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-   -   Function Parameters (http://www.programmingforums.org/showthread.php?t=12446)

grimpirate Jan 26th, 2007 2:00 PM

Function Parameters
 
ok let's assume I have a function with four parameters for instance:
:

function someFunction($var1, $var2, $var3, $var4){
...
}

Now in the various functions that come bundled with PHP there are certain functions that come bundled with optional parameters (that don't necessarily have to be included for the function to behave properly). For instance, the substr function which is described as follows:
:

string substr ( string string, int start [, int length] )
where the length parameter is optional.

My question is the following: How do I specify a parameter as optional? Or will PHP simply accept the function with one parameter passed to it and it's up to me to code the situation accordingly? For instance:
:

function someFunction($var1, $var2, $var3, $var4){
if(isset($var1) && isset($var2) && isset($var3) && isset($var4)){
...
}elseif(isset($var1) && isset($var2) && isset($var3)){
...
}
}

In this way making $var 4 an optional parameter? Any sample code to illustrate the idea would be appreciated.

DaWei Jan 26th, 2007 2:39 PM

You can have a variable number of arguments in PHP (similar to C printf, etc.), but I think you're actually talking about default arguments. See the manual here for defaults, here for variable length argument lists.

grimpirate Jan 26th, 2007 4:30 PM

Thanks DaWei yeah I meant a variable length argument list. Here's the function that I wrote with it:[PHP]function fluctuate(){
$args = func_get_args();
switch(func_num_args()){
case 1:
if(!is_string($args[0])) return !trigger_error("bool <strong>fluctuate</strong> ( string filename [, string mode [, string string [, int mode]]]) &rarr; <em>filename</em> is not a string", E_USER_ERROR);
if(!file_exists($args[0])) return !trigger_error("bool <strong>fluctuate</strong> ( string filename [, string mode [, string string [, int mode]]]) &rarr; Nonexistent file cannot be deleted", E_USER_NOTICE);
if(unlink($args[0])){
return true;
}else{
return !trigger_error("bool <strong>fluctuate</strong> ( string filename [, string mode [, string string [, int mode]]]) &rarr; Unable to delete file", E_USER_WARNING);
}
case 4:
if(!is_string($args[0])) return !trigger_error("bool <strong>fluctuate</strong> ( string filename [, string mode [, string string [, int mode]]]) &rarr; <em>filename</em> is not a string", E_USER_ERROR);
if(!is_string($args[1]) || strlen($args[1]) !== 1) return !trigger_error("bool <strong>fluctuate</strong> ( string filename [, string mode [, string string [, int mode]]]) &rarr; <em>mode</em> is not a character", E_USER_ERROR);
if(!is_int($args[3])) return !trigger_error("bool <strong>fluctuate</strong> ( string filename [, string mode [, string string [, int mode]]]) &rarr; <em>mode</em> is not an int", E_USER_ERROR);
$args[1] = strtolower($args[1]);
$ffd = null;
switch($args[1]){
case 'a':
if(!file_exists($args[0])) return !trigger_error("bool <strong>fluctuate</strong> ( string filename [, string mode [, string string [, int mode]]]) &rarr; Cannot append to nonexistent file", E_USER_WARNING);
if(!is_writeable($args[0])) return !trigger_error("bool <strong>fluctuate</strong> ( string filename [, string mode [, string string [, int mode]]]) &rarr; File is not writeable", E_USER_WARNING);
if(false === ($ffd = fopen($args[0], "a"))) return !trigger_error("bool <strong>fluctuate</strong> ( string filename [, string mode [, string string [, int mode]]]) &rarr; Unable to open file", E_USER_WARNING);
break;
case 'w':
if(false === ($ffd = fopen($args[0], "w"))) return !trigger_error("bool <strong>fluctuate</strong> ( string filename [, string mode [, string string [, int mode]]]) &rarr; Unable to open file", E_USER_WARNING);
if(!file_exists($args[0])) return !trigger_error("bool <strong>fluctuate</strong> ( string filename [, string mode [, string string [, int mode]]]) &rarr; Cannot write to nonexistent file", E_USER_WARNING);
if(!is_writeable($args[0])) return !trigger_error("bool <strong>fluctuate</strong> ( string filename [, string mode [, string string [, int mode]]]) &rarr; File is not writeable", E_USER_WARNING);
break;
default:
return !trigger_error("bool <strong>fluctuate</strong> ( string filename [, string mode [, string string [, int mode]]]) &rarr; Illegal mode specified", E_USER_ERROR);
}
if(stream_set_write_buffer($ffd, 0) !== 0) return !trigger_error("bool <strong>fluctuate</strong> ( string filename [, string mode [, string string [, int mode]]]) &rarr; Unable to buffer stream", E_USER_WARNING);
if(fwrite($ffd, $args[2]) === false) return !trigger_error("bool <strong>fluctuate</strong> ( string filename [, string mode [, string string [, int mode]]]) &rarr; Unable to write to file", E_USER_WARNING);
if(!fclose($ffd)) return !trigger_error("bool <strong>fluctuate</strong> ( string filename [, string mode [, string string [, int mode]]]) &rarr; Unable to close file", E_USER_WARNING);
if(!chmod($args[0], $args[3])) return !trigger_error("bool <strong>fluctuate</strong> ( string filename [, string mode [, string string [, int mode]]]) &rarr; Unable to change file permissions", E_USER_WARNING);
return true;
default:
return !trigger_error("bool <strong>fluctuate</strong> ( string filename [, string mode [, string string [, int mode]]]) &rarr; Incorrect number of arguments passed", E_USER_ERROR);
}
}[/PHP]Who knew file operations could produce so many errors *_* lol

