Programming Forums - How to skip a number in java

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How to skip a number in java

Hello to all.

I have this code for my class and I what I am trying to do is decrement the number 39 by two so that odd numbers show, until I get to zero using the "for loop" The issue is that I am suppose to exclude the numbers 33, and 3 when it prints the numbers out. I can't figure that part out, and I can't find it anywhere in the chapter that I had to read on this. Can someone please help me understand how i should do this? This is the code I have so far, but I took out the extra for statements for clarity, beacuse I thought they would help me but they don't.

If I am suppose to use if statements, I don't know how to do this excluding 3 and 33.

import java.util.*;
 
public class loop
{
 
public static void main (String[] args)
{
 
int i;
 
 
for (i = 39; i >= 0; i = i - 2)
 
 
        System.out.print(i + " ");
 
System.out.println();
}
}

Re: How to skip a number in java

Hey everyone, I figured it out about 5 minutes after I asked. Sorry, but thanks to those who would have helped anyway. :) Here is the solution that I found worked.

import java.util.*;
 
public class loop
{
 
public static void main (String[] args)
{
 
int i;
 
 
for (i = 39; i >= 35; i = i - 2)
 
 
        System.out.print(i + " ");
 
for (i = 31; i >= 5; i = i - 2)
 
 
        System.out.print(i + " ");
 
 
for (i = 1; i >= 0; i = i - 2)
 
 
        System.out.print(i + " ");
 
 
System.out.println();
}
}

Re: How to skip a number in java

There's a simpler way to do it, using an if statement. Here's the pseudocode:

loop i from 39 to 0 step 2:

    if i != 33 and i != 3:

        print i + " "

    end if

end loop

By the way, to enclose Java code, you should do this:

Quote:

[code=java]
// insert code here
[/code]

Re: How to skip a number in java

did you mean "every time the digit 3 is attained, ignore it"? or just the values 33 & 3? If its any digit, 3, then you might want to use some kind of toString() then get rid of the 3 then toInt()