bigmitch

Heres my code:

[ CODE ]


#include <stdio.h>
#include <stdlib.h> /*header for malloc call*/

/*setting filename before main program starts*/
#define FILENAME "maze2.txt"

/*Recusive maze solver function*/
void solve (char **maze, int row, int col) {

if (maze[row][col] == 'g' )
{
printf("Goal Reached!\n");
}
else if (maze[row][col] == 'p')
{
maze[row][col] = 'f';

if (maze[row-1][col] == 'p') //up
{
maze[row-1][col] = 'f';
solve(maze, row-1, col);
maze[row-1][col] = 'f';
}

if (maze[row+1][col] == 'p') //down

{
maze[row+1][col] = 'f';
solve(maze, row+1, col);
maze[row+1][col] = 'f';
}

if (maze[row][col-1] == 'p') //left

{
maze[row][col-1] = 'f';
solve(maze, row, col-1);
maze[row][col-1] = 'f';
}

if (maze[row][col+1] == 'p') //right

{
maze[row][col+1] = 'f';
solve(maze, row, col+1);
maze[row][col+1] = 'f';
}
}
return;
}


/*main*/
int main ( void )
{

/*pointer to file */
FILE *ipf;

/*declare variables*/
int size,x,y;
char **maze;
int p, q;
int ch;

/* Open file for reading*/
ipf = fopen ( FILENAME, "r" );

/* If file not there show error*/
if((ipf=fopen(FILENAME,"r"))==NULL) {
printf("The file is not open");
}

/* Get size of maze from file*/
fscanf ( ipf, "%d", &size );
printf ("%d x %d MAZE\n Text File:\n", size, size);

/* Check for start of maze */
if ( fgetc ( ipf ) != '\n' ) {
printf ("Invalid file format\n" );
fclose (ipf);
}

/*Declaring maze using memory allocation*/
maze = malloc ( size * sizeof *maze );

for (p= 0; p < size; p++ ) {
maze[p] = malloc ( size * sizeof *maze[p] );

}

/*Loop through rows and columns of text file entering
*characters into array*/
for ( p = 0; p < size; p++ ) {
for ( q = 0; q < size; q++ ) {
ch = fgetc ( ipf ); //fgetc gets char's from text file
if ( ch != '\n' )
maze[p][q] = (char)ch;
else
--q;
}
}

/* Displays the whole maze */
printf ( "%d\n", size );
for ( p = 0; p < size; p++ ) {
for ( q = 0;q < size; q++ )
putchar ( maze[p][q] );
putchar ( '\n' ); //new line added at end of each row
}

/*Closes file from reading*/
fclose (ipf);

/*Ask user for start coordinates*/
start: printf("The start coordinates must be a p character\n");
printf("Coordinates start from 0,0\n");
printf("Give start coordinates\nX = ");
scanf("%d", &x);
if ( x >= size )
{
printf("Coordinate out of range\n");
goto start; //if x value too big then restart
}
printf("Y = ");
scanf("%d", &y);
if ( y >= size )
{
printf("Coordinate out of range\n");
goto start;//if y value too big then restart
}

if (maze[x][y] == 'x')
{
printf ( "You have landed on a wall! - Please try again\n");
goto start; //if not starting on x then restart
}

if (maze[x][y] == 'g' )
{
printf( "You got lucky - End of Maze!\n" );
exit(1);
}
printf("Start at [%d , %d]\n", x,y);

solve (maze, x, y);

return 0;
}


[ CODE\ ]


Here's the txt file:

11
xxxxxxxxxxx
xpxxpxxpgxx
xppppxppxxx
xxxppxpppxx
xpppxxxxpxx
xxxppppppxx
xpppxxxxxxx
xxxpxxxppxx
xxxpppppxxx
xxxxxxxxxxx
xxxxxxxxxxx

Question: When I type coordinates at beginning of program, X seams to the Y coordinate and visa versa? eg type X = 1 and Y = 2 shows x - wall and not p - path

Eggbert

In cartesian coordinate notation, x is the horizontal path while y is the vertical path. Using the table:
x = 1 and y = 2 (with zero based indexing) under the cartesian coordinate system would result in 8. However, because C++ arrays are in row-major order, the index of the first dimension is the vertical path (it selects which single array in the array of arrays to use) and the index of the second dimension is the horizontal path (it selects which item in the single array to use). Using the same indices under C++ rules, the result would be 6. You should adjust your logic and assumptions accordingly.