Programming Forums > Application Development > Assembly

cwl157 · Dec 4th, 2006, 8:52 PM

alright. One problem left it prints 1 for the hamming distance everytime. I think its because i don't quite understand how the printing stuff works so im printing the wrong register.
here is the code though:

(Toggle Plain Text)

.text

main:
	la $a0,prompt_in      #print prompt on terminal
	li $v0,4              #prints a string on the terminal
	syscall

	li $v0,5	      #reads in an integer
	syscall
	sw $v0,num1

	la $a0,prompt_ina      #print prompt on terminal
	li $v0,4               #prints a string on the terminal
	syscall

        li $v0,5	       #reads in an integer
	syscall
	sw $v0,num2

	lw $v0,num1		#set a
	lw $t0,num2		#set b

	xor $v1,$v0,$t0		# $v1 is c.  compare $v0 and $t0 and store in $v1

	move $s1, $zero		#s1 is the counter set to 0
	move $s2, $zero		#set hamming to 0
	li $s6,1		#set $s6 to 1
loop:
	and $s4,$v1,$s6		#s4 is d and c with d store in $s4	
	beq $s4, $s6,hamming	#set s5 equal to 1 if d equals 1
	srl $v1, $v1, $s6	#shift c right by 1
	addi $s1, $s1, 1	#i = i + 1 increment loop counter
	li $s7,32		#set $s7 to 32
	blt $s1,$s7,loop	#if loopCount <32 go to loop
	beq $s1,$s7,loop	#if loopCount == 32 go to loop
	#j loop			#goto loop
	
hamming:
	addi $s2, $s2, 1	#increment hamming

print:
	la $a0,prompt_out      #print prompt on terminal
	li $v0,4              #prints a string on the terminal
	syscall

	move $a0, $s2		# syscall 1 prints an integer
	li $v0, 1
	syscall

	li $v0,10              #exit program
	syscall



.data
prompt_in:    .asciiz "Enter first integer: "            # first integer
prompt_ina:    .asciiz "Enter second integer: "          #second integer
prompt_out:   .asciiz "The hamming distance is "
num1: .word 0
num2: .word 0

cwl157 · Dec 4th, 2006, 8:57 PM

and how do i even go about starting to debug it. Printing stuff takes like 3 lines. Like is there a way to print out what hamming distance is after every time through the loop?

The Dark · Dec 4th, 2006, 9:00 PM

(Toggle Plain Text)

loop:
	and $s4,$v1,$s6		#s4 is d and c with d store in $s4	
	beq $s4, $s6,hamming	#set s5 equal to 1 if d equals 1
	srl $v1, $v1, $s6	#shift c right by 1
	addi $s1, $s1, 1	#i = i + 1 increment loop counter
	li $s7,32		#set $s7 to 32
	blt $s1,$s7,loop	#if loopCount <32 go to loop
	beq $s1,$s7,loop	#if loopCount == 32 go to loop
	#j loop			#goto loop
	
hamming:
	addi $s2, $s2, 1	#increment hamming

print:

When it jumps to hamming, there is nothing to make it jump back. It also goes through the hamming code when the loop finishes so it will always add 1
It might be easier to just jump around the hamming increment code if $s4 is equal to zero.

Did you look at the google search for less than or equal to?

The Dark · Dec 4th, 2006, 9:02 PM

Quote:

Originally Posted by cwl157

and how do i even go about starting to debug it. Printing stuff takes like 3 lines. Like is there a way to print out what hamming distance is after every time through the loop?

before you check to see if you need to go around again, you could put

(Toggle Plain Text)

	move $a0, $s2		# syscall 1 prints an integer
	li $v0, 1
	syscall

cwl157 · Dec 4th, 2006, 9:06 PM

well the simulator im using has a single step option so i did that and didnt get much from it but what i did notice was it looked like it was only going through the loop once.

cwl157 · Dec 4th, 2006, 9:08 PM

it said 0 and then the hamming distance is 1 so yea i think its only going through the loop one time.

cwl157 · Dec 4th, 2006, 9:12 PM

i think i know the problem. when the hamming distance increases i have to have it branch to another part of the program to do that which is called hamming. So when it goes through that its out of the loop and then goes to print. Can i like somehow have the hamming being added under a label but then put that label still in the loop or maybe put the check and stuff under the hamming label?

