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TecBrain · Apr 13th, 2005, 3:16 AM

I have tried that before and I ended up with the same results, The loop never stops .....

void strencypt(char str[])
{
	char star='*';
	char str2[10];
	int i;
	
	for(i=0;((i<10) && (str[i]!='\0'));i++)
	{
		if((str[i])== ' ') str2[i]= star;
	
		else str2[i]=int(str[i]+1);

	}
	
	std::cout << "String A Is Encrypted Now With This Format: " << "\n";
	
	for(i=0;((i<10) && (str[i]!='\0'));i++)
	{
		std::cout << str2[i];
	}
	std::cout << "\n";
	
}

Apr 13th, 2005, 3:16 AM	#3
TecBrain Hobbyist Programmer Join Date: Sep 2004 Location: Cyprus Posts: 147 Rep Power: 4	I have tried that before and I ended up with the same results, The loop never stops ..... (Toggle Plain Text) void strencypt(char str[]) { char star=''; char str2[10]; int i; for(i=0;((i<10) && (str[i]!='\0'));i++) { if((str[i])== ' ') str2[i]= star; else str2[i]=int(str[i]+1); } std::cout << "String A Is Encrypted Now With This Format: " << "\n"; for(i=0;((i<10) && (str[i]!='\0'));i++) { std::cout << str2[i]; } std::cout << "\n"; } void strencypt(char str[]) { char star=''; char str2[10]; int i; for(i=0;((i<10) && (str[i]!='\0'));i++) { if((str[i])== ' ') str2[i]= star; else str2[i]=int(str[i]+1); } std::cout << "String A Is Encrypted Now With This Format: " << "\n"; for(i=0;((i<10) && (str[i]!='\0'));i++) { std::cout << str2[i]; } std::cout << "\n"; } __________________ Personal Portfolio TecBrain Support Forum Linux VS Windows ... Dont Even Think of it .. Distribution: Slackware if (OS==Linux) return success There are 10 kinds of people, those who can read binary numbers and those who can't.