Programming Forums > Application Development > C++

Simplesouljah · Oct 28th, 2007, 7:00 PM

Quote:

Originally Posted by DaWei

How so? We can see your statements, but you haven't explained how the charges are supposed to be calculated. Have you tested to see that your input is correct? (I can see you haven't tested the input for failure, which is a bad thing to skip.) Have you worked your formulae by hand to see if they are what you expect?

Again, you're being overly reticent with the information. I'm sure we'll get to the bottom of your problem, but it's easier when it isn't like pulling hen's teeth.

I'm sorry....here's what my programs is suppose to do:

A connection fee of $1.99 will be assessed for all
calls; the first three minutes will cost $2.00 per minute; after three
minutes, each additional minute will cost $0.45.
Write a program that prompts the user for the number of minutes the call
lasted and outputs the cost of the phone call.

DaWei · Oct 28th, 2007, 7:10 PM

Your charge for calls over three minutes should be connection fee + (3 * cost of minutes up to 3) + ((minutes - 3) * cost of minutes over 3). Working this out before hitting the keyboard is a good idea.

Jabo · Oct 28th, 2007, 7:10 PM

Might we infer something about the teacher who gave this problem?

DaWei · Oct 28th, 2007, 7:11 PM

You might, but I don't think that helps the OP solve this problem, or future problems.

Simplesouljah · Oct 28th, 2007, 7:22 PM

I am still confused.....

DaWei · Oct 28th, 2007, 7:47 PM

And I read your mind as to what is confusing you, right?

Simplesouljah · Oct 28th, 2007, 7:50 PM

Quote:

Originally Posted by DaWei

And I read your mind as to what is confusing you, right?

yes

The Dark · Oct 28th, 2007, 9:19 PM

This code:

(Toggle Plain Text)

    if (min  <= 3)  
       total = cf + (ftm * min);
       
    else (min > 3);
       total = cf + ftm + (min * adm);

You are missing an "if" after the else and you have a semi-colon after the (min > 3).
This is what the compiler interprets this as:

(Toggle Plain Text)

    if (min  <= 3)  
    {
       total = cf + (ftm * min);
    } 
    else
    {
      (min > 3);  // note - this does nothing.
    }
    total = cf + ftm + (min * adm);

So you are always calculating the total using the second method - does this match your results?

Edit: I only looked at the syntax, not the logic. See Dawei's posts as well.

Simplesouljah · Nov 4th, 2007, 8:01 AM

I need 2 Write a program with a for or while loop that will calculate the sum of intergers between 1 & 500 that are evenly divisible by either 7 or 11. then calculate an print to the screen how many intergers there are between 1 & 500 that are evenly divisible by either 7 or 11 and calculate the average number from the sum divided by the count, format it with two numbers after the decimal point. The average should come out to be 251.45. I need any help i can get thank you.

this is what i have so far, not sure what I'm doing wrong.

(Toggle Plain Text)

int main()

{
    int i, sum, count;
    sum = 0;
    count = 0;
    float averege;
    
for (i = 1; i <= 500; i++)
{
    if (i % 7 == 0 || i % 11 == 0)
    sum = sum += i;
    count = count++;
    }
    
    cout << fixed << setprecision(2);

    cout << "The sum is " << sum << " and the averege is " << averege << endl;

    cout << "The total count is " << count << endl;

system("pause");

return 0;
}

The Dark · Nov 4th, 2007, 3:07 PM

(Toggle Plain Text)

    sum = sum += i;
    count = count++;

The first line is adding i in twice.
The second line is adding 1 to count and then resetting it back to what it was.
You should just be using sum=sum+i and count++

Oct 28th, 2007, 7:10 PM	#12
DaWei Resident Grouch Join Date: Jun 2005 Posts: 6,453 Rep Power: 10	Re: Hey Pf Your charge for calls over three minutes should be connection fee + (3 * cost of minutes up to 3) + ((minutes - 3) * cost of minutes over 3). Working this out before hitting the keyboard is a good idea. __________________ Abstraction doesn't make it impossible to write bad code; it makes it possible to write superior code. Contributor's Corner: Grumpy on C++ Exceptions DaWei on Pointers

Oct 28th, 2007, 7:10 PM	#13
Jabo Not a user? Join Date: Sep 2007 Posts: 255 Rep Power: 1	Re: Hey Pf Might we infer something about the teacher who gave this problem?

