Programming Forums > Application Development > C#

theflamer14 · Apr 2nd, 2008, 7:43 PM

Hi,

For the past few weeks, I've been working on a racing game using directx. My vehicle driving and acceleration are good, however, I'm having a little trouble with the camera movements(the cam is placed behind my vehicle). I'm trying to position the camera so that when turning my vehicle, the camera should still be behind the vehicle, and the vehicle still remains to be the camera target, thereby only changing the yaw of the camera. I've been trying to come up with a solution to this for a few days now. But I'm still unsure of what to do. Any help is appreciated. Thanks in advance!

BstrucT · Apr 3rd, 2008, 12:31 AM

Are you using XNA Game Studio to develop your game?

lectricpharaoh · Apr 3rd, 2008, 1:59 AM

I don't know if this will help, but here's a .NET Managed DirectX resource.

BstrucT · Apr 3rd, 2008, 3:17 AM

Thanks for the link lectricpharaoh!

Was looking for something like that myself but couldn't find anything decent.

>BstrucT

theflamer14 · Apr 3rd, 2008, 11:38 AM

Thank you for trying to help, but I have gone through every single one of these tutorials for DirectX. If I get the camera rotations for the car, then my problem will be solved. The site provided above does not have any tutorials on camera movements, but only how to set it up. I'm looking for a certain formula(s) for the camera position.

OpenLoop · Apr 3rd, 2008, 11:51 AM

You need to multiply the camera position vector with the same quaternion you used to rotate the car. Reimers's tutorials should have some insight about this.

http://www.riemers.net/eng/Tutorials...rp/series2.php

theflamer14 · Apr 3rd, 2008, 5:41 PM

Thanks for helping everyone. Although I didn't use quaternions, I got it! This is what it looks like after I modified it:

(Toggle Plain Text)

            cameraPosition = new Vector3(Racer.vehiclePosition.X, 1f, Racer.vehiclePosition.Z);
            cameraPosition.X -= (float)(Math.Sin(Racer.angle)) * 2f;
            cameraPosition.Z -= (float)(Math.Cos(Racer.angle)) * 2f;


            cameraTarget = cameraPosition;

            cameraTarget.X += (float)Math.Sin(Racer.angle) * 0.5f;
            cameraTarget.Y += (float)Math.Sin(_pitch) * 0.5f;
            cameraTarget.Z += (float)Math.Cos(Racer.angle) * 0.5f;

This code is from my camera.cs, and "Racer" is my main form with the rendering, and "angle" is increased by a certain amount every time Left/Right is pressed. It looks really good! Thanks for trying to help once again.

Apr 2nd, 2008, 7:43 PM	#1
theflamer14 13 Year Old Join Date: Jan 2008 Location: Toronto Posts: 11 Rep Power: 0	Directx 3D Racing Game Hi, For the past few weeks, I've been working on a racing game using directx. My vehicle driving and acceleration are good, however, I'm having a little trouble with the camera movements(the cam is placed behind my vehicle). I'm trying to position the camera so that when turning my vehicle, the camera should still be behind the vehicle, and the vehicle still remains to be the camera target, thereby only changing the yaw of the camera. I've been trying to come up with a solution to this for a few days now. But I'm still unsure of what to do. Any help is appreciated. Thanks in advance!

Apr 3rd, 2008, 12:31 AM	#2
BstrucT Hobbyist Programmer Join Date: Dec 2007 Location: Durban, South-Africa Posts: 134 Rep Power: 1	Re: Directx 3D Racing Game Are you using XNA Game Studio to develop your game? __________________ >BstrucT

Apr 3rd, 2008, 1:59 AM	#3
lectricpharaoh Caffeinated Neural Net Join Date: Jun 2005 Location: Dry west coast of Canada Posts: 927 Rep Power: 4	Re: Directx 3D Racing Game I don't know if this will help, but here's a .NET Managed DirectX resource. __________________ A man's knowledge is like an expanding sphere, the surface corresponding to the boundary between the known and the unknown. As the sphere grows, so does its surface; the more a man learns, the more he realizes how much he does not know. Hence, the most ignorant man thinks he knows it all. - L. Sprague de Camp

Apr 3rd, 2008, 3:17 AM	#4
BstrucT Hobbyist Programmer Join Date: Dec 2007 Location: Durban, South-Africa Posts: 134 Rep Power: 1	Re: Directx 3D Racing Game Thanks for the link lectricpharaoh! Was looking for something like that myself but couldn't find anything decent. >BstrucT __________________ >BstrucT

Apr 3rd, 2008, 11:38 AM	#5
theflamer14 13 Year Old Join Date: Jan 2008 Location: Toronto Posts: 11 Rep Power: 0	Re: Directx 3D Racing Game Thank you for trying to help, but I have gone through every single one of these tutorials for DirectX. If I get the camera rotations for the car, then my problem will be solved. The site provided above does not have any tutorials on camera movements, but only how to set it up. I'm looking for a certain formula(s) for the camera position.

Apr 3rd, 2008, 11:51 AM	#6
OpenLoop Expert Programmer Join Date: May 2005 Location: East Lansing, MI Posts: 663 Rep Power: 4	Re: Directx 3D Racing Game You need to multiply the camera position vector with the same quaternion you used to rotate the car. Reimers's tutorials should have some insight about this. http://www.riemers.net/eng/Tutorials...rp/series2.php

Apr 3rd, 2008, 5:41 PM	#7
theflamer14 13 Year Old Join Date: Jan 2008 Location: Toronto Posts: 11 Rep Power: 0	Re: Directx 3D Racing Game Thanks for helping everyone. Although I didn't use quaternions, I got it! This is what it looks like after I modified it: (Toggle Plain Text) cameraPosition = new Vector3(Racer.vehiclePosition.X, 1f, Racer.vehiclePosition.Z); cameraPosition.X -= (float)(Math.Sin(Racer.angle)) * 2f; cameraPosition.Z -= (float)(Math.Cos(Racer.angle)) * 2f; cameraTarget = cameraPosition; cameraTarget.X += (float)Math.Sin(Racer.angle) * 0.5f; cameraTarget.Y += (float)Math.Sin(_pitch) * 0.5f; cameraTarget.Z += (float)Math.Cos(Racer.angle) * 0.5f; cameraPosition = new Vector3(Racer.vehiclePosition.X, 1f, Racer.vehiclePosition.Z); cameraPosition.X -= (float)(Math.Sin(Racer.angle)) * 2f; cameraPosition.Z -= (float)(Math.Cos(Racer.angle)) * 2f; cameraTarget = cameraPosition; cameraTarget.X += (float)Math.Sin(Racer.angle) * 0.5f; cameraTarget.Y += (float)Math.Sin(_pitch) * 0.5f; cameraTarget.Z += (float)Math.Cos(Racer.angle) * 0.5f; This code is from my camera.cs, and "Racer" is my main form with the rendering, and "angle" is increased by a certain amount every time Left/Right is pressed. It looks really good! Thanks for trying to help once again.

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Programming Forums > Application Development > C#

Directx 3D Racing Game