Programming Forums > Application Development > C++

TecBrain · Oct 18th, 2004, 5:53 AM

Write a program to test the user on a multiplication table, asking them to enter the multiplication table he/she wants and then asking them to enter the answer to each of the 12 multiplications and printing the string �Correct� or �Incorrect� as appropriate.

I was able to solve the proram, but I want to add one more thing, I need to have the option for the user to exit any time he/she wants.

I tried adding the else if (number == 100 ) return (0);

But it seems to ignore it.

Can anyone help?

(Toggle Plain Text)

#include <iostream>
#include <stdlib.h>

using namespace std;

int main()
{
 *
 *
 *
 *int number, result;
 *int i;
 *
 *cout << "Please Enter a number:" << endl;
 *cin >> number;
 *
 *for ( i=1;i<=12;i++)
 {
 * *
 * *cout << number << " * " << i << " = ";
 * *cin >> result;
 * *
 * *if ( result == i * number)
 * *cout << "Correct Answer " <<endl;
 * *
 * *else
 * *cout << "Incorrect Answer, Please Try Again" << endl;
 * *
 
} * *
 *
 *
 *system("PAUSE");	
 *return 0;
}

Benoit · Oct 18th, 2004, 6:49 AM

You post a lot of homework assignments <_< I'm not sure about C++, but in C you use exit(0);

TecBrain · Oct 18th, 2004, 8:09 AM

Quote:

Originally posted by Benoit@Oct 18 2004, 10:49 AM
You post a lot of homework assignments <_< I'm not sure about C++, but in C you use exit(0);

Do You mind?? <_<

The assignment is solved, I want to add this is an extra work.

TecBrain · Oct 18th, 2004, 9:08 AM

Ok guys I managed to do something, maybe not professional but it does what I want for now.

Thanks.

(Toggle Plain Text)

#include <iostream>
#include <stdlib.h>

using namespace std;

int main()
{
 
 
 
 int number, result;
 int i;
 
 cout << "Please Enter a number:" << endl;
 cin >> number;
 
 for ( i=1;i<=12;i++)
{
  if (number == -1 ) return(0);
  
  cout << number << " * " << i << " = ";
  cin >> result;
  if (result == -1 ) return(0);
     
  if ( result == i * number)
  cout << "Correct Answer " <<endl;
  
  else
  cout << "Incorrect Answer, Please Try Again" << endl;
  

}  
 
 
 system("PAUSE"); 
 return 0;
}

Pizentios · Oct 18th, 2004, 10:23 AM

Why not use a while loop. Have a menu that gets looped unless the number that the user enters is like zero or somthing like that. That why your program has room for other stuff later, with little work. Then inside the while loop have a switch. The user input gets fed into the switch and they get to go the different parts of the program. So somthing like this:

(Toggle Plain Text)

#include <iostream.h>    
#include <conio.h>  

int main()
{

int input;
         While (x<>4)
         {
                cout<<"1 Math Test";
                cout<<"2 Play a Game";
                cout<<"3 Other Stuff";
                cout<<"4 Exit";
                cout<<"What do you want to do?";
                cin>>x;

                switch (x)
                {
                      case 1: math_test();
                                 //Insert your code for math test here.
                                 break;
                      case 2: play_game();
                                  //Insert game code here.
                                  break;
                      case 3: other_stuff();
                                  //Yeah i think you get the idea.
                                  break;
                      case 4: 
                                  return 0;
                                  break;
                      default:
                                 cout<<"Bad Input, Please Try Again....";
                 }
        }
return 0;
}

Anyways, i havn't tested that code, it was more of a thing to give you an idea. Cheers.

TecBrain · Oct 18th, 2004, 2:42 PM

Thanks Pizentios for sharing, I'll make sure that I will test it.

Cheers.

Pizentios · Oct 18th, 2004, 5:32 PM

No Prob. With your current code, you really don't need it since your program does only one thing. I guess you could add some other math testing funtions. like adding and such.

