Programming Forums - Help with this code

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Silicon_Pudding

Mar 15th, 2007 1:41 AM

Help with this code

ITERATE=240

for COUNT in `seq -w 1 $TOTAL`

do

  OTHER=$(($COUNT*2))

  ... more stuff

  ...

done

The problem I am having is that I can't figure out how to multiply COUNT by 2. In this example since TOTAL is 240, COUNT will be 3 digits. I get an error message at count 8 saying the value is too great for the base, which I assume is because of 3 digits and something with binary.

Is there a way I can multiply this number by two, while still interating through by one?

a thing

Mar 15th, 2007 3:55 PM

Don't use the -w option on seq. Many things interpret numbers starting with 0 as octal (base 8), likewise with 0x and hexadecimal (base 16).

Silicon_Pudding

Mar 15th, 2007 4:45 PM

I need the -w option to keep the 000 spaces in front of the number. Is there another clean way to do this?

Serinth

Mar 17th, 2007 12:20 PM

try this:
previously declare variable OTHER and set it to 0 then in the loop:

let OTHER="$COUNT"*2

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