Oct 28th, 2007, 7:11 PM	#14
DaWei Resident Grouch Join Date: Jun 2005 Posts: 6,453 Rep Power: 10	Re: Hey Pf You might, but I don't think that helps the OP solve this problem, or future problems. __________________ Abstraction doesn't make it impossible to write bad code; it makes it possible to write superior code. Contributor's Corner: Grumpy on C++ Exceptions DaWei on Pointers

Oct 28th, 2007, 7:22 PM	#15
Simplesouljah Newbie Join Date: Oct 2007 Posts: 28 Rep Power: 0	Re: Hey Pf I am still confused.....

Oct 28th, 2007, 7:47 PM	#16
DaWei Resident Grouch Join Date: Jun 2005 Posts: 6,453 Rep Power: 10	Re: Hey Pf And I read your mind as to what is confusing you, right? __________________ Abstraction doesn't make it impossible to write bad code; it makes it possible to write superior code. Contributor's Corner: Grumpy on C++ Exceptions DaWei on Pointers

Oct 28th, 2007, 9:19 PM	#18
The Dark Expert Programmer Join Date: Jun 2005 Posts: 824 Rep Power: 4	Re: Hey Pf This code: (Toggle Plain Text) if (min <= 3) total = cf + (ftm * min); else (min > 3); total = cf + ftm + (min * adm); if (min <= 3) total = cf + (ftm * min); else (min > 3); total = cf + ftm + (min * adm); You are missing an "if" after the else and you have a semi-colon after the (min > 3). This is what the compiler interprets this as: (Toggle Plain Text) if (min <= 3) { total = cf + (ftm * min); } else { (min > 3); // note - this does nothing. } total = cf + ftm + (min * adm); if (min <= 3) { total = cf + (ftm * min); } else { (min > 3); // note - this does nothing. } total = cf + ftm + (min * adm); So you are always calculating the total using the second method - does this match your results? Edit: I only looked at the syntax, not the logic. See Dawei's posts as well. Last edited by The Dark; Oct 28th, 2007 at 9:21 PM. Reason: Posted before noticing second page in thread :(

Nov 4th, 2007, 8:01 AM	#19
Simplesouljah Newbie Join Date: Oct 2007 Posts: 28 Rep Power: 0	Re: Hey Pf I need 2 Write a program with a for or while loop that will calculate the sum of intergers between 1 & 500 that are evenly divisible by either 7 or 11. then calculate an print to the screen how many intergers there are between 1 & 500 that are evenly divisible by either 7 or 11 and calculate the average number from the sum divided by the count, format it with two numbers after the decimal point. The average should come out to be 251.45. I need any help i can get thank you. this is what i have so far, not sure what I'm doing wrong. (Toggle Plain Text) int main() { int i, sum, count; sum = 0; count = 0; float averege; for (i = 1; i <= 500; i++) { if (i % 7 == 0 \|\| i % 11 == 0) sum = sum += i; count = count++; } cout << fixed << setprecision(2); cout << "The sum is " << sum << " and the averege is " << averege << endl; cout << "The total count is " << count << endl; system("pause"); return 0; } int main() { int i, sum, count; sum = 0; count = 0; float averege; for (i = 1; i <= 500; i++) { if (i % 7 == 0 \|\| i % 11 == 0) sum = sum += i; count = count++; } cout << fixed << setprecision(2); cout << "The sum is " << sum << " and the averege is " << averege << endl; cout << "The total count is " << count << endl; system("pause"); return 0; } Last edited by DaWei; Nov 4th, 2007 at 10:38 AM. Reason: Added code tags. That's twice.

Nov 4th, 2007, 3:07 PM	#20
The Dark Expert Programmer Join Date: Jun 2005 Posts: 824 Rep Power: 4	Re: Hey Pf (Toggle Plain Text) sum = sum += i; count = count++; sum = sum += i; count = count++; The first line is adding i in twice. The second line is adding 1 to count and then resetting it back to what it was. You should just be using sum=sum+i and count++

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Programming Forums > Application Development > C++

Hey Pf