colt

I am doing a project with consists in printing on the screen a arithmetic table in this format using two variable values:

1 + 0 = 1/// 1 * 0 = 0/// 1 - 0 = 0
1 + 1 = 2/// 1 * 1 = 1/// 1 - 1 = 1
1 + 2 = 3/// 1 * 2 = 2/// 1 - 2 = 0
1+ 3 = 4/// 1 * 3 = 3/// 1 - 3 = -2
1 + 4 = 5/// 1 * 4 = 4/// 1 - 4 = -3
......
1+ M=..../// 1 * M= ..../// 1 - M=....


N+ 0 = N/// N* 0 =0 /// N- 0=N
N+ 1 = .../// N* 1 = N /// N- 1=
N+ 2 = .../// N* 2 = .../// N- 2

N + M=....... M * N= M-N=......

I already did a part of it with this code:

#include<stdio.h>
main()
{
int num, mult, resp;

for (num=1, mult=0; mult<5; mult++ )
{
resp=num+mult;
printf ("%d+%d=%d \n", num,mult,resp);
}
for (num=1, mult=0; mult<5; mult++)
{
resp=num*mult;
printf ("%d*%d=%d \n", num,mult,resp);
}
for (num=1, mult=0; mult<5; mult++)
{
resp=num-mult;
printf ("%d-%d=%d \n", num,mult,resp);
}
scanf ("%d", &num);

return 0;
}

...this prints the arithmetgic table with one perfectly, but I need to put those my three for loops inside of another for loop to increase the value of my num variable until it reaches the limit that I will choose (I am thinking about 5), instead of printing the table with only 1*0, 1*1.....

I already tried this without sucess, I think that I am confused in relation to the functioning of the for loop.

So how I can put this all inside of another for loop to increase the value of my num variable?. Thanks for the help

Dizzutch

i think this should work and if not it should get you int he right direction.. Good luck
Dizz

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colt

That's basically the idea that I had, but it's written in a way that works. Besides that, now the code is well more clean. Thanks