Programming Forums > Web Development and Design > PHP

Kelvoron · Nov 29th, 2007, 8:32 PM

thanks every one i will look up the fetch function tonight at work

Sane · Nov 29th, 2007, 9:03 PM

Quote:

Originally Posted by pegasus001

The $host variable is a string by itself, try removing the double quotes.

Just a thought, though.

In PHP, double quotes are parsed for variable names.

(Toggle Plain Text)

$name = 'PFO';

// Outputs: PFO
echo $name;

// Outputs: PFO
echo "$name";

// Outputs: Hello PFO
echo "Hello $name";

// Outputs: Hello $name
echo 'Hello $name';

So you were correct in a way, since the double quotes are completely pointless. $host is the exact same as "$host".

MiKuS · Nov 29th, 2007, 9:46 PM

I suggest working with this tutorial so you understand the basics of database functionality
http://www.phpfreaks.com/tutorials/142/0.php

 php Syntax (Toggle Plain Text) 
$dbhost = 'localhost';
$dbuser = 'your_user';
$dbpass = 'user_password';
$conn = mysql_connect($dbhost, $dbuser, $dbpass);
mysql_select_db('your_database');
 
$sql="SELECT name FROM ".$table_name."WHERE gender='male'";
$retval = mysql_query($sql, $conn );
if (! $retval ) {
    print_r($sql);
    die('Could not get data: ' . mysql_error());
}
if ($row = mysql_fetch_array($retval, MYSQL_ASSOC)) {
    echo "<h1>{$row['gender']}</h1> ";
}
$dbhost = 'localhost';
$dbuser = 'your_user';
$dbpass = 'user_password';
$conn = mysql_connect($dbhost, $dbuser, $dbpass);
mysql_select_db('your_database');

$sql="SELECT name FROM ".$table_name."WHERE gender='male'";
$retval = mysql_query($sql, $conn );
if (! $retval ) {
    print_r($sql);
    die('Could not get data: ' . mysql_error());
}
if ($row = mysql_fetch_array($retval, MYSQL_ASSOC)) {
    echo "<h1>{$row['gender']}</h1> ";
}

I haven't checked the above code but it should work.

09jyoung · Dec 2nd, 2007, 10:21 PM

here's what your SELECT statement should look like:
$sql = "SELECT name FROM " . $table_name . " WHERE gender='male';";

Sane · Dec 2nd, 2007, 11:11 PM

09jyoung... his select statement was fine. Read before posting. Discussion over.

FireflyX · Dec 4th, 2007, 3:54 PM

(Toggle Plain Text)

<?
$host="localhost";
$username="----------";
$password="*******";
$db_name="kelvoron_testscripts";
$table_name="test1";

mysql_connect("$host", "$username", "$password")or die("cannot connect"); 
mysql_select_db("$db_name")or die("cannot select DB");

$sql="SELECT * FROM $tabLE_name WHERE gender='male'";
$result=mysql_query($sql);

while ($row = mysql_fetch_array($result)){

echo $row['name'];

}

mysql_close();
?>

Ok above is what i believe to be the simplest way to what you are trying to achieve. I changed SELECT name FROM to just SELECT * FROM because as you can see i am only selecting the name row. If you needed to output any other rows like you wanted to display the name then the gender you could put

(Toggle Plain Text)

echo $row['name']." - ".$row['gender'];

Hope that cleared things up a bit. I recommend reading here for further info http://www.tizag.com/mysqlTutorial/mysqlfetcharray.php

Nov 29th, 2007, 8:32 PM	#11
Kelvoron Programmer Join Date: Aug 2007 Location: Ohio Posts: 46 Rep Power: 0	Re: SELECT statement thanks every one i will look up the fetch function tonight at work __________________ Good better best, never let it rest, untill your good is better and your better is the best.

Nov 29th, 2007, 9:46 PM	#13
MiKuS Programmer Join Date: Jun 2007 Posts: 93 Rep Power: 2	Re: SELECT statement I suggest working with this tutorial so you understand the basics of database functionality http://www.phpfreaks.com/tutorials/142/0.php php Syntax (Toggle Plain Text) $dbhost = 'localhost'; $dbuser = 'your_user'; $dbpass = 'user_password'; $conn = mysql_connect($dbhost, $dbuser, $dbpass); mysql_select_db('your_database'); $sql="SELECT name FROM ".$table_name."WHERE gender='male'"; $retval = mysql_query($sql, $conn ); if (! $retval ) { print_r($sql); die('Could not get data: ' . mysql_error()); } if ($row = mysql_fetch_array($retval, MYSQL_ASSOC)) { echo "<h1>{$row['gender']}</h1> "; } $dbhost = 'localhost'; $dbuser = 'your_user'; $dbpass = 'user_password'; $conn = mysql_connect($dbhost, $dbuser, $dbpass); mysql_select_db('your_database'); $sql="SELECT name FROM ".$table_name."WHERE gender='male'"; $retval = mysql_query($sql, $conn ); if (! $retval ) { print_r($sql); die('Could not get data: ' . mysql_error()); } if ($row = mysql_fetch_array($retval, MYSQL_ASSOC)) { echo "<h1>{$row['gender']}</h1> "; } I haven't checked the above code but it should work.

Dec 2nd, 2007, 10:21 PM	#14
09jyoung codemaniac Join Date: Dec 2007 Posts: 9 Rep Power: 0	Re: SELECT statement here's what your SELECT statement should look like: $sql = "SELECT name FROM " . $table_name . " WHERE gender='male';";

Dec 2nd, 2007, 11:11 PM	#15
Sane Programming Guru Join Date: Apr 2005 Posts: 1,799 Rep Power: 5	Re: SELECT statement 09jyoung... his select statement was fine. Read before posting. Discussion over.

Dec 4th, 2007, 3:54 PM	#16
FireflyX PHP God Join Date: Nov 2007 Location: Stockton, England Posts: 15 Rep Power: 0	Re: SELECT statement (Toggle Plain Text) <? $host="localhost"; $username="----------"; $password="******"; $db_name="kelvoron_testscripts"; $table_name="test1"; mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $sql="SELECT FROM $tabLE_name WHERE gender='male'"; $result=mysql_query($sql); while ($row = mysql_fetch_array($result)){ echo $row['name']; } mysql_close(); ?> <? $host="localhost"; $username="----------"; $password="******"; $db_name="kelvoron_testscripts"; $table_name="test1"; mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $sql="SELECT FROM $tabLE_name WHERE gender='male'"; $result=mysql_query($sql); while ($row = mysql_fetch_array($result)){ echo $row['name']; } mysql_close(); ?> Ok above is what i believe to be the simplest way to what you are trying to achieve. I changed SELECT name FROM to just SELECT * FROM because as you can see i am only selecting the name row. If you needed to output any other rows like you wanted to display the name then the gender you could put (Toggle Plain Text) echo $row['name']." - ".$row['gender']; echo $row['name']." - ".$row['gender']; Hope that cleared things up a bit. I recommend reading here for further info http://www.tizag.com/mysqlTutorial/mysqlfetcharray.php __________________ mysql_query("DELETE chavs FROM earth") or die("chavs");

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