Programming Forums > Application Development > Visual Basic

boatn19 · Jun 29th, 2007, 2:30 PM

the following code is only displaying one number and I am trying to get it display six numbers

        Dim number(5) As Integer
        Dim subscript As Integer
        Dim searchSubscript As Integer
        Dim isFound As Boolean
        Dim raNumber As Integer
        Dim randomGenerator As New Random

        number(0) = 5
        subscript = number(1)
        Do While subscript < number.Length
            raNumber = randomGenerator.Next(1, 54)
            searchSubscript = 0
            Do While searchSubscript < subscript
                isFound = False
                If searchSubscript = raNumber Then
                    isFound = True
                Else
                    searchSubscript = searchSubscript + 1
                End If
            Loop
            If isFound = False Then
                subscript = raNumber
                subscript = subscript + 1
            End If
        Loop
        'display the numbers
        Me.xLotteryLabel.Text = (subscript.ToString())
    End Sub
End Class

mackenga · Jul 10th, 2007, 6:53 PM

I can see what you're trying to do there, but you're getting confused between numbers, subscripts, etc. You start off by generating numbers into your array, then you display the numbers (right?). So how about:

(Toggle Plain Text)

Dim I As Integer, J As Integer
Dim intNumber(5) As Integer
Dim intNew As Integer
Dim rndGen As New Random

For I = 0 To 5
    intNew = rndGen.Next(1, 54)
    For J = 0 To I - 1
        If intNumber(J) = intNew Then
            I = I - 1
            Exit For
        End If
    Next J
Next I

For I = 0 To 5
    lblResult.Caption = lblResult.Caption & intNumber(I)
Next

Notice I don't really need the boolean to note whether I've found the number already there; instead, after the new number is generated I search through the array to see if it's already there and take one off I if it is, which will push the outer loop back so it runs this step again next time. Then I Exit For to duck out of the inner For loop to let that happen.

This is probably not the best way and isn't exactly what you were asking for but I was finding your code confusing, so I hope you can figure out how to put the two together and that this helps. I also hope it runs - I don't actually have VB handy to try it out!

zaracyn · Aug 3rd, 2007, 1:21 PM

You both appear to be forgetting to populate your array, it might look something like this:

Private Sub FindWinningLottoNumberButton_Click()
Dim I As Integer
Dim lottoNum As Integer
Dim lottoNumArray(5) As Integer

For I = 0 To 5
lottoNum = Rand(1, 56)
lottoNumArray(I) = lottoNum
' place code to check for unique numbers here
Next I

For I = 0 To 5
TextBox1.Text = TextBox1.Text & lottoNumArray(I) & " "
Next I

TextBox1.Text = TextBox1.Text & vbNewLine
End Sub

Hope this helps!

Jabo · Sep 3rd, 2007, 10:47 PM

Quote:

Originally Posted by boatn19

(Toggle Plain Text)

number(0) = 5
subscript = number(1)

This looks to me like a data error.
number(0) is initialized to value 5, number(1) will be initialized to 0, unless that's what you were counting on.

Jun 29th, 2007, 2:30 PM	#1
boatn19 Newbie Join Date: May 2005 Location: Charleston, SC Posts: 11 Rep Power: 0	only displays 1 number not 6 the following code is only displaying one number and I am trying to get it display six numbers (Toggle Plain Text) Dim number(5) As Integer Dim subscript As Integer Dim searchSubscript As Integer Dim isFound As Boolean Dim raNumber As Integer Dim randomGenerator As New Random number(0) = 5 subscript = number(1) Do While subscript < number.Length raNumber = randomGenerator.Next(1, 54) searchSubscript = 0 Do While searchSubscript < subscript isFound = False If searchSubscript = raNumber Then isFound = True Else searchSubscript = searchSubscript + 1 End If Loop If isFound = False Then subscript = raNumber subscript = subscript + 1 End If Loop 'display the numbers Me.xLotteryLabel.Text = (subscript.ToString()) End Sub End Class Dim number(5) As Integer Dim subscript As Integer Dim searchSubscript As Integer Dim isFound As Boolean Dim raNumber As Integer Dim randomGenerator As New Random number(0) = 5 subscript = number(1) Do While subscript < number.Length raNumber = randomGenerator.Next(1, 54) searchSubscript = 0 Do While searchSubscript < subscript isFound = False If searchSubscript = raNumber Then isFound = True Else searchSubscript = searchSubscript + 1 End If Loop If isFound = False Then subscript = raNumber subscript = subscript + 1 End If Loop 'display the numbers Me.xLotteryLabel.Text = (subscript.ToString()) End Sub End Class

Jul 10th, 2007, 6:53 PM	#2
mackenga Professional Programmer Join Date: Mar 2005 Location: Glasgow, Scotland Posts: 317 Rep Power: 4	I can see what you're trying to do there, but you're getting confused between numbers, subscripts, etc. You start off by generating numbers into your array, then you display the numbers (right?). So how about: (Toggle Plain Text) Dim I As Integer, J As Integer Dim intNumber(5) As Integer Dim intNew As Integer Dim rndGen As New Random For I = 0 To 5 intNew = rndGen.Next(1, 54) For J = 0 To I - 1 If intNumber(J) = intNew Then I = I - 1 Exit For End If Next J Next I For I = 0 To 5 lblResult.Caption = lblResult.Caption & intNumber(I) Next Dim I As Integer, J As Integer Dim intNumber(5) As Integer Dim intNew As Integer Dim rndGen As New Random For I = 0 To 5 intNew = rndGen.Next(1, 54) For J = 0 To I - 1 If intNumber(J) = intNew Then I = I - 1 Exit For End If Next J Next I For I = 0 To 5 lblResult.Caption = lblResult.Caption & intNumber(I) Next Notice I don't really need the boolean to note whether I've found the number already there; instead, after the new number is generated I search through the array to see if it's already there and take one off I if it is, which will push the outer loop back so it runs this step again next time. Then I Exit For to duck out of the inner For loop to let that happen. This is probably not the best way and isn't exactly what you were asking for but I was finding your code confusing, so I hope you can figure out how to put the two together and that this helps. I also hope it runs - I don't actually have VB handy to try it out! __________________ "I'm not a genius. Why do I have to suffer?"

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Aug 3rd, 2007, 1:21 PM	#3
zaracyn Newbie Join Date: Jun 2006 Location: Michigan Posts: 13 Rep Power: 0	You both appear to be forgetting to populate your array, it might look something like this: Private Sub FindWinningLottoNumberButton_Click() Dim I As Integer Dim lottoNum As Integer Dim lottoNumArray(5) As Integer For I = 0 To 5 lottoNum = Rand(1, 56) lottoNumArray(I) = lottoNum ' place code to check for unique numbers here Next I For I = 0 To 5 TextBox1.Text = TextBox1.Text & lottoNumArray(I) & " " Next I TextBox1.Text = TextBox1.Text & vbNewLine End Sub Hope this helps!

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Programming Forums > Application Development > Visual Basic

only displays 1 number not 6