The Dark · Dec 4th, 2006, 9:19 PM

I'd do something like:

(Toggle Plain Text)

loop:
	and $s4,$v1,$s6		#s4 is d and c with d store in $s4	
	beq $s4, 0, nohamming	#Jumpt to nohamming if $s4 is zero

        addi $s2, $s2, 1	#increment hamming
   
nohamming:
	srl $v1, $v1, $s6	#shift c right by 1
	addi $s1, $s1, 1	#i = i + 1 increment loop counter
	ble $s1,32,loop	#if loopCount <=32 go to loop

This link seems to have a nice list of MIPS instructions.

cwl157 · Dec 4th, 2006, 9:36 PM

nope nevermind i was an idiot and was making the check twice. It seems to work thank you so very much for the help and simplifying the actual problem for me. When the problem was first explained it was dealing with arrays and adding things to them and looping through them and everything. I guess that made the most sense to me because of the java i've done that wouldn't have been that big of a deal in java but this is really different.

The Dark · Dec 4th, 2006, 9:39 PM

So what does your code look like now?

Dec 4th, 2006, 8:52 PM	#31
cwl157 Professional Programmer Join Date: Feb 2005 Posts: 327 Rep Power: 4	alright. One problem left it prints 1 for the hamming distance everytime. I think its because i don't quite understand how the printing stuff works so im printing the wrong register. here is the code though: (Toggle Plain Text) .text main: la $a0,prompt_in #print prompt on terminal li $v0,4 #prints a string on the terminal syscall li $v0,5 #reads in an integer syscall sw $v0,num1 la $a0,prompt_ina #print prompt on terminal li $v0,4 #prints a string on the terminal syscall li $v0,5 #reads in an integer syscall sw $v0,num2 lw $v0,num1 #set a lw $t0,num2 #set b xor $v1,$v0,$t0 # $v1 is c. compare $v0 and $t0 and store in $v1 move $s1, $zero #s1 is the counter set to 0 move $s2, $zero #set hamming to 0 li $s6,1 #set $s6 to 1 loop: and $s4,$v1,$s6 #s4 is d and c with d store in $s4 beq $s4, $s6,hamming #set s5 equal to 1 if d equals 1 srl $v1, $v1, $s6 #shift c right by 1 addi $s1, $s1, 1 #i = i + 1 increment loop counter li $s7,32 #set $s7 to 32 blt $s1,$s7,loop #if loopCount <32 go to loop beq $s1,$s7,loop #if loopCount == 32 go to loop #j loop #goto loop hamming: addi $s2, $s2, 1 #increment hamming print: la $a0,prompt_out #print prompt on terminal li $v0,4 #prints a string on the terminal syscall move $a0, $s2 # syscall 1 prints an integer li $v0, 1 syscall li $v0,10 #exit program syscall .data prompt_in: .asciiz "Enter first integer: " # first integer prompt_ina: .asciiz "Enter second integer: " #second integer prompt_out: .asciiz "The hamming distance is " num1: .word 0 num2: .word 0 .text main: la $a0,prompt_in #print prompt on terminal li $v0,4 #prints a string on the terminal syscall li $v0,5 #reads in an integer syscall sw $v0,num1 la $a0,prompt_ina #print prompt on terminal li $v0,4 #prints a string on the terminal syscall li $v0,5 #reads in an integer syscall sw $v0,num2 lw $v0,num1 #set a lw $t0,num2 #set b xor $v1,$v0,$t0 # $v1 is c. compare $v0 and $t0 and store in $v1 move $s1, $zero #s1 is the counter set to 0 move $s2, $zero #set hamming to 0 li $s6,1 #set $s6 to 1 loop: and $s4,$v1,$s6 #s4 is d and c with d store in $s4 beq $s4, $s6,hamming #set s5 equal to 1 if d equals 1 srl $v1, $v1, $s6 #shift c right by 1 addi $s1, $s1, 1 #i = i + 1 increment loop counter li $s7,32 #set $s7 to 32 blt $s1,$s7,loop #if loopCount <32 go to loop beq $s1,$s7,loop #if loopCount == 32 go to loop #j loop #goto loop hamming: addi $s2, $s2, 1 #increment hamming print: la $a0,prompt_out #print prompt on terminal li $v0,4 #prints a string on the terminal syscall move $a0, $s2 # syscall 1 prints an integer li $v0, 1 syscall li $v0,10 #exit program syscall .data prompt_in: .asciiz "Enter first integer: " # first integer prompt_ina: .asciiz "Enter second integer: " #second integer prompt_out: .asciiz "The hamming distance is " num1: .word 0 num2: .word 0

