Programming Forums - Printing escape sequences using printf()?

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bivhitscar

Nov 2nd, 2005 8:34 PM

Printing escape sequences using printf()?

Is it possible to print the escape sequence representation of a nonprinting character using printf()? ie. print "\n" instead of actually printing the newline itself.

I am trying to get a loop to read a string and print each character with it's equivalent ascii code. But this all turns to shit mainly with the newline character. Aside from making a kinda long if statement to filter the possibilites, any suggestions?

nindoja

Nov 2nd, 2005 8:37 PM

[code]printf("\\n");[code]
Basically, escape the backslash, so the escape sequence isn't seen.

bivhitscar

Nov 2nd, 2005 8:48 PM

Quote:

Originally Posted by nindoja

printf("\\n");

Basically, escape the backslash, so the escape sequence isn't seen.

That only works when I know what character is coming.

This is the code I'm using:

for (i = 1; i <= length; i++)

  {

    printf("%c = %3d, ", string[i - 1], string[i - 1]);



    if (i % 8 == 0)

      printf("\n");

  }

That basicaly says, read the current element of the array, print the character and print it's ascii code. The if statement is just for formatting purposes.

Ideally, I just want a simple if else that says if ch == isspace() print the escape sequence instead of the actual character, else print the character. Am I making any sense?

bivhitscar

Nov 2nd, 2005 8:56 PM

Actually, after reviewing what characters would actually pop up in real input, it's only two - a fair bit easier than I first thought. Although, I'd still like to hear if it's possible. :)

InfoGeek

Nov 3rd, 2005 3:08 AM

You can do something like

if(ch=='\n')

  printf("<new-line> - %3d",ch);

else if(ch==' ')

  printf("<space> - %3d",ch);

bivhitscar

Nov 3rd, 2005 10:08 PM

Quote:

Originally Posted by InfoGeek

You can do something like

if(ch=='\n')

  printf("<new-line> - %3d",ch);

else if(ch==' ')

  printf("<space> - %3d",ch);

Yeh, I just ended up using a switch. Thanks though. :D

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