Programming Forums - View Single Post - I can print 'today', but can I print 'yesterday'?

Sane · Jan 27th, 2006, 1:27 PM

You could do that easily by yourself...

o_O I'll throw something up, just a moment.

EDIT:

import time

def yday(time_zone):  #HOURS FROM GMT!!
    new  = time.gmtime(time.time()+(time_zone-24)*3600)
    mon  = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"]
    return "%s %s %s"%(new[2],mon[int(new[1])-1],new[0])

today = time.strftime("%d %B %Y")
yesterday = yday(-5)

print today, yesterday

Then just change -5 to how many hours you are from GMT.

Jan 27th, 2006, 1:27 PM	#6
Sane Programming Guru Join Date: Apr 2005 Location: Waterloo, Ontario Posts: 1,890 Rep Power: 5	You could do that easily by yourself... o_O I'll throw something up, just a moment. EDIT: (Toggle Plain Text) import time def yday(time_zone): #HOURS FROM GMT!! new = time.gmtime(time.time()+(time_zone-24)3600) mon = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"] return "%s %s %s"%(new[2],mon[int(new[1])-1],new[0]) today = time.strftime("%d %B %Y") yesterday = yday(-5) print today, yesterday import time def yday(time_zone): #HOURS FROM GMT!! new = time.gmtime(time.time()+(time_zone-24)3600) mon = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"] return "%s %s %s"%(new[2],mon[int(new[1])-1],new[0]) today = time.strftime("%d %B %Y") yesterday = yday(-5) print today, yesterday Then just change -5 to how many hours you are from GMT.