Programming Forums - Need help in 2 scripts in bash

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gawi	May 10th, 2005 3:25 AM

Need help in 2 scripts in bash

Hi! I need your help.

1)
How to make a script which writes its argument in the other way round. I mean if arguments are "2 3 4 5" the script writes "5 4 3 2"

2)
How to make a script which reads a file which consinst of numbers (one number in one line) and writes the sum of those numbers.

E.G. the content of file:
------
3
7
6
4
------

in this case the script should write: 20

Please help me

Seamus

May 10th, 2005 1:11 PM

for the first will

echo "$9 $8 $7 $6 $5 $4 $3 $2 $1"

do?

Second:

#! /bin/bash

a=`cat file | perl -nle "print for m/^[0-9]*/g"`

b=`echo $a | tr ' ' '+'`

((c=$b))

echo $c

gawi	May 11th, 2005 10:39 AM

For the first script:

echo "$9 $8 $7 $6 $5 $4 $3 $2 $1"

This is not universal and too simple way. I need a script which writes its arguments in the other way round but i don't know how many will be those arguments. That way you wrote me works only with 1 to 9 arguments.

For the second: This is what i looked for :) thanx a lot. I didn't know that commend:

((=$b))

I even wrote simpler way (also working)



a=`cat file`

b=`echo -n $a | tr ' ' '+'`

((c=$b))

echo $c

THANX a lot and if you could help me with the first script

:)

Seamus

May 11th, 2005 12:59 PM

yea I know what you mean.
You'll have to use shift somewhere then.

Pizentios

May 11th, 2005 1:42 PM

for the first one, you could probally use a loop of some kind to keep looping, till you get to the end.

gawi	May 11th, 2005 3:12 PM

yeah i know but i tried with for and while but no idea :(

levk	Jul 18th, 2005 12:12 PM

re: reverse

for the first one...

I din't know, but is there a way to take the first argument and the rest of arguments? that way you can do it recursively:

if [ -n $1 ]

else

 ./reverse # after $1

 echo $1

fi

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