Programming Forums > Application Development > Java

Tazz_Mission_13 · Mar 11th, 2005, 4:27 PM

Hello,

I was wondering if someone can help me figure out the issue that I cannot seem to get around. I have been attempting to convert a 1-Dimensional array to a 2-Dimensional array (also called a matrix), but just cannot figure out how to do it. Here are the parameters:

--- I have a 1-Dimensional array of characters that has length 36,
called array1. The array is:
abcdefghijklmnopqrstuvwxyz0123456789

--- The 2-Dimensional array, called matrix, is 6x6, so it is square and can
hold all the 36 characters from array1.

What I want to do is convert the array1 to matrix starting with the upper right corner. An example of this would be:

(Toggle Plain Text)

              a  ---->    ba  ---->    dba   --->    gdba
                           c            ec            hec
                                         f             if

and so on untill all 36 characters are inserted into the matrix.

If anyone can help me I would really appreciate it.

Thankz,

Tazz

Tazz_Mission_13 · Mar 12th, 2005, 11:41 PM

I got the solution my self

Xero · Mar 13th, 2005, 12:18 AM

Glad you found it...

Shouldn't have been that bad

nanoh2001 · Apr 4th, 2005, 8:27 AM

hi,,,

can u write the sulution pleaze??

Childe Roland · Apr 4th, 2005, 3:23 PM

i think i would of attempted it using nested for loops but I would like to see how someone else would do it if anybody would like to post the code for it

nanoh2001 · Apr 5th, 2005, 2:37 PM

pllllz put the code i need it nessesary ... for the assigment plazzz

xavier · Apr 8th, 2005, 11:58 AM

I know, i'm slow .. but i haven't got the time to think about it. Here it is:

(Toggle Plain Text)

import java.io.*;

class matrix {
	public static void main(String args[]){
		BufferedReader in=new BufferedReader(new InputStreamReader(System.in));
		
                int n=3;


		int a[][]=new int[3][3];
		int i=0;  //row
		int j=0;  //colomn
		int step=1; // used when under the main diagonal
		int pas=0;  // used when above the main diagonal
		

		for(;;){
			if(pas<=n-1){
				i=0;
				j=n-1-pas;

				do{
					try{
						String s=in.readLine();
						int x=Integer.parseInt(s);
                               //see if the index is working
						System.out.println("i="+i+" "+"j="+j);

						a[i][j]=x;
						i++;
						j++;
						}
					catch(IOException e){e.printStackTrace();}
				}while(i<=pas);
				pas++;
			}

			if(pas>n-1){
				i=step;
				j=0;

				do{
					try{
						String s=in.readLine();
						int x=Integer.parseInt(s);
                               //see if the index is working
					System.out.println("i="+i+" "+"j="+j);
					a[i][j]=x;
					i++;
					j++;

					}catch(IOException e){e.printStackTrace();}
				}while(i<=n-1);
				step++;
			}
		if((step>n-1))break;
		}
//see if it worked :)
	for(i=0;i<n;i++){
		for(j=0;j<n;j++){
			System.out.print(a[i][j]);}
	System.out.println();}
}
}

Mar 11th, 2005, 4:27 PM	#1
Tazz_Mission_13 Newbie Join Date: Mar 2005 Posts: 2 Rep Power: 0	Converting 1-dimensional array to 2-dimensional array Hello, I was wondering if someone can help me figure out the issue that I cannot seem to get around. I have been attempting to convert a 1-Dimensional array to a 2-Dimensional array (also called a matrix), but just cannot figure out how to do it. Here are the parameters: --- I have a 1-Dimensional array of characters that has length 36, called array1. The array is: abcdefghijklmnopqrstuvwxyz0123456789 --- The 2-Dimensional array, called matrix, is 6x6, so it is square and can hold all the 36 characters from array1. What I want to do is convert the array1 to matrix starting with the upper right corner. An example of this would be: (Toggle Plain Text) a ----> ba ----> dba ---> gdba c ec hec f if a ----> ba ----> dba ---> gdba c ec hec f if and so on untill all 36 characters are inserted into the matrix. If anyone can help me I would really appreciate it. Thankz, Tazz Last edited by Tazz_Mission_13; Mar 11th, 2005 at 4:30 PM.

