==-1) to interrupt my semi-infinite loop of 1000 interactions at any point, and then print on the screen the correct total amount of money that I inserted in the machine throught a insertion of several coins, using something that could be this: "result= coin1(50 cents) + coin2 (25 cents) + coin 3 (100 cents) + coin 4 (5 cents).....until a x limit that is changeable at each time. Summarizing, I must know how to add the values of a changeable amount of currencies to get the total inserted money in the machine.

Thanks for the help.

spydoor · Mar 23rd, 2005, 4:40 PM

You just need to change the order you are doing things.

If you do this -1 will not get added to result because you break before the addition

pseudo code

(Toggle Plain Text)

printf
scanf
if(coins == -1) break;
result = result + coins;

I don't quite understand your 2nd issue

to display details of what was entered I'd keep a counter of each coin type and increment as you go
int dime;
dime++

then your output can be something like
total: $1.23
3 quarter
4 dimes
1 nickles
3 pennies

Berto · Mar 24th, 2005, 2:19 AM

(Toggle Plain Text)

switch(coin){
      case 1:
           cent+;+;
           break
      case 10:
          dime++;
          break;
      case 25:
          quater++;
          break;
}

Mar 23rd, 2005, 3:56 PM	#1
colt Newbie Join Date: Mar 2005 Posts: 7 Rep Power: 0	2 problems Hello, I am writing this program whose function is to insert coins into a machine and I don't know how to perform this actions: (Toggle Plain Text) #include <stdio.h> main () { int coins, i, result; for (i=1; i<=1000; i++) { printf ("Print 5 to insert a coin of 5 cents, 10 for the 10 cents coin, 25 for the 25cents, 50 for the 50cents, 100 for the 1 peso and -1 to close the process of insert coins: \n "); if (coins==-1) break; scanf ("%d", &coins); } result=coins; printf ("The total money put in the machine is:%d", result); } #include <stdio.h> main () { int coins, i, result; for (i=1; i<=1000; i++) { printf ("Print 5 to insert a coin of 5 cents, 10 for the 10 cents coin, 25 for the 25cents, 50 for the 50cents, 100 for the 1 peso and -1 to close the process of insert coins: \n "); if (coins==-1) break; scanf ("%d", &coins); } result=coins; printf ("The total money put in the machine is:%d", result); } 1) I am using the "if (coins==-1)" followed for the break statement to interrupt my coin loop, but if I do that, my program will store -1 in the coin variable and print the total money as -1, instead of previously supplying to me the result of the addition of the values of the inserted coins. 2)Even if I use a loop with like this "for=1; i<=5; i++" and didn't use "if coins==-1", as in this case I would not need to interrupt the loop before it's end, I still don't get the correct value of the "total money" because at each loop interaction the coin that I insert in the machine overwrite the previous value. So what I need to know is how to use correctly the "if (coins==-1) to interrupt my semi-infinite loop of 1000 interactions at any point, and then print on the screen the correct total amount of money that I inserted in the machine throught a insertion of several coins, using something that could be this: "result= coin1(50 cents) + coin2 (25 cents) + coin 3 (100 cents) + coin 4 (5 cents).....until a x limit that is changeable at each time. Summarizing, I must know how to add the values of a changeable amount of currencies to get the total inserted money in the machine. Thanks for the help.

Mar 23rd, 2005, 4:40 PM	#2
spydoor Programmer Join Date: Feb 2005 Posts: 64 Rep Power: 4	You just need to change the order you are doing things. If you do this -1 will not get added to result because you break before the addition pseudo code (Toggle Plain Text) printf scanf if(coins == -1) break; result = result + coins; printf scanf if(coins == -1) break; result = result + coins; I don't quite understand your 2nd issue to display details of what was entered I'd keep a counter of each coin type and increment as you go int dime; dime++ then your output can be something like total: $1.23 3 quarter 4 dimes 1 nickles 3 pennies Last edited by spydoor; Mar 23rd, 2005 at 4:43 PM.

Mar 24th, 2005, 2:19 AM	#3
Berto Programming Guru Join Date: Aug 2004 Posts: 1,022 Rep Power: 6	(Toggle Plain Text) switch(coin){ case 1: cent+;+; break case 10: dime++; break; case 25: quater++; break; } switch(coin){ case 1: cent+;+; break case 10: dime++; break; case 25: quater++; break; }

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Programming Forums > Application Development > C++

2 problems