Programming Forums - View Single Post

TecBrain · Apr 13th, 2005, 12:12 AM

If the user input a space the output should be replaced with a ' * ', Not seems to except, I have added the value 32 which represent the space value on the ASCII table,However; if I replace the value of 32 to 33 which represent ' ! ' char, it would work, Any idea!!

(Toggle Plain Text)

void strencypt(char str[])
{
	char star='*';
	char str2[10];
	int i;
	
	for(i=0;((i<10) && (str[i]!='\0'));i++)
	{
			if ((int)(str[i])==32)
			str2[i]= star;
	
			else str2[i]=(int)(str[i]+1);

	}
	
	std::cout << "String A Is Encrypted Now With This Format: " << "\n";
	
	for(i=0;((i<10) && (str[i]!='\0'));i++)
	{
		std::cout << str2[i];
	}
	std::cout << "\n";
	
}

Apr 13th, 2005, 12:12 AM	#1
TecBrain Hobbyist Programmer Join Date: Sep 2004 Location: Cyprus Posts: 147 Rep Power: 4	*replace space with ' '** If the user input a space the output should be replaced with a ' * ', Not seems to except, I have added the value 32 which represent the space value on the ASCII table,However; if I replace the value of 32 to 33 which represent ' ! ' char, it would work, Any idea!! (Toggle Plain Text) void strencypt(char str[]) { char star=''; char str2[10]; int i; for(i=0;((i<10) && (str[i]!='\0'));i++) { if ((int)(str[i])==32) str2[i]= star; else str2[i]=(int)(str[i]+1); } std::cout << "String A Is Encrypted Now With This Format: " << "\n"; for(i=0;((i<10) && (str[i]!='\0'));i++) { std::cout << str2[i]; } std::cout << "\n"; } void strencypt(char str[]) { char star=''; char str2[10]; int i; for(i=0;((i<10) && (str[i]!='\0'));i++) { if ((int)(str[i])==32) str2[i]= star; else str2[i]=(int)(str[i]+1); } std::cout << "String A Is Encrypted Now With This Format: " << "\n"; for(i=0;((i<10) && (str[i]!='\0'));i++) { std::cout << str2[i]; } std::cout << "\n"; } __________________ Personal Portfolio TecBrain Support Forum Linux VS Windows ... Dont Even Think of it .. Distribution: Slackware if (OS==Linux) return success There are 10 kinds of people, those who can read binary numbers and those who can't.