Get Current Directory Of Script
 

can someone tell me a way to get the directory that the script is in from within the program?

[php]
#!/usr/bin/perl
$pwd = "";
open(getPwd, "/bin/pwd |");
while(<getPwd>) {
$pwd .= $_;
}
close getPwd;

print "The working directory is, " . $pwd;
[/php]

There is probably a much simpler way, my perl skills are rudimentary.

Im using windows and I cant follow what your script is supposed to do. It didn't work for me, can you explain your thought process

look into CWD .... http://search.cpan.org/~kwilliams/Cwd-2.21/Cwd.pm

I have seen CWD but it doesnt return the directory the script is in just the current working directory which isnt the same thing

Isn't the program path and name in $0 or $$ or $_ or one of those special variables?

Yeah, $0 holds the the programs own name, which may contain the path (it varies). $$ is the process ID number.

There may be something in a Win32 specific module that finds the path.

Investigate GetFullPathName. Don't know that it's precisely what you're looking for.

$ENV{'SCRIPT_NAME'} contains the name of the current running script as well as the full path. You could extract the path from that.