Programming Forums > Web Development and Design > PHP

TerraNerd · Feb 26th, 2005, 9:51 AM

In my book on PHP, it allways starts a section of code, as if it were starting the page of code, with the fallowing:

<!DOCTYPE html PUBLIC
     "=//W3C//DTD XHTML 1.0 Strict//EN"
     "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">

and it never expains what that means, yet it's in each example of code.

im going to guess DOCTYPE is the type of the document, but yet with the ! operator, which is 'not,' right? So im guessing it's saying 'not an html public document.' However im lost after that.

Feb 26th, 2005, 9:51 AM	#1
TerraNerd Programmer Join Date: Jul 2004 Location: Vermont, USA Posts: 65 Rep Power: 5	!DOCTYPE - What does this mean? In my book on PHP, it allways starts a section of code, as if it were starting the page of code, with the fallowing: (Toggle Plain Text) <!DOCTYPE html PUBLIC "=//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <!DOCTYPE html PUBLIC "=//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> and it never expains what that means, yet it's in each example of code. im going to guess DOCTYPE is the type of the document, but yet with the ! operator, which is 'not,' right? So im guessing it's saying 'not an html public document.' However im lost after that. __________________ [See a gallery of my Graphic art Here.][Visit my website Here]

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Programming Forums > Web Development and Design > PHP

!DOCTYPE - What does this mean?