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Hobbyist Programmer
Join Date: Jun 2005
Location: New Mexico
Posts: 228
Rep Power: 4 
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Consider using strptime - which is pretty flexible. Most compilers now support it. Older Windows compilers don't. Most calendric work uses strptime to convert dates to seconds in the epoch, which is the basis for time and date calculations in C.
#include <time.h>
#include <string.h>
#include <stdlib.h>
#include <ctype.h>
/* 86400 seconds per day */
#define DAY 86400
/*
lose the
th, nd, st suffixes if they exist
*/
char *remove_th_nd_st(const char *src)
{
const char *values[3]={{"th "}, {"nd "},{"st "} };
char *dest=strdup(src);
char *p=NULL;
int i=0;
while(i<3)
{
if( (p=strstr(src,values[i++]))==NULL ) continue;
if( !isdigit(*(p-1)) ) continue;
p+=3;
sprintf(dest,"%d %s",atoi(src),p);
break;
}
return dest;
}
/* return time difference in days
date1 = recent date
date1 = older date
---otherwise you get a negative value which may be okay.
*/
int date_diff(const char *date1, const char *date2)
{
int retval=0;
const char *fmt="%d %b %Y";
struct tm now, then;
char *wdate1=remove_th_nd_st(date1);
char *wdate2=remove_th_nd_st(date2);
if ( strptime(wdate1,fmt,&now)==NULL ||
strptime(wdate2,fmt,&then)==NULL )
{
perror("Bad date format");
exit(EXIT_FAILURE);
}
now.tm_isdst = -1; /* force mktime to get daylight savings */
then.tm_isdst = -1;
retval=difftime(mktime(&now),mktime(&then));
retval=retval/DAY;
free(wdate1);
free(wdate2);
return retval;
}
int main()
{
char now[32]={0x0};
char then[32]={0x0};
strcpy(then,"14th June 1983");
strcpy(now,"15th April 2006");
printf("Date difference in days: %s - %s = %d\n",
now,then,date_diff(now,then) );
strcpy(now,"1st June 2005");
printf("Date difference in days: %s - %s = %d\n",
now,then,date_diff(now,then) );
strcpy(now,"2nd August 2014");
printf("Date difference in days: %s - %s = %d\n",
now,then,date_diff(now,then) );
strcpy(now,"1st July 1975");
printf("Date difference in days: %s - %s = %d\n",
now,then,date_diff(now,then) );
return 0;
}
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