writephp Feb 9th, 2007 10:40 PM

you could just set it to null in the function

so for instance

function something($var1,$var2,$var3,$var4=NULL){
}

so say you have to declare 1 2 and 3 and then 4 is set to null unless otherwise assigned

DaWei Feb 10th, 2007 12:02 AM

That's a default. You can actually set it to any default value you like. He said he meant a variable length list, though, which isn't the same thing.

Arevos Feb 10th, 2007 5:36 AM

Quote:

Originally Posted by grimpirate (Post 123139)
My question is the following: How do I specify a parameter as optional?

That seems to be asking more about default values than variable length arguments, DaWei.

DaWei Feb 10th, 2007 7:22 AM

I know it seems to. I expressed as much in post #2, and was told differently in post #3. If we're quoting,
Quote:

Thanks DaWei yeah I meant a variable length argument list.
Since the links I provided in post #2 covered both eventualities, I took the OP at his word. Personally, I don't see anything wrong with any of my posts here. If the OP is mistaken, he still has both links.

Arevos Feb 10th, 2007 8:19 AM

Quote:

Originally Posted by DaWei (Post 123765)
I know it seems to. I expressed as much in post #2, and was told differently in post #3.

Ah, you're quite right. My mistake.

woozy Mar 14th, 2007 5:37 PM

PHP is pretty flexible. In defining a function you can declare as few or as many variables as you wish.

The following will all do the exact same thing:

1)
function eat($subject, $object, $verb, $adjective){
if (! isset($verb)){$verb = "eats";}
if (isset($adjective)){
return $subject." ".$verb." ".$adjective." ".$object.".";
}else{
return $subject." ".$verb." ".$object.".";
}

eat("man", "chicken");

will return "man eats chicken" and the verb and the adjective weren't nescessarily. It'll work but you will get warning in your error log that it was "expecting" four parameters and only got two.

on the other hand

eat("man", "chicken", "savors", "juicy", "pickle", "my", "bottom");

will return "man savors juicy chicken" and leave no warning message what so ever. Giving too many arguments does nothing at all.

2)
function eat($subject, $object, $verb="eats"){
$adjective = func_get_arg(3);
if ($adjective){
return

}

eat("man", "chicken");

will return "man eats chicken." and gave no warnings. Why? function only expects three arguments but the $verb has a default setting to "eats" so that when it isn't supplied explicitly, "eats" is supplied by default.

eat("man", "chicken", "savors", "juicy", "pickle", "my", "bottom");

will return "man savors juicy chicken." Why? The function was "expecting" three parameters ($subject, $object, and $verb) and got them. The line:

$adjective = func_get_arg(3);

means that if there is a fourth parameter (3 is the index of the 4th parameter), set $adjective to it. If there isn't a fourth parameter $adjective is set to FALSE.

3)
function eat(){
$args = func_get_args();
$num = func_num_args();
if ($num < 2){
die ("Need to give two arguments at least");
}
else {
$subject = $args[0];
$object = $args[1];
}
if ($nums == 2){
$verb = "eats";
}else{
$verb = $args[2];
}
if ($nums >= 4){
$adjective = $args[3];
return $subject." ".$verb." ".$adjective." ".$object.".";
}else{
return $subject." ".$verb." ".$object.".";
}

eat("man", "chicken");

returns "man eats chicken." Why? eat() doesn't "expect" any parameters.

$args = func_get_args();

sets $args to the array ("man", "chicken").

$num = func_num_args();

set $num equal to 2. $num == 2 so $verb is set to "eats". $num is not >= 4 so "man eats chicken." is returned.

eat("man", "chicken", "savors", "juicy", "pickle", "my", "bottom");

yeilds "man savors juicy chicken". Which is pretty clear as $args ==("man", "chicken", "savors", "juicy", "pickle", "my", "bottom") and $num == 7.

---
As a rule of thumb define the parameters you need provided, set defaults for parameters you need but expect to be optional, and don't define the optional ones.

example:

function member($name, $id, $hobby){
if (! isset($id)) $id = set_id();
$hobbies = array_splice(func_get_args(),2);
}

Then

member("woozy",,"php","cooking", "skiing","being obtuse", "calling in sick");

will set $hobbies equal to the array ("php", "cooking", "skiing", etc.) and you can send as many arguments as you darn well please.




}

DaWei Mar 14th, 2007 6:41 PM

Please read the forum's rules/faq. In the absence of code tags I can't tell if your code is really ugly, or just seems that way.


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