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Dec 10th, 2005, 4:40 PM
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#1 | ||
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Hobbyist Programmer
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trouble reading string into array
so i've got this string called code, of type std::string, which has this inside it
Quote:
int last_flushed = 0;
std::string statements[1000];
int array_pos = 0;
for (int i = 0; i <= code.size(); i++)
{
if (code[i] == '\n')
{
statements[array_pos] = string_copy(code, last_flushed, i - last_flushed);
cout << statements[array_pos];
array_pos++;
last_flushed = i;
}
}it just prints out this: Quote:
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Dec 10th, 2005, 4:47 PM
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#2 |
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Resident Grouch
 
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You are using a lot of things there which you neither show nor define nor explain. Crystal balls are nice, but we don't all have one. Would you care to think about your post, think about your problem, think about your audience, and elucidate?
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Abstraction doesn't make it impossible to write bad code; it makes it possible to write superior code. Contributor's Corner: Grumpy on C++ Exceptions DaWei on Pointers |
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Dec 10th, 2005, 4:50 PM
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#3 |
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I eat cake for breakfast.
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I have no idea what you're trying to do here. Can you post some more code?
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Dec 10th, 2005, 4:51 PM
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#4 |
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Expert Programmer
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I tried reading through that code and i hit dead ends that could be vital to explaining whats wrong.
For example code.size() in the for loop.
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Dec 10th, 2005, 5:08 PM
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#5 |
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Hobbyist Programmer
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I'm sorry, I forgot to post string_copy()'s definition:
string string_copy(string source, int startpos, int length)
{
string final;
final = "";
for (int i = startpos; i <= length; i++)
final += source[i];
return final;
}the idea with that function is to return a 'length' substring of 'source', starting at 'startpos'. the idea of all this was to take a string containing several lines, each seperated by a newline (\n) and put each line into a seperate element of the array statements. the variable last_flushed is so it puts a substring of 'code', between last_flushed (the end of the last string put into the array) and i (the position of the next \n) and not everything from the beginning to whatever newline it encounters. @coldDeath: size() is a member of std::string. code.size() returns the length of the string 'code'.
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Children in the dark cause accidents, and accidents in the dark cause children. http://www.ronincoders.org |
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Dec 10th, 2005, 5:10 PM
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#6 |
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Expert Programmer
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Ty, I couldn't see any variables called code, so i got a little confused.
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Dec 10th, 2005, 5:17 PM
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#7 |
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I eat cake for breakfast.
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Instead of string_copy, why not just do this?
std::string myNewString = myOldString.substr(offset, length);  |
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Dec 10th, 2005, 5:28 PM
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#8 |
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Hobbyist Programmer
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coldDeath: np
Ooble: thanks, i got it working. yay.
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