Dec 4th, 2006, 9:00 PM	#33
The Dark Expert Programmer Join Date: Jun 2005 Posts: 816 Rep Power: 4	(Toggle Plain Text) loop: and $s4,$v1,$s6 #s4 is d and c with d store in $s4 beq $s4, $s6,hamming #set s5 equal to 1 if d equals 1 srl $v1, $v1, $s6 #shift c right by 1 addi $s1, $s1, 1 #i = i + 1 increment loop counter li $s7,32 #set $s7 to 32 blt $s1,$s7,loop #if loopCount <32 go to loop beq $s1,$s7,loop #if loopCount == 32 go to loop #j loop #goto loop hamming: addi $s2, $s2, 1 #increment hamming print: loop: and $s4,$v1,$s6 #s4 is d and c with d store in $s4 beq $s4, $s6,hamming #set s5 equal to 1 if d equals 1 srl $v1, $v1, $s6 #shift c right by 1 addi $s1, $s1, 1 #i = i + 1 increment loop counter li $s7,32 #set $s7 to 32 blt $s1,$s7,loop #if loopCount <32 go to loop beq $s1,$s7,loop #if loopCount == 32 go to loop #j loop #goto loop hamming: addi $s2, $s2, 1 #increment hamming print: When it jumps to hamming, there is nothing to make it jump back. It also goes through the hamming code when the loop finishes so it will always add 1 It might be easier to just jump around the hamming increment code if $s4 is equal to zero. Did you look at the google search for less than or equal to?

Dec 4th, 2006, 9:19 PM	#38
The Dark Expert Programmer Join Date: Jun 2005 Posts: 816 Rep Power: 4	I'd do something like: (Toggle Plain Text) loop: and $s4,$v1,$s6 #s4 is d and c with d store in $s4 beq $s4, 0, nohamming #Jumpt to nohamming if $s4 is zero addi $s2, $s2, 1 #increment hamming nohamming: srl $v1, $v1, $s6 #shift c right by 1 addi $s1, $s1, 1 #i = i + 1 increment loop counter ble $s1,32,loop #if loopCount <=32 go to loop loop: and $s4,$v1,$s6 #s4 is d and c with d store in $s4 beq $s4, 0, nohamming #Jumpt to nohamming if $s4 is zero addi $s2, $s2, 1 #increment hamming nohamming: srl $v1, $v1, $s6 #shift c right by 1 addi $s1, $s1, 1 #i = i + 1 increment loop counter ble $s1,32,loop #if loopCount <=32 go to loop This link seems to have a nice list of MIPS instructions.

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Dec 4th, 2006, 8:57 PM	#32
cwl157 Professional Programmer Join Date: Feb 2005 Posts: 327 Rep Power: 4	and how do i even go about starting to debug it. Printing stuff takes like 3 lines. Like is there a way to print out what hamming distance is after every time through the loop?

Dec 4th, 2006, 9:06 PM	#35
cwl157 Professional Programmer Join Date: Feb 2005 Posts: 327 Rep Power: 4	well the simulator im using has a single step option so i did that and didnt get much from it but what i did notice was it looked like it was only going through the loop once.

Dec 4th, 2006, 9:08 PM	#36
cwl157 Professional Programmer Join Date: Feb 2005 Posts: 327 Rep Power: 4	it said 0 and then the hamming distance is 1 so yea i think its only going through the loop one time.

Dec 4th, 2006, 9:12 PM	#37
cwl157 Professional Programmer Join Date: Feb 2005 Posts: 327 Rep Power: 4	i think i know the problem. when the hamming distance increases i have to have it branch to another part of the program to do that which is called hamming. So when it goes through that its out of the loop and then goes to print. Can i like somehow have the hamming being added under a label but then put that label still in the loop or maybe put the check and stuff under the hamming label?

Dec 4th, 2006, 9:36 PM	#39
cwl157 Professional Programmer Join Date: Feb 2005 Posts: 327 Rep Power: 4	nope nevermind i was an idiot and was making the check twice. It seems to work thank you so very much for the help and simplifying the actual problem for me. When the problem was first explained it was dealing with arrays and adding things to them and looping through them and everything. I guess that made the most sense to me because of the java i've done that wouldn't have been that big of a deal in java but this is really different.

Dec 4th, 2006, 9:39 PM	#40
The Dark Expert Programmer Join Date: Jun 2005 Posts: 816 Rep Power: 4	So what does your code look like now?

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Programming Forums > Application Development > Assembly

MIPS assembly language