bliznags

i am very new to programming and have been faced with a problem i can not figure out. i first wrote a program to print out:

****
****
****
****

and I was successful with it. the code is as follwed:

#include <stdio.h>
int main(){

int i;

for(i=0; i<16; i++)
{
if(i % 4 == 0)
printf("\n");
printf("*");
}
printf("\n");
}

but now i have to use this same program and write a void function that prints out a single asterik and use it inside the loop instead of printf.

any help will be appreciated.

brkstf

this is pretty simple

you just declare your prototype
void makeAsterisk();

then, you have to write the actual function
void makeAsterisk()
{
code goes here
}

and then everytime you want to print the asterisk, you call the function.

maybe you're overthinking it. it's more about learning the syntax than doing the work.

tempest

#include <stdio.h>

void printAst();
void printNL();
void printPattern(int count, int brk);

int main(int argc, char *argv[]) {
    if(argc != 3) {
        printf("Usage %s count break\n", argv[0]);
        exit(0);
    }

    printPattern(atoi(argv[1]), atoi(argv[2]));

    return 0;
}

void printAst() {
    printf("*");
}

void printNL() {
    printf("\n");
}

void printPattern(int count, int brk) {
    int i;

    for(i=1;i<=count;i++) {
        printAst();
        if((i%brk) == 0) printNL();
    }
}

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bliznags

hey guys thanks for the help. Tempest, your code is way too advanced for me to follow, I have not learned most of the things included in it but thank you.

brkstf, i am somewhat following what youre saying, but i'm brand new to the world of coding. with what you said this is what i came up with (please dont laguh)

#include <stdio.h>
void printAst();

int main(){

int i;

for(i=0; i<16; i++)
{
if(i % 4 == 0)
printf("\n");
return 0;

void printAst(){
printf("*");
}
}
printf("\n");
}


this does not work. i get the following errors.
"lab04.6.c", line 14: syntax error before or at: void
"lab04.6.c", line 16: warning: end-of-loop code not reached
"lab04.6.c", line 18: syntax error before or at: "\n"
"lab04.6.c", line 18: warning: old-style declaration or incorrect type for: printf
"lab04.6.c", line 18: warning: identifier redeclared: printf
current : function() returning int
previous: function(pointer to const char, ...) returning int : "/usr/include/iso/stdio_iso.h", line 179


my textbook is crap and tells me nothing about void functions. furthermore, my professor is extremely vague when describing concepts.

Ooble

The function goes outside the main function:

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Me :: You :: Them

bliznags

that was a nice explaination ooble. thanks a lot. works perfect

tempest

Sorry about that, it wasn't intentional. What happened was i created one that i was going to post, and decided to test it to make sure it worked. As i was doing that i added in command-line arguments in a different file (or so i thought) and overwrote the one i was going to cut and paste into the forum. Without looking i posted the wrong code, stupid of me.

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