shinni

Hi .. I am a new bie in writing scripts, so this doubt may be a simple one.

I am trying to apply a parsing program to a set of input files in a directoy.
How can i access all the files from a source directory , one by one and to write the
output files with another name to some directory ? i.e
my exe file is a.out
I have input files 1.txt,2.txt .. in one directory.
I need this cmd line ./a.out <inputfilename> > <outputfilename> , on all input files.

can i write a loop to get all files like this ? right now i am writing the same line
again and again to apply to all files..

Plz post ur suggestions.

Thank u

Shinni

Infinite Recursion

in your script, have ls -lstr > file

then have a while loop that gets fed file

inside the while loop...

assign a variable to the 10th position in that file (the filename of the current file in your dir) - you can do this with awk

then, still in the loop, call your a.out $curFile > newFile

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shinni

Thank u .. I had posted this doubt at one more forum n i got the following steps also..
This also works.

#!/bin/bash
cd <input_file_directory>
for file in `dir -d *` ; do
<exeFile with full path> "$file" <output_file_path/"$file".out>
done

I have another doubt , as a follow up .. If i need to change this input directory and output directory to test different data sets, what should i do ? Now, i hav specified SourceDir and DestDir within the program. Can i pass command line arguements or soemthing like that to assign some path to variables representing the directories ?

Thank u

Shinni

Infinite Recursion

yes, parameters will work fine.

$0 = program name
$1 = 1st parameter
$2 = 2nd parameter

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http://jasonpowers.net

"There are a thousand hacking at the branches of evil to one who is striking at the root."

magyarkid

Yeah... that will work if you want to run
Then you just use $1 and $2 to reffer to infilename and outfilename, respectively.

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Magyarkid