Programming Forums - View Single Post - How can i round a number to the nearest 300?

mesbaba8 · Jun 14th, 2004, 1:10 PM

i will only give the algorithm, you try the code. There are two steps:

i) Last two digits should be 00 , so if it is >50 round to next hundred, and vica versa.

ii) sum all the digits of the new number, and continue this till you get one digit number (its easy with a recursive function). If the last digit, is divisible by 3, then it is ok, if not increase or decrease the hundred digit by one.

for example, take your number : 2527254

i) since last 2 digits > 50, round to 2527300

ii) sum of the digits = 19
sum of the digits = 10
sum of the digits = 1

then you will decrease the hundred digit by one.

so the final number is 2527200

not too diffucult to code

good luck

Jun 14th, 2004, 1:10 PM	#4
mesbaba8 Newbie Join Date: Apr 2004 Posts: 1 Rep Power: 0	i will only give the algorithm, you try the code. There are two steps: i) Last two digits should be 00 , so if it is >50 round to next hundred, and vica versa. ii) sum all the digits of the new number, and continue this till you get one digit number (its easy with a recursive function). If the last digit, is divisible by 3, then it is ok, if not increase or decrease the hundred digit by one. for example, take your number : 2527254 i) since last 2 digits > 50, round to 2527300 ii) sum of the digits = 19 sum of the digits = 10 sum of the digits = 1 then you will decrease the hundred digit by one. so the final number is 2527200 not too diffucult to code good luck