Mar 12th, 2005, 11:41 PM	#2
Tazz_Mission_13 Newbie Join Date: Mar 2005 Posts: 2 Rep Power: 0	[solved] I got the solution my self

Mar 13th, 2005, 12:18 AM	#3
Xero Hobbyist Programmer Join Date: Dec 2004 Location: a cardboard box Posts: 118 Rep Power: 4	Glad you found it... Shouldn't have been that bad __________________ ...

Apr 8th, 2005, 11:58 AM	#7
xavier Professional Programmer Join Date: Oct 2004 Location: .ro Posts: 370 Rep Power: 4	I know, i'm slow .. but i haven't got the time to think about it. Here it is: (Toggle Plain Text) import java.io.; class matrix { public static void main(String args[]){ BufferedReader in=new BufferedReader(new InputStreamReader(System.in)); int n=3; int a[][]=new int[3][3]; int i=0; //row int j=0; //colomn int step=1; // used when under the main diagonal int pas=0; // used when above the main diagonal for(;;){ if(pas<=n-1){ i=0; j=n-1-pas; do{ try{ String s=in.readLine(); int x=Integer.parseInt(s); //see if the index is working System.out.println("i="+i+" "+"j="+j); a[i][j]=x; i++; j++; } catch(IOException e){e.printStackTrace();} }while(i<=pas); pas++; } if(pas>n-1){ i=step; j=0; do{ try{ String s=in.readLine(); int x=Integer.parseInt(s); //see if the index is working System.out.println("i="+i+" "+"j="+j); a[i][j]=x; i++; j++; }catch(IOException e){e.printStackTrace();} }while(i<=n-1); step++; } if((step>n-1))break; } //see if it worked :) for(i=0;i<n;i++){ for(j=0;j<n;j++){ System.out.print(a[i][j]);} System.out.println();} } } import java.io.; class matrix { public static void main(String args[]){ BufferedReader in=new BufferedReader(new InputStreamReader(System.in)); int n=3; int a[][]=new int[3][3]; int i=0; //row int j=0; //colomn int step=1; // used when under the main diagonal int pas=0; // used when above the main diagonal for(;;){ if(pas<=n-1){ i=0; j=n-1-pas; do{ try{ String s=in.readLine(); int x=Integer.parseInt(s); //see if the index is working System.out.println("i="+i+" "+"j="+j); a[i][j]=x; i++; j++; } catch(IOException e){e.printStackTrace();} }while(i<=pas); pas++; } if(pas>n-1){ i=step; j=0; do{ try{ String s=in.readLine(); int x=Integer.parseInt(s); //see if the index is working System.out.println("i="+i+" "+"j="+j); a[i][j]=x; i++; j++; }catch(IOException e){e.printStackTrace();} }while(i<=n-1); step++; } if((step>n-1))break; } //see if it worked :) for(i=0;i<n;i++){ for(j=0;j<n;j++){ System.out.print(a[i][j]);} System.out.println();} } } __________________ Don't take life too seriously, it's not permanent !

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Apr 4th, 2005, 8:27 AM	#4
nanoh2001 Newbie Join Date: Apr 2005 Posts: 5 Rep Power: 0	hi,,, can u write the sulution pleaze??

Apr 4th, 2005, 3:23 PM	#5
Childe Roland Newbie Join Date: Mar 2005 Posts: 17 Rep Power: 0	i think i would of attempted it using nested for loops but I would like to see how someone else would do it if anybody would like to post the code for it

Apr 5th, 2005, 2:37 PM	#6
nanoh2001 Newbie Join Date: Apr 2005 Posts: 5 Rep Power: 0	pllllz put the code i need it nessesary ... for the assigment plazzz

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Programming Forums > Application Development > Java

Converting 1-dimensional array to 2-dimensional array