Polaris

Hello every one,

I am stuck with the following problem, it's the course final assignment of my 'structured programming' course at the univerisity. I'm student of EEE, and therefor I'm not much into programming... I know it's cheating, but I would really be thankful if some can kindly solve the problem for me, I really don't want to get a double zero :o

Here's the problem, and it should be solved with C (no C++):

Write a program to dispense change.The user enters the amount paid and the amount due. The program determines how many dollars, 50cents, 20cents, 10cents should be given as change.

a) write a function with the heading:
void dispense(int change,int *dollars,int *c10,int *c20,int *c50) that determines and return the quantity of each kind of coin.
(Note:16 cents-5 cents=11 cents meaning that one 10cents is returned
for charge.However 16 cents-1 cents=15 cents meaning that one 20-cents
is required(round-up))

b) write a function int getData(int *paid,int *due) that doe the following:

inform the user that amount paid and amount due should be entered in
cents(integer)
do
prompt the user to enter the amount paid and amount due
read in the data
while (amount due<0 or amount paid<amount due);
if both amount paid and amount due are zeros
return 0
otherwise
return 1

following until both the amount paid and amount due are zeros.

1.call the function getData to ask for the amount paid and amount due
2.print out the charge and the # of each kind of coins to dispense.

Program output:

The amount-paid and amount-due should be entered in cents (integer)
To terminate the program,enter 0 for both values
Enter the amount paid and amount due please:16 5
amount due:5,amount paid:16,and thus change=11
You are suggested to give him/her 1 10-cents coin(s)

The amount-paid and amount-due should be entered in cents (integer)
To terminate the program,enter 0 for both values
Enter the amount paid and amount due please:26 5
amount due:5,amount paid:26,and thus change=21
You are suggested to give him/her 1 20-cents coin(s)

The amount-paid and amount-due should be entered in cents (integer)
To terminate the program,enter 0 for both values
Enter the amount paid and amount due please:66 5
amount due:5,amount paid:66,and thus change=61
You are suggested to give him/her 1 50-cents coin(s) 1 10-cents coin(s)

The amount-paid and amount-due should be entered in cents (integer)
To terminate the program,enter 0 for both values
Enter the amount paid and amount due please:81 5
amount due:5,amount paid:81,and thus change=76
You are suggested to give him/her 1 50-cents coin(s) 1 20-cents
coin(s) 1 10-cents coin(s)

The amount-paid and amount-due should be entered in cents (integer)
To terminate the program,enter 0 for both values
Enter the amount paid and amount due please:5 81
Enter the amount paid and amount due please:0 0

tempest

Shit, i actually had this program already done... let me fumble around with some floppies and see if i can find it.

__________________

Polaris

Oops, I posted on the wrong forum! Sorry guys! Actually I'm too tensed about the grade... I've got to study for three other subjects! I hate school!

tempest, it would be great if you can help... my address is rimina1985@yahoo.com. Thanks in advanced.

Ooble

Post it here too - I'm curious.

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Mjordan2nd

~moved

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&quot;Every gun that is made, every warship launched, every rocket signifies, in the final sense, a theft from those who hunger and are not fed, from those who are cold and are not clothed. The world in arms is not spending money alone. It is spending the sweat of its laborers, the genius of its scientists, the hopes of its children.&quot; - Dwight D. Eisenhower

Polaris

Here's what I wrote. Not to mention, this doesn't work :(

#include <stdio.h>

int getData(int *paid,int *due){
printf ("\nThe amount-paid and amount-due should be entered in cents(integer)");
do {
printf ("\nTo terminate the program,enter 0 for both values");
printf ("\nEnter the amount-paid and amount-due please:");
scanf ("%d %d",&paid,&due); } while (due<0||paid<due);
if (paid==0&&due==0)
return 0;
else return 1;}

void dispense(int change,int *dollars,int *c10,int *c20,int *c50){
dollars=round(paid-due);
change=dollars/10;
while (change>=1&&change<=9){
switch (change) {
case '1' :c10+=1;
break;

case '2' :c20+=1;
break;

case '3' :c10+=1;
c20+=1;
break;

case '4' :c20+=2;
break;

case '5' :c50+=1;
break;

case '6' :c10+=1;
c50+=1;
break;

case '7' :c20+=1;
c50+=1;
break;

case '8' :c10+=1;
c20+=1;
c50+=1;
break;

case '9' :c20+=2;
c50+=1;
break;

default:printf ("\nCheck your input!");
printf ("\nEnter the amount-paid and amount-due please:");
}
}


int main ()

{
do {
getData();} while getData==1;

dispense();
printf ("\namount due:%d",due);
printf ("amount paid:%d",paid);
printf ("and thus change=%d",change);

if (change<5) {
if (c20==0){
printf ("You are suggested to give him/her %d 10-cents coin(s)",c10);}
if (c10==0){
printf ("You are suggested to give him/her %d 20-cents coin(s)",c20);}
else
printf ("You are suggested to give him/her %d 10-cents coin(s) %d 20-cents coiu(s)",c10,c20);}

else if (change>5) {
if (c10==0){
printf ("You are suggested to give him/her %d 20-cents coin(s) %d 50-cents coin(s)",c20,c50);}
if (c20==0){
printf ("You are suggested to give him/her %d 10-cents coin(s) %d 50-cents coin(s)",c10,c50);}
else
printf ("You are suggested to give him/her %d 10-cents coin(s) %d 20-cents coin(s) %d 50-cents coin(s)",c10,c20,c50);}

else if (change==5) {
printf ("You are suggested to give him/her %d 50-cents coin(s)",c50);}


}
}

Please help me!

RemoteC2

here is what i got, but the source is in c++ (sorry )


sorry that it is not exactly how you wanted your program to be, but i will work on it so that it will be =)

RemoteC2

lol it only took 540 days to get an answer lol

DaWei

540 days to break the forum's rules regarding homework? Wonderful. You must be very proud. Since it's fucked up, you must be doubly proud. Since it appears many times on every C/C++ forum that ever existed, you must be triply proud. Now, if you'll excuse me, I need to go sniff my ass and puke in my shirt pocket.

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