find out the average of odd numbers -do-while statement.
 

hi , I want to know if my answer is true??and I want your opinion in my answer..
• Write a program fragment to find out the average of odd numbers between two numbers given by the user using a do-while statement?


int sum=0;
int X=50;
int Y = 70;
int count=0;
do{
X++;
if(X%2!=0)
{
sum +=X;
count++;
}
}
while(X<Y);
int average = sum/count;
System.out.println("average=" + average );

Re: find out the average of odd numbers -do-while statement.
 

Looks like it would give the correct results, without testing i will say that you may have to change < to <= and possible change the point at which you increment X.

P.S Use [code] tags

Chris

Re: find out the average of odd numbers -do-while statement.
 

yes it will give you right answer possibly. Try with <= and note out different hope one will be the right answer.

Re: find out the average of odd numbers -do-while statement.
 

your code is quite right but the question says given by the user. ending with an odd no is not provided for, so the while statement should read x<=y; so as 2 test d last number, in case its odd.

Re: find out the average of odd numbers -do-while statement.
 

The code as you have written it should work; however, that's based on X and Y being even. If X were odd, the "X++;" line would be bad. If Y were odd, the "X<Y" condition would be bad.
For arbitrary X and Y, you'd either need to modify the rest of the code, or add something like the following near the beginning:


I'd also add that since consecutive odd numbers are 2 apart, incrementing by 1 then checking if your number is odd or even is kind of wasteful. Something like the following would be better:


I was going to point out that average may not be an int, but you can prove that the average is (X+Y)/2 (again, X and Y are both even, or both odd, I guess), so it has to be.