Programming Forums - Printing only from the matching exp to the end of line?

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Printing only from the matching exp to the end of line?

Hello there! :)

Is there a way to print only from the matching expression to the end of line ?

Example, ( exp: /DC/ )

OU=TI,OU=Clientes,OU=TI-RIO,OU=Unidades,DC=crp,DC=pes,DC=biz

Output should be:

DC=crp,DC=pes,DC=biz

Thanks!
hippie :)

awk ' {if ( $0 ~ /DC/) print substr($0,index($0,"DC")) }' <filename>

sample run:

original file:

OU=TI,OU=Clientes,OU=TI-RIO,OU=Unidades,DC=crp,DC=pes,DC=biz

OU=TI,OU=Clientes,OU=TI-RIO,OU=Unidades

OU=Unidades,DC=crp2,DC=pes2,DC=biz2

DC=crp,DC=pes,DC=biz,OU=Unidades,DC=crp,DC=pes,DC=biz



this command 

 awk ' {if ( $0 ~ /DC/) print substr($0,index($0,"DC")) }' filename 



produced the following:



DC=crp,DC=pes,DC=biz

DC=crp2,DC=pes2,DC=biz2

DC=crp,DC=pes,DC=biz,OU=Unidades,DC=crp,DC=pes,DC=biz