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Narue · May 18th, 2006, 5:00 PM

After division, DX contains the remainder. In this case, DX holds the digit we just sliced off. Earlier I posted how the division works:

(Toggle Plain Text)

123 / 10
AX = 12
DX = 3

12 / 10
AX = 1
DX = 2

1 / 10
AX = 0
DX = 1

The only problem is that these values are bare. 3 is 3, 2 is 2, and 1 is 1. You want the ASCII representation of those numbers, where 3 is 51, 2 is 50, and 1 is 49. So to force that representation, you take the bare number and add '0', which has a value of 48.

May 18th, 2006, 5:00 PM	#21
Narue Professional Programmer Join Date: Sep 2005 Posts: 419 Rep Power: 4	After division, DX contains the remainder. In this case, DX holds the digit we just sliced off. Earlier I posted how the division works: (Toggle Plain Text) 123 / 10 AX = 12 DX = 3 12 / 10 AX = 1 DX = 2 1 / 10 AX = 0 DX = 1 123 / 10 AX = 12 DX = 3 12 / 10 AX = 1 DX = 2 1 / 10 AX = 0 DX = 1 The only problem is that these values are bare. 3 is 3, 2 is 2, and 1 is 1. You want the ASCII representation of those numbers, where 3 is 51, 2 is 50, and 1 is 49. So to force that representation, you take the bare number and add '0', which has a value of 48. __________________ Even if the voices aren't real, they have some pretty good ideas.