Programming Forums > Application Development > Java

theguy0000 · Dec 20th, 2005, 7:35 PM

is there a Java equivilent to the PHP explode() function?

also a method to abort the application?

sorry if the answer is obvious, I am just really experienced in PHP but a noob at Java. :o

titaniumdecoy · Dec 21st, 2005, 12:38 AM

exit(0); will abort the application.

The equivalent of the PHP explode(str) function in Java is str.split(regexp) which will return a String[] containing the separated pieces.

Here is an example:

(Toggle Plain Text)

String str = "one two three";
String[] result = str.split(" ");

At the end result will contain the array "one", "two", "three".

Because split() takes a regular expression as its argument some characters, like . | ? * + will cause problems. To prevent this you can escape them with a double backslash (\\).

For example, str.split(".") will cause problems if you don't know that in regular expression terms "." represents any single character--so str.split("a.b") would separate the string at any three characters beginning with a and ending with b. To prevent this behavior in order to simply split the string at each period, you would use str.split("\\.").

andro · Dec 21st, 2005, 3:01 AM

You could also use a StringTokenizer to get similar results.

theguy0000 · Dec 21st, 2005, 9:53 AM

perfect, exactly what I needed.

Thanks!

Dec 20th, 2005, 7:35 PM	#1
theguy0000 Programmer Join Date: Jul 2005 Posts: 73 Rep Power: 4	explode() and aborting is there a Java equivilent to the PHP explode() function? also a method to abort the application? sorry if the answer is obvious, I am just really experienced in PHP but a noob at Java. :o Last edited by theguy0000; Dec 20th, 2005 at 7:49 PM. Reason: typo

Dec 21st, 2005, 12:38 AM	#2
titaniumdecoy Expert Programmer Join Date: Nov 2005 Posts: 856 Rep Power: 3	exit(0); will abort the application. The equivalent of the PHP explode(str) function in Java is str.split(regexp) which will return a String[] containing the separated pieces. Here is an example: (Toggle Plain Text) String str = "one two three"; String[] result = str.split(" "); String str = "one two three"; String[] result = str.split(" "); At the end result will contain the array "one", "two", "three". Because split() takes a regular expression as its argument some characters, like . \| ? * + will cause problems. To prevent this you can escape them with a double backslash (\\). For example, str.split(".") will cause problems if you don't know that in regular expression terms "." represents any single character--so str.split("a.b") would separate the string at any three characters beginning with a and ending with b. To prevent this behavior in order to simply split the string at each period, you would use str.split("\\."). Last edited by titaniumdecoy; Dec 21st, 2005 at 12:48 AM.

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Dec 21st, 2005, 3:01 AM	#3
andro Professional Programmer Join Date: Oct 2005 Location: California Posts: 312 Rep Power: 3	You could also use a StringTokenizer to get similar results.

Dec 21st, 2005, 9:53 AM	#4
theguy0000 Programmer Join Date: Jul 2005 Posts: 73 Rep Power: 4	perfect, exactly what I needed. Thanks!

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Programming Forums > Application Development > Java

explode() and aborting