Programming Forums > Application Development > C++

amin1982 · May 8th, 2005, 8:40 AM

i have the following problem:

i need to define two dimension array with unkown size,the array define after its size is computed>>>>example:
#include<iostream.h>

int main()
{

int m,n;

m=8;
n=9;

int a[m][n];

for(int i=0;i<m;i++)
{
for(int j=0;j<n;n++)
{
a[i][j]=255;
cout<<a[i][j];
}
cout<<endl;
}
return 0;
}

this is not a program ,its just for explanation of my problem>>>

Ooble · May 8th, 2005, 8:59 AM

If you want to declare an array of variable length, you need to use pointers:

(Toggle Plain Text)

int m, n;

m = 8;
n = 9;

int *a = new int [m][n];

I hope that's right...

LOI Kratong · May 8th, 2005, 10:54 AM

I read a tutorial on this ages ago, here is the sample source. sorry can't remember who wrote it (so can't legitamately attribute it to him) but it's not mine anyway...

(Toggle Plain Text)

#include <iostream.h>
#include <stdlib.h>

int main()
{
    char input [100];
    int i,n;
    long * l;
    cout << "How many numbers do you want to type in? ";
    cin.getline (input,100); i=atoi (input);
    l= new long[i];
    if (l == NULL) exit (1);
    for (n=0; n<i; n++)
    {
     cout << "Enter Number: ";
     cin.getline (input,100); l[n]=atol (input);
    }
    cout << "You have entered: ";
    for (n=0; n<i; n++)
        cout << l[n] << ", ";
    delete[] l;
      system("PAUSE");
      return 0;
}

hope it shows you what you need to know

May 8th, 2005, 8:40 AM	#1
amin1982 Newbie Join Date: Oct 2004 Posts: 15 Rep Power: 0	question(ARRAy) i have the following problem: i need to define two dimension array with unkown size,the array define after its size is computed>>>>example: #include<iostream.h> int main() { int m,n; m=8; n=9; int a[m][n]; for(int i=0;i<m;i++) { for(int j=0;j<n;n++) { a[i][j]=255; cout<<a[i][j]; } cout<<endl; } return 0; } this is not a program ,its just for explanation of my problem>>>

May 8th, 2005, 8:59 AM	#2
Ooble I eat cake for breakfast. Join Date: Jul 2004 Location: In my box. Posts: 4,434 Rep Power: 9	If you want to declare an array of variable length, you need to use pointers: (Toggle Plain Text) int m, n; m = 8; n = 9; int a = new int [m][n]; int m, n; m = 8; n = 9; int a = new int [m][n]; I hope that's right... __________________ Me :: You :: Them

May 8th, 2005, 10:54 AM	#3
LOI Kratong Professional Programmer Join Date: May 2005 Location: Woo - Boot Sector! Posts: 294 Rep Power: 4	I read a tutorial on this ages ago, here is the sample source. sorry can't remember who wrote it (so can't legitamately attribute it to him) but it's not mine anyway... (Toggle Plain Text) #include <iostream.h> #include <stdlib.h> int main() { char input [100]; int i,n; long * l; cout << "How many numbers do you want to type in? "; cin.getline (input,100); i=atoi (input); l= new long[i]; if (l == NULL) exit (1); for (n=0; n<i; n++) { cout << "Enter Number: "; cin.getline (input,100); l[n]=atol (input); } cout << "You have entered: "; for (n=0; n<i; n++) cout << l[n] << ", "; delete[] l; system("PAUSE"); return 0; } #include <iostream.h> #include <stdlib.h> int main() { char input [100]; int i,n; long * l; cout << "How many numbers do you want to type in? "; cin.getline (input,100); i=atoi (input); l= new long[i]; if (l == NULL) exit (1); for (n=0; n<i; n++) { cout << "Enter Number: "; cin.getline (input,100); l[n]=atol (input); } cout << "You have entered: "; for (n=0; n<i; n++) cout << l[n] << ", "; delete[] l; system("PAUSE"); return 0; } hope it shows you what you need to know __________________ www.heldtogether.co.uk

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Programming Forums > Application Development > C++

question(ARRAy)