Programming Forums > Application Development > C

deathseeker25 · Jun 29th, 2005, 8:01 PM

Hello I'm a n00b ate programming and I think I need some help solving one exercise that I saw in a Google search.It says exactly:

Quote:

1. To write a program that reads 3 corresponding whole number to one hour in hours, minutes and seconds, and converts into seconds, and prints the result. Assuming the following 0 variable for the hours, minutes and seconds, the reading could be:

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int horas, minutos,segundos;
long int result_em_segundos;
.....
scanf("%d%d%d",&horas, &min, & seg);

Note: this was translated by Google....

Well this problem was solved almost successfully:

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/*Horas. minutos e segundos*/

#include <stdio.h>
#include <stdlib.h>

int main()
{
    int horas,min,seg;
    long int result_em_segundos;
    
    printf("\nDiga que horas, quantos minutos e quantos segundos s�o respectivamente: ");
    scanf("%d%d%d",&horas,&min,&seg);
    
    horas=60*60*horas;
    min=60*min;
    
    printf("O resultado em segundos e de %d ",horas+min+seg);
    
    
    system("PAUSE");

Some things are in portuguese btu I think the code is quite understandable...

Well, my big problem is the second exercise:

Quote:

2. write a program that makes the inverse operation in the previous exercice.

And I wrote this code:

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#include <stdio.h>
#include <stdlib.h>

int main()
{
    int horas,sec,min;
    
           
    printf(" Say how many seconds you intend to convert for hourly time....");
    scanf("%d",&sec);
    
    horas=sec/60/60;
    min=sec/60;
    
    printf("Sao %d horas %d minutos e %d segundos",horas,min,sec);
    
    system("PAUSE");
    
}

The problem is that after compiling and executing it appears the following one in relation the last printf, introducing as given 3600 seconds:

Quote:

It's 1 hour, 60 minutes and 3600 seconds

Well, this is quite bad, isn't it....help me please....

DaWei · Jun 29th, 2005, 8:47 PM

When you use part (or all) of the seconds to make the appropriate number of hours, you have to only use the remainder for the minutes, and the remainder of that operation for the seconds. You may find the modulus operator (%) useful for that.

deathseeker25 · Jun 30th, 2005, 5:10 AM

Quote:

Originally Posted by DaWei

When you use part (or all) of the seconds to make the appropriate number of hours, you have to only use the remainder for the minutes, and the remainder of that operation for the seconds. You may find the modulus operator (%) useful for that.

Thanks pal I used this code:

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horas = sec/3600;
min = (sec%3600)/60;
sec = sec%60;

And it functioned prety well....

Thanks for helping

Jun 29th, 2005, 8:47 PM	#2
DaWei Resident Grouch Join Date: Jun 2005 Posts: 6,453 Rep Power: 10	When you use part (or all) of the seconds to make the appropriate number of hours, you have to only use the remainder for the minutes, and the remainder of that operation for the seconds. You may find the modulus operator (%) useful for that. __________________ Abstraction doesn't make it impossible to write bad code; it makes it possible to write superior code. Contributor's Corner: Grumpy on C++ Exceptions DaWei on Pointers

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Programming Forums > Application Development > C

Some exercises