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Dietrich · Sep 23rd, 2005, 6:37 PM

Thanks Cerulean and hydroxide for the "replacement of lambda" suggestions.

Here is my code to time map() versus list comprehension:

(Toggle Plain Text)

# 85% of the time map() beats list comprehension by 5 - 10% on Windows XP  Python 2.4.1

import timeit

tt = timeit.Timer('map(str, [2, 3, 5, 1])')
te = (1000000 * tt.timeit(number=100000)/100000)
print "Function map(str, [2, 3, 5, 1]) uses %0.5f ms/pass" % te

tt = timeit.Timer('[str(x) for x in [2, 3, 5, 1]]')
te = (1000000 * tt.timeit(number=100000)/100000)
print "LC [str(x) for x in [2, 3, 5, 1]] uses %0.5f ms/pass" % te

Did the decorator syntax come from Java?

Sep 23rd, 2005, 6:37 PM	#19
Dietrich Professional Programmer Join Date: Feb 2005 Posts: 434 Rep Power: 4	Thanks Cerulean and hydroxide for the "replacement of lambda" suggestions. Here is my code to time map() versus list comprehension: (Toggle Plain Text) # 85% of the time map() beats list comprehension by 5 - 10% on Windows XP Python 2.4.1 import timeit tt = timeit.Timer('map(str, [2, 3, 5, 1])') te = (1000000 * tt.timeit(number=100000)/100000) print "Function map(str, [2, 3, 5, 1]) uses %0.5f ms/pass" % te tt = timeit.Timer('[str(x) for x in [2, 3, 5, 1]]') te = (1000000 * tt.timeit(number=100000)/100000) print "LC [str(x) for x in [2, 3, 5, 1]] uses %0.5f ms/pass" % te # 85% of the time map() beats list comprehension by 5 - 10% on Windows XP Python 2.4.1 import timeit tt = timeit.Timer('map(str, [2, 3, 5, 1])') te = (1000000 * tt.timeit(number=100000)/100000) print "Function map(str, [2, 3, 5, 1]) uses %0.5f ms/pass" % te tt = timeit.Timer('[str(x) for x in [2, 3, 5, 1]]') te = (1000000 * tt.timeit(number=100000)/100000) print "LC [str(x) for x in [2, 3, 5, 1]] uses %0.5f ms/pass" % te Did the decorator syntax come from Java? __________________ I looked it up on the Intergnats!