Programming Forums - View Single Post - Reading source from a browser or intercepting the HTML stream over HTTP

Arevos · Feb 18th, 2006, 10:26 AM

Since this is the Java forum, I'll hazard a guess and say he wants to program it in Java

public static void main(String[] args) 
	throws IOException, MalformedURLException
{
	URL url = new URL("http://www.monkeyengines.co.uk");
	
	BufferedReader reader = new BufferedReader(
			new InputStreamReader(url.openStream())
	);
	while (true)
	{
		String line = reader.readLine();
		
		if (line == null) {
			break;
		}
		System.out.println(line);
	}
}

That's some simple code to get the source from a URL. What I guess you want is some sort of HTTP proxy...

Have you thought of using a prewritten HTTP proxy? Some of them are pretty flexible.

Here's a page that lists some java-based HTTP proxies.

Feb 18th, 2006, 10:26 AM	#3
Arevos Programming Guru Join Date: Aug 2005 Location: England Posts: 1,499 Rep Power: 5	Since this is the Java forum, I'll hazard a guess and say he wants to program it in Java (Toggle Plain Text) public static void main(String[] args) throws IOException, MalformedURLException { URL url = new URL("http://www.monkeyengines.co.uk"); BufferedReader reader = new BufferedReader( new InputStreamReader(url.openStream()) ); while (true) { String line = reader.readLine(); if (line == null) { break; } System.out.println(line); } } public static void main(String[] args) throws IOException, MalformedURLException { URL url = new URL("http://www.monkeyengines.co.uk"); BufferedReader reader = new BufferedReader( new InputStreamReader(url.openStream()) ); while (true) { String line = reader.readLine(); if (line == null) { break; } System.out.println(line); } } That's some simple code to get the source from a URL. What I guess you want is some sort of HTTP proxy... Have you thought of using a prewritten HTTP proxy? Some of them are pretty flexible. Here's a page that lists some java-based HTTP proxies.