Also i can see somthing that could be changed in my code. i edited the post and changed it, just amkes it a little cleaner.

Ooble · Oct 19th, 2004, 3:04 PM

Also, with Pizentios's code, you might wanna change (x<>4) to (x!=4) - this is C++ here.

Pizentios · Oct 19th, 2004, 4:17 PM

Sorry, i am used to vb and PHP. Heh, i don't get to use my ~outdated~ knowledge of c++ very offten. It's sad really. Kinda like a Dog that a kid forgets about because they got a xbox for christmas.

Oct 18th, 2004, 5:53 AM	#1
TecBrain Hobbyist Programmer Join Date: Sep 2004 Location: Cyprus Posts: 147 Rep Power: 5	Write a program to test the user on a multiplication table, asking them to enter the multiplication table he/she wants and then asking them to enter the answer to each of the 12 multiplications and printing the string �Correct� or �Incorrect� as appropriate. I was able to solve the proram, but I want to add one more thing, I need to have the option for the user to exit any time he/she wants. I tried adding the else if (number == 100 ) return (0); But it seems to ignore it. Can anyone help? (Toggle Plain Text) #include <iostream> #include <stdlib.h> using namespace std; int main() { * * * int number, result; int i; * cout << "Please Enter a number:" << endl; cin >> number; * for ( i=1;i<=12;i++) { * * cout << number << " " << i << " = "; * cin >> result; * * if ( result == i number) * cout << "Correct Answer " <<endl; * * else cout << "Incorrect Answer, Please Try Again" << endl; * } * * * * system("PAUSE"); return 0; } #include <iostream> #include <stdlib.h> using namespace std; int main() { * * * int number, result; int i; * cout << "Please Enter a number:" << endl; cin >> number; * for ( i=1;i<=12;i++) { * * cout << number << " " << i << " = "; * cin >> result; * * if ( result == i number) * cout << "Correct Answer " <<endl; * * else cout << "Incorrect Answer, Please Try Again" << endl; * } * * * * system("PAUSE"); return 0; } __________________ Personal Portfolio TecBrain Support Forum Linux VS Windows ... Dont Even Think of it .. Distribution: Slackware if (OS==Linux) return success There are 10 kinds of people, those who can read binary numbers and those who can't.

Oct 18th, 2004, 6:49 AM	#2
Benoit Expert Programmer Join Date: Sep 2004 Location: Ontario, Canada Posts: 579 Rep Power: 5	You post a lot of homework assignments <_< I'm not sure about C++, but in C you use exit(0); __________________ Johnny was a chemist's son but Johnny is no more, for what Johnny thought was H2O was H2SO4

Oct 18th, 2004, 9:08 AM	#4
TecBrain Hobbyist Programmer Join Date: Sep 2004 Location: Cyprus Posts: 147 Rep Power: 5	Ok guys I managed to do something, maybe not professional but it does what I want for now. Thanks. (Toggle Plain Text) #include <iostream> #include <stdlib.h> using namespace std; int main() { int number, result; int i; cout << "Please Enter a number:" << endl; cin >> number; for ( i=1;i<=12;i++) { if (number == -1 ) return(0); cout << number << " * " << i << " = "; cin >> result; if (result == -1 ) return(0); if ( result == i * number) cout << "Correct Answer " <<endl; else cout << "Incorrect Answer, Please Try Again" << endl; } system("PAUSE"); return 0; } #include <iostream> #include <stdlib.h> using namespace std; int main() { int number, result; int i; cout << "Please Enter a number:" << endl; cin >> number; for ( i=1;i<=12;i++) { if (number == -1 ) return(0); cout << number << " * " << i << " = "; cin >> result; if (result == -1 ) return(0); if ( result == i * number) cout << "Correct Answer " <<endl; else cout << "Incorrect Answer, Please Try Again" << endl; } system("PAUSE"); return 0; } __________________ Personal Portfolio TecBrain Support Forum Linux VS Windows ... Dont Even Think of it .. Distribution: Slackware if (OS==Linux) return success There are 10 kinds of people, those who can read binary numbers and those who can't.

Oct 18th, 2004, 10:23 AM	#5
Pizentios Programming Guru Join Date: May 2004 Location: Brandon, Manitoba, Canada Posts: 2,023 Rep Power: 7	Why not use a while loop. Have a menu that gets looped unless the number that the user enters is like zero or somthing like that. That why your program has room for other stuff later, with little work. Then inside the while loop have a switch. The user input gets fed into the switch and they get to go the different parts of the program. So somthing like this: (Toggle Plain Text) #include <iostream.h> #include <conio.h> int main() { int input; While (x<>4) { cout<<"1 Math Test"; cout<<"2 Play a Game"; cout<<"3 Other Stuff"; cout<<"4 Exit"; cout<<"What do you want to do?"; cin>>x; switch (x) { case 1: math_test(); //Insert your code for math test here. break; case 2: play_game(); //Insert game code here. break; case 3: other_stuff(); //Yeah i think you get the idea. break; case 4: return 0; break; default: cout<<"Bad Input, Please Try Again...."; } } return 0; } #include <iostream.h> #include <conio.h> int main() { int input; While (x<>4) { cout<<"1 Math Test"; cout<<"2 Play a Game"; cout<<"3 Other Stuff"; cout<<"4 Exit"; cout<<"What do you want to do?"; cin>>x; switch (x) { case 1: math_test(); //Insert your code for math test here. break; case 2: play_game(); //Insert game code here. break; case 3: other_stuff(); //Yeah i think you get the idea. break; case 4: return 0; break; default: cout<<"Bad Input, Please Try Again...."; } } return 0; } Anyways, i havn't tested that code, it was more of a thing to give you an idea. Cheers. __________________ Profanity is the one language that all programmers understand. Check out my Blog <---updated Nov 30 2007!

Oct 18th, 2004, 2:42 PM	#6
TecBrain Hobbyist Programmer Join Date: Sep 2004 Location: Cyprus Posts: 147 Rep Power: 5	Thanks Pizentios for sharing, I'll make sure that I will test it. Cheers. __________________ Personal Portfolio TecBrain Support Forum Linux VS Windows ... Dont Even Think of it .. Distribution: Slackware if (OS==Linux) return success There are 10 kinds of people, those who can read binary numbers and those who can't.

Oct 18th, 2004, 5:32 PM	#7
Pizentios Programming Guru Join Date: May 2004 Location: Brandon, Manitoba, Canada Posts: 2,023 Rep Power: 7	No Prob. With your current code, you really don't need it since your program does only one thing. I guess you could add some other math testing funtions. like adding and such. Also i can see somthing that could be changed in my code. i edited the post and changed it, just amkes it a little cleaner. __________________ Profanity is the one language that all programmers understand. Check out my Blog <---updated Nov 30 2007!

Oct 19th, 2004, 3:04 PM	#8
Ooble I eat cake for breakfast. Join Date: Jul 2004 Location: In my box. Posts: 4,434 Rep Power: 9	Also, with Pizentios's code, you might wanna change (x<>4) to (x!=4) - this is C++ here. __________________ Me :: You :: Them

Oct 19th, 2004, 4:17 PM	#9
Pizentios Programming Guru Join Date: May 2004 Location: Brandon, Manitoba, Canada Posts: 2,023 Rep Power: 7	Sorry, i am used to vb and PHP. Heh, i don't get to use my ~outdated~ knowledge of c++ very offten. It's sad really. Kinda like a Dog that a kid forgets about because they got a xbox for christmas. __________________ Profanity is the one language that all programmers understand. Check out my Blog <---updated Nov 30 2007!

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Programming Forums > Application Development > C++

Program To Test The User......