Programming Forums > Application Development > C#

gencor45 · Feb 8th, 2005, 12:02 PM

Today, 12:51 PM Any help would be appreciated!
Im new to C# and im going crazy trying to figure out a simple way to create a 4-digit non-repeating random number for a number guessing game. If anyone can help with the code I already have I would be grateful.

Heres what I have:

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Code:
private void form1_Load(object sender, System.EventArgs e)
        {
string answer;
            
//Creates random number array

String[] myNumbers={"0","1","2","3","4","5","6","7","8","9"};
Random rndNumbers=new Random();

I dont know what kind of loop make from here, and then I dont understand how to put the random number into a string

Please help

Dizzutch · Feb 8th, 2005, 12:41 PM

check if the random number generated has already been generated, if so generate a new one, if not, use it.

good luck

Dizz

bobc · Feb 9th, 2005, 12:11 AM

Here is a simple one using a form, a label, and a button to generate the random number (4 digits padded with zero's).

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private void button1_Click(object sender, System.EventArgs e)
		{
			Random rnd = new Random();
			int rndNumber = rnd.Next(9999);
			label1.Text = rndNumber.ToString("0000");
		}

If you want to make sure there are no duplicate numbers, you must put each generated number in an array or array list. Every time you click the button you must loop through the generated numbers and compare them to the newly generated number. If there is a duplicate number you must generate another until it is unique.

Hope this helps.
bobc

Feb 8th, 2005, 12:02 PM	#1
gencor45 Newbie Join Date: Feb 2005 Posts: 20 Rep Power: 0	non repeating random number generation Today, 12:51 PM Any help would be appreciated! Im new to C# and im going crazy trying to figure out a simple way to create a 4-digit non-repeating random number for a number guessing game. If anyone can help with the code I already have I would be grateful. Heres what I have: (Toggle Plain Text) Code: private void form1_Load(object sender, System.EventArgs e) { string answer; //Creates random number array String[] myNumbers={"0","1","2","3","4","5","6","7","8","9"}; Random rndNumbers=new Random(); Code: private void form1_Load(object sender, System.EventArgs e) { string answer; //Creates random number array String[] myNumbers={"0","1","2","3","4","5","6","7","8","9"}; Random rndNumbers=new Random(); I dont know what kind of loop make from here, and then I dont understand how to put the random number into a string Please help

Feb 8th, 2005, 12:41 PM	#2
Dizzutch Professional Programmer Join Date: Dec 2004 Location: Worcester, MA Posts: 441 Rep Power: 4	check if the random number generated has already been generated, if so generate a new one, if not, use it. good luck Dizz __________________ naked pictures of you \| PFO F@H stats

Feb 9th, 2005, 12:11 AM	#3
bobc Newbie Join Date: Feb 2005 Posts: 16 Rep Power: 0	Here is a simple one using a form, a label, and a button to generate the random number (4 digits padded with zero's). (Toggle Plain Text) private void button1_Click(object sender, System.EventArgs e) { Random rnd = new Random(); int rndNumber = rnd.Next(9999); label1.Text = rndNumber.ToString("0000"); } private void button1_Click(object sender, System.EventArgs e) { Random rnd = new Random(); int rndNumber = rnd.Next(9999); label1.Text = rndNumber.ToString("0000"); } If you want to make sure there are no duplicate numbers, you must put each generated number in an array or array list. Every time you click the button you must loop through the generated numbers and compare them to the newly generated number. If there is a duplicate number you must generate another until it is unique. Hope this helps. bobc

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Programming Forums > Application Development > C#

non repeating random number generation