Programming Forums > Application Development > Java

dchankhour · Feb 11th, 2006, 6:27 PM

i'm trying to pase a string into three integers that are seperated by the integers. then i'm taking the three integers and passing them into a ssn constructor that would create a ssn object. but my problem is how could i parse the string that in this form ###-##-####.
string ssn;
i used int s = Integer.parseInt(ss), but how would i take care for the dashes.

Mjordan2nd · Feb 11th, 2006, 7:39 PM

I haven't run this through a compiler, but this should do the trick:

(Toggle Plain Text)

String [] ssn = ss.split("-");
int [] nums = new int[3];

for(int i = 0; i<3; i++)
{
	 nums[i] = Integer.parseInt(ssn[i]);
}

dchankhour · Feb 12th, 2006, 12:30 AM

but how could i get three integers so i could pass them through my constructor

jaeusm · Feb 12th, 2006, 12:41 AM

Using the code above, you could modify your constructor to take an int array, or you could pass the three ints like this:

(Toggle Plain Text)

Ssn s = new Ssn(nums[0], nums[1], nums[2]);

I think this is a cumbersome way to pass the numbers, though.

xavier · Feb 12th, 2006, 12:42 AM

damn .. a few seccond too late with my response :p

dchankhour · Feb 12th, 2006, 1:19 AM

i tried that but it did not work, and that is because, the method is suppose to pass a string, not an array of string.

(Toggle Plain Text)

String [] ssn = ss.split("-");
int [] nums = new int[3];

for(int i = 0; i<3; i++)
{
	 nums[i] = Integer.parseInt(ssn[i]);
}

[/quote]
i have tried this, but still did not work.
num = Integer.parsInt(ssn);
num2= integer.parsInt(ssn);
but could i pass parseInt another paramter, telling it where to stop.

xavier · Feb 12th, 2006, 1:24 AM

Quote:

num = Integer.parsInt(ssn);

You have to do it like : num = Integer.parseInt(ssn[0]);
then ssn[1] and ssn[2].
you can't parse the entire array , you have to do it element by element.

dchankhour · Feb 12th, 2006, 1:39 AM

is there a way i could do it with out using arrays, and just using parseInt

Arevos · Feb 12th, 2006, 4:18 AM

Quote:

Originally Posted by dchankhour

is there a way i could do it with out using arrays, and just using parseInt

Why? What would be the point? If you tried to do it with three variables, the code would wind up being a lot more complicated (as you couldn't use split() or for loops). I suppose you could use a List instead, but there wouldn't be any point.

If you wish, you could take the array variables and convert them into named variables:

(Toggle Plain Text)

first = num[1];
second = num[2];
third = num[3];

But the point of doing this eludes me.

Feb 11th, 2006, 6:27 PM	#1
dchankhour Newbie Join Date: Jan 2006 Location: Poway, CA Posts: 13 Rep Power: 0	parsing a string i'm trying to pase a string into three integers that are seperated by the integers. then i'm taking the three integers and passing them into a ssn constructor that would create a ssn object. but my problem is how could i parse the string that in this form ###-##-####. string ssn; i used int s = Integer.parseInt(ss), but how would i take care for the dashes.

Feb 11th, 2006, 7:39 PM	#2
Mjordan2nd The Supreme Ruler Join Date: May 2004 Location: Houston Posts: 1,476 Rep Power: 6	I haven't run this through a compiler, but this should do the trick: (Toggle Plain Text) String [] ssn = ss.split("-"); int [] nums = new int[3]; for(int i = 0; i<3; i++) { nums[i] = Integer.parseInt(ssn[i]); } String [] ssn = ss.split("-"); int [] nums = new int[3]; for(int i = 0; i<3; i++) { nums[i] = Integer.parseInt(ssn[i]); } __________________ "Every gun that is made, every warship launched, every rocket signifies, in the final sense, a theft from those who hunger and are not fed, from those who are cold and are not clothed. The world in arms is not spending money alone. It is spending the sweat of its laborers, the genius of its scientists, the hopes of its children." - Dwight D. Eisenhower

Feb 12th, 2006, 12:41 AM	#4
jaeusm Programmer Join Date: Feb 2006 Location: Columbus, OH Posts: 84 Rep Power: 3	Using the code above, you could modify your constructor to take an int array, or you could pass the three ints like this: (Toggle Plain Text) Ssn s = new Ssn(nums[0], nums[1], nums[2]); Ssn s = new Ssn(nums[0], nums[1], nums[2]); I think this is a cumbersome way to pass the numbers, though.

Feb 12th, 2006, 12:42 AM	#5
xavier Professional Programmer Join Date: Oct 2004 Location: .ro Posts: 383 Rep Power: 4	damn .. a few seccond too late with my response :p __________________ Don't take life too seriously, it's not permanent !

Feb 12th, 2006, 1:19 AM	#6
dchankhour Newbie Join Date: Jan 2006 Location: Poway, CA Posts: 13 Rep Power: 0	i tried that but it did not work, and that is because, the method is suppose to pass a string, not an array of string. (Toggle Plain Text) String [] ssn = ss.split("-"); int [] nums = new int[3]; for(int i = 0; i<3; i++) { nums[i] = Integer.parseInt(ssn[i]); } String [] ssn = ss.split("-"); int [] nums = new int[3]; for(int i = 0; i<3; i++) { nums[i] = Integer.parseInt(ssn[i]); } [/quote] i have tried this, but still did not work. num = Integer.parsInt(ssn); num2= integer.parsInt(ssn); but could i pass parseInt another paramter, telling it where to stop.

Feb 12th, 2006, 12:30 AM	#3
dchankhour Newbie Join Date: Jan 2006 Location: Poway, CA Posts: 13 Rep Power: 0	but how could i get three integers so i could pass them through my constructor

Feb 12th, 2006, 1:39 AM	#8
dchankhour Newbie Join Date: Jan 2006 Location: Poway, CA Posts: 13 Rep Power: 0	is there a way i could do it with out using arrays, and just using parseInt

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Programming Forums > Application Development > Java

parsing a string