Programming Forums > Application Development > Java

Progejad · Nov 11th, 2004, 7:07 AM

I have to do program which calculates x and y couples using next formulas:

x=(40*cos)+60*Math.cos((2/3)*t);

y=(40*sin)-60*Math.sin((2/3)*t);

the output of the program should look something like this:

x | y

1234 | 3456 // x and y results
2234 | 8923
1256 | 9842

"t" should change after 0,01 step (from -10 to 10)
(So in output there should be 2000 couples of x and y + first line x|y)

I tried to program but got only more confused after hours of trying...biggest problem is that "step" thing...and that "t" should change after every step...
I hope there's anyone that could help me ...

Infinite Recursion · Nov 11th, 2004, 9:12 AM

Sounds easy enough... Since this is a homework assignment, I'd like to see effort (code) on your end before I contribute code.

The "step" problem, would be a loop with an index variable that increments through from -10 to 10.

Progejad · Nov 12th, 2004, 3:39 AM

/*at the end my code was like that, but x and y were not right (maybe i did something wrong with x and y calculating
http://www.itcollege.ee/~kkoemets/kodused2...l_51b41c47.gif- x and y should be like that*/

(Toggle Plain Text)

//starting my code:   

    public class Hindeline1 {

    public static void main (String [] args) {   

    double x;
    double y;
   
    
    double t;
	

	for (t = -10; t <= (10); t +=0.01) 
	{
	
	double sin=Math.sin(t);
    double cos=Math.cos(t);
	
	x=(40*cos)+60*Math.cos((2/3)*t);
   
    y=(40*sin)-60*Math.sin((2/3)*t);
   
	
	System.out.println (x+ "|" +y);
	}
	}

}//End of code

drunkenCoder · Nov 13th, 2004, 1:29 AM

looks like you got it right to me ... what you wrote calculates x & y correctly (going by the formula you have provided)

Infinite Recursion · Nov 13th, 2004, 11:51 AM

Looks good. The code achieves your 2000+1 lines of output.
Drunken coder has confirmed the value is correct... you can plug them into a
calculator to confirm further if needed.

(Toggle Plain Text)

public class Hindeline1
{
 public static void main (String [] args)
 {
   double x;
   double y;
   double t;

   for (t = -10; t <= 10; t += 0.01)
   {
    double sin=Math.sin(t);
    double cos=Math.cos(t);

    x = (40 * cos) + 60 * Math.cos((2/3)*t);
    y = (40 * sin) - 60 * Math.sin((2/3)*t);

    System.out.println(x + " | " + y);
   }
 }
}

Nov 11th, 2004, 9:12 AM	#2
Infinite Recursion Programming Guru Join Date: Jul 2004 Location: United States Posts: 3,467 Rep Power: 8	Sounds easy enough... Since this is a homework assignment, I'd like to see effort (code) on your end before I contribute code. The "step" problem, would be a loop with an index variable that increments through from -10 to 10. __________________ http://jasonpowers.net "There are a thousand hacking at the branches of evil to one who is striking at the root."

Nov 12th, 2004, 3:39 AM	#3
Progejad Newbie Join Date: Nov 2004 Posts: 2 Rep Power: 0	/at the end my code was like that, but x and y were not right (maybe i did something wrong with x and y calculating http://www.itcollege.ee/~kkoemets/kodused2...l_51b41c47.gif- x and y should be like that/ (Toggle Plain Text) //starting my code: public class Hindeline1 { public static void main (String [] args) { double x; double y; double t; for (t = -10; t <= (10); t +=0.01) { double sin=Math.sin(t); double cos=Math.cos(t); x=(40cos)+60Math.cos((2/3)t); y=(40sin)-60Math.sin((2/3)t); System.out.println (x+ "\|" +y); } } }//End of code //starting my code: public class Hindeline1 { public static void main (String [] args) { double x; double y; double t; for (t = -10; t <= (10); t +=0.01) { double sin=Math.sin(t); double cos=Math.cos(t); x=(40cos)+60Math.cos((2/3)t); y=(40sin)-60Math.sin((2/3)t); System.out.println (x+ "\|" +y); } } }//End of code

Nov 13th, 2004, 11:51 AM	#5
Infinite Recursion Programming Guru Join Date: Jul 2004 Location: United States Posts: 3,467 Rep Power: 8	Looks good. The code achieves your 2000+1 lines of output. Drunken coder has confirmed the value is correct... you can plug them into a calculator to confirm further if needed. (Toggle Plain Text) public class Hindeline1 { public static void main (String [] args) { double x; double y; double t; for (t = -10; t <= 10; t += 0.01) { double sin=Math.sin(t); double cos=Math.cos(t); x = (40 * cos) + 60 * Math.cos((2/3)t); y = (40 sin) - 60 * Math.sin((2/3)t); System.out.println(x + " \| " + y); } } } public class Hindeline1 { public static void main (String [] args) { double x; double y; double t; for (t = -10; t <= 10; t += 0.01) { double sin=Math.sin(t); double cos=Math.cos(t); x = (40 cos) + 60 * Math.cos((2/3)t); y = (40 sin) - 60 * Math.sin((2/3)*t); System.out.println(x + " \| " + y); } } } __________________ http://jasonpowers.net "There are a thousand hacking at the branches of evil to one who is striking at the root."

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Nov 11th, 2004, 7:07 AM	#1
Progejad Newbie Join Date: Nov 2004 Posts: 2 Rep Power: 0	I have to do program which calculates x and y couples using next formulas: x=(40cos)+60Math.cos((2/3)t); y=(40sin)-60Math.sin((2/3)t); the output of the program should look something like this: x \| y 1234 \| 3456 // x and y results 2234 \| 8923 1256 \| 9842 "t" should change after 0,01 step (from -10 to 10) (So in output there should be 2000 couples of x and y + first line x\|y) I tried to program but got only more confused after hours of trying...biggest problem is that "step" thing...and that "t" should change after every step... I hope there's anyone that could help me ...

Nov 13th, 2004, 1:29 AM	#4
drunkenCoder Newbie Join Date: Nov 2004 Posts: 8 Rep Power: 0	looks like you got it right to me ... what you wrote calculates x & y correctly (going by the formula you have provided)

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