Programming Forums > Application Development > C++

357mag · Jun 8th, 2007, 3:23 AM

This program I've got uses an array and calls a function to find the average of the integers in the array. The integers in the array are 9, 4, 6, 8, 10 and when you add them up you get 37. When you divide by 5 you get 7.4.

I do not want to lose the fractional part of the answer so that's why I'm using the static_cast< >operator. I also always want the answer to be output with a fixed decimal point and two digits of precision to the right of the decimal point.

But my output says "The average is 7.00" instead of "7.40" like it should.

I'm not sure where I'm going wrong. Here is the code:

(Toggle Plain Text)

int findAverage(int j[]);

int main()
{
	int numbers[] = {9, 4, 6, 8, 10};
	double average = 0.0;
	
	cout << "The values in the array are: "; 

	for (int i = 0; i < 5; i++)
		cout << numbers[i] << " ";

	cout << endl;

	average = findAverage(numbers);

	cout << "The average of the values is: " << setprecision(2)
		 << setiosflags(ios::fixed | ios::showpoint)
		 << average;

    cout << endl;
	return 0;
}

int findAverage(int j[])
{
    int total = 0;

	for (int i = 0; i < 5; i++)
		total += j[i];

	return static_cast<double>(total) / 5;

}

grumpy · Jun 8th, 2007, 4:08 AM

A function that returns int can never return a value that is not an integer. Try making findAverage() return double, and return from it using;

(Toggle Plain Text)

return total/5.0;

Jun 8th, 2007, 3:23 AM	#1
357mag Hobbyist Programmer Join Date: Mar 2005 Posts: 148 Rep Power: 4	I'm getting the wrong answer This program I've got uses an array and calls a function to find the average of the integers in the array. The integers in the array are 9, 4, 6, 8, 10 and when you add them up you get 37. When you divide by 5 you get 7.4. I do not want to lose the fractional part of the answer so that's why I'm using the static_cast< >operator. I also always want the answer to be output with a fixed decimal point and two digits of precision to the right of the decimal point. But my output says "The average is 7.00" instead of "7.40" like it should. I'm not sure where I'm going wrong. Here is the code: (Toggle Plain Text) int findAverage(int j[]); int main() { int numbers[] = {9, 4, 6, 8, 10}; double average = 0.0; cout << "The values in the array are: "; for (int i = 0; i < 5; i++) cout << numbers[i] << " "; cout << endl; average = findAverage(numbers); cout << "The average of the values is: " << setprecision(2) << setiosflags(ios::fixed \| ios::showpoint) << average; cout << endl; return 0; } int findAverage(int j[]) { int total = 0; for (int i = 0; i < 5; i++) total += j[i]; return static_cast<double>(total) / 5; } int findAverage(int j[]); int main() { int numbers[] = {9, 4, 6, 8, 10}; double average = 0.0; cout << "The values in the array are: "; for (int i = 0; i < 5; i++) cout << numbers[i] << " "; cout << endl; average = findAverage(numbers); cout << "The average of the values is: " << setprecision(2) << setiosflags(ios::fixed \| ios::showpoint) << average; cout << endl; return 0; } int findAverage(int j[]) { int total = 0; for (int i = 0; i < 5; i++) total += j[i]; return static_cast<double>(total) / 5; } Last edited by 357mag; Jun 8th, 2007 at 3:25 AM. Reason: Mistake

Jun 8th, 2007, 4:08 AM	#2
grumpy Programming Guru Join Date: Jun 2005 Location: Adelaide, South Australia Posts: 1,261 Rep Power: 5	A function that returns int can never return a value that is not an integer. Try making findAverage() return double, and return from it using; (Toggle Plain Text) return total/5.0; return total/5.0;

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Programming Forums > Application Development > C++

I'm getting the wrong answer