Programming Forums - View Single Post - Printing escape sequences using printf()?

bivhitscar · Nov 2nd, 2005, 8:48 PM

Quote:

Originally Posted by nindoja

printf("\\n");

Basically, escape the backslash, so the escape sequence isn't seen.

That only works when I know what character is coming.

This is the code I'm using:

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for (i = 1; i <= length; i++)
  {
    printf("%c = %3d, ", string[i - 1], string[i - 1]);

    if (i % 8 == 0)
      printf("\n");
  }

That basicaly says, read the current element of the array, print the character and print it's ascii code. The if statement is just for formatting purposes.

Ideally, I just want a simple if else that says if ch == isspace() print the escape sequence instead of the actual character, else print the character. Am